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WASpecialist MathematicsSyllabus dot point

How does a vector equation with a parameter trace out a curve, and how do we convert it to cartesian form?

Write vector and parametric equations of curves and convert between vector, parametric and cartesian forms

WACE Specialist Unit 3 vector and cartesian equations of curves: parametrising a path with a vector equation, reading off component equations, eliminating the parameter to get a cartesian relation, and recognising standard curves, with a worked example.

Generated by Claude Opus 4.76 min answer

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  1. What this dot point is asking
  2. From vector to parametric form
  3. Eliminating the parameter
  4. Recognising standard curves

What this dot point is asking

SCSA wants you to move fluently between the vector form of a curve, its parametric component equations, and its cartesian equation, and to recognise the standard curves these describe.

From vector to parametric form

A curve in the plane can be written as a position vector that depends on a parameter:

r(t)=x(t)i+y(t)j.\mathbf{r}(t) = x(t)\,\mathbf{i} + y(t)\,\mathbf{j}.

As tt ranges over an interval, the tip of r(t)\mathbf{r}(t) sweeps out the curve. The two component functions x=x(t)x = x(t) and y=y(t)y = y(t) are the parametric equations of the same curve.

Eliminating the parameter

The resulting relation between xx and yy, free of tt, is the cartesian equation. Always note any restriction the parameter places on the range of xx or yy, since the parametric curve may be only part of the full cartesian graph.

Recognising standard curves

Some parametrisations recur. A linear r(t)=a+tb\mathbf{r}(t) = \mathbf{a} + t\mathbf{b} traces a straight line. The pair x=acostx = a\cos t, y=asinty = a\sin t traces a circle of radius aa, since squaring and adding gives x2+y2=a2x^2 + y^2 = a^2. The pair x=acostx = a\cos t, y=bsinty = b\sin t traces an ellipse.