The second derivative and concavity: WACE Year 12 Mathematics Methods Unit 3
“Find and interpret the second derivative, determine concavity and points of inflection, and apply the second derivative test”
The second derivative measures concavity: is concave up, is concave down. A point of inflection is where changes sign. The second derivative test classifies a stationary point as a minimum if and a maximum if .
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What this dot point is asking
SCSA Unit 3 introduces the second derivative as the derivative of the derivative. This dot point asks you to compute it, read concavity from its sign, locate points of inflection, and use it to classify stationary points, all examinable in both sections of the WACE written examination.
What the second derivative measures
The first derivative is the rate of change of . The second derivative is the rate of change of , so it measures how the gradient is changing. In kinematics, if is displacement then is velocity and is acceleration.
- : the gradient is increasing, so the curve is concave up.
- : the gradient is decreasing, so the curve is concave down.
- A point of inflection occurs where changes sign (the concavity reverses).
A common requirement is that alone does not guarantee an inflection: the sign of must actually change there. Confirming the sign change, with a brief sign table or a sentence stating the signs on each side, is the part SCSA markers look for and the part most often omitted.
Points of inflection
To find points of inflection, solve , then confirm a sign change of on either side. The function illustrates the trap: is zero at but never negative, so the concavity does not reverse and there is no inflection.
Step 1: Differentiate twice to obtain
Differentiating twice gives the second derivative that will reveal where concavity may change:
Step 2: Solve to find the candidate
Setting locates where the concavity could reverse; this is a necessary condition, not a sufficient one:
Step 3: Confirm the sign change of on either side
For , (concave down); for , (concave up). Because the concavity reverses, is a genuine point of inflection.
Step 4: Find the -coordinate
Substituting into the original function gives the -value of the inflection point:
Final answer: Point of inflection at
The second derivative test
Once a stationary point is found from , the second derivative test classifies it quickly.
At a stationary point where :
- if , then is a local minimum;
- if , then is a local maximum;
- if , the test is inconclusive; use a sign table for .
Step 1: Find the stationary points from
Differentiating and setting the result to zero locates the candidates for classification:
Step 2: Compute and evaluate at each stationary point
The second derivative is straightforward to evaluate. Its sign at each stationary point determines the nature of that point without needing a sign table for :
- At : , so is a local minimum.
- At : , so is a local maximum.
Final answer: Local minimum at ; local maximum at .
Acceleration and the second derivative
In kinematics the second derivative has a direct physical meaning. If is displacement, then is velocity and is acceleration. Concave-up displacement () means the velocity is increasing, and concave-down displacement () means it is decreasing. A point of inflection of the displacement graph is exactly where the acceleration is zero and changing sign, which is the instant the motion switches between speeding up and slowing down. This connects the abstract idea of concavity to a quantity students can feel.
Reading concavity from a sketch
When you sketch a curve, concavity tells you how to draw it between the key points. A concave-up section curves like a valley with the gradient steadily increasing; a concave-down section curves like a hill with the gradient steadily decreasing. At a point of inflection the tangent crosses the curve as the bend reverses. Getting the concavity right is a marked feature of a curve sketch, separate from plotting the correct stationary points.
- Assuming means an inflection
- You must confirm changes sign. has but no inflection at .
- Using the test when
- The second derivative test is inconclusive then; fall back on the sign of either side.
- Reversing the concavity labels
- Concave up corresponds to (a valley shape), concave down to (a hill shape).
Exam-style questions
Questions in the style of SCSA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.
WACE 2022-style6 marksCalculator-free. Consider . (a) Find the stationary points and classify them using the second derivative test. (b) Find the coordinates of the point of inflection.Show worked answer →
A standard stationary-point and inflection question.
(a) , so stationary points at and . . At , , a local minimum, with . At , , a local maximum, with .
(b) at , where changes sign. , so the inflection is .
Markers reward both stationary points with the second-derivative test and the inflection with a sign-change justification.
WACE 2024-style4 marksCalculator-free. The displacement of a particle is metres. (a) Find the acceleration . (b) Find the time at which the acceleration is zero and describe the motion at that instant.Show worked answer →
A kinematics application of the second derivative.
(a) and .
(b) when , so s. At the acceleration is zero, so the velocity is momentarily neither increasing nor decreasing; this is the point of inflection of the displacement graph, where the particle's speed is changing least.
Markers reward the second derivative as acceleration, , and the interpretation as zero acceleration.