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WASpecialist MathematicsSyllabus dot point

How do we extend the real numbers to solve every polynomial equation?

Represent complex numbers in Cartesian and polar form, perform arithmetic, and apply de Moivre's theorem

WACE Specialist Unit 3 complex numbers: Cartesian and polar (modulus-argument) form, the Argand plane, arithmetic, conjugates, de Moivre's theorem and the nth roots of a complex number, with full worked examples.

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  1. What this dot point is asking
  2. Cartesian form and arithmetic
  3. The Argand plane, modulus and argument
  4. Polar form and de Moivre's theorem

What this dot point is asking

SCSA wants you to move fluently between Cartesian form z=x+iyz = x + iy and polar (modulus-argument) form, plot numbers on the Argand plane, carry out all four arithmetic operations, use the conjugate, and apply de Moivre's theorem to find powers and the nn roots of a complex number.

Cartesian form and arithmetic

Write z=x+iyz = x + iy where x=Re(z)x = \operatorname{Re}(z) and y=Im(z)y = \operatorname{Im}(z), and i2=1i^2 = -1. Addition and subtraction act component-wise. Multiplication uses the distributive law with i2=1i^2 = -1:

(a+ib)(c+id)=(acbd)+i(ad+bc).(a + ib)(c + id) = (ac - bd) + i(ad + bc).

The conjugate of z=x+iyz = x + iy is zˉ=xiy\bar z = x - iy. The product zzˉ=x2+y2=z2z\bar z = x^2 + y^2 = |z|^2 is real and non-negative, which is the key to division: multiply numerator and denominator by the conjugate of the denominator.

a+ibc+id=(a+ib)(cid)c2+d2.\frac{a + ib}{c + id} = \frac{(a + ib)(c - id)}{c^2 + d^2}.

The Argand plane, modulus and argument

Plot z=x+iyz = x + iy as the point (x,y)(x, y). The modulus z=x2+y2|z| = \sqrt{x^2 + y^2} is the distance from the origin. The argument argz\arg z is the angle measured anticlockwise from the positive real axis. The principal argument Argz\operatorname{Arg} z lies in (π,π](-\pi, \pi]. Always check the quadrant: a bare tan1(y/x)\tan^{-1}(y/x) can land in the wrong half-plane.

Polar form and de Moivre's theorem

In polar form z=rcisθz = r\,\text{cis}\,\theta where cisθ=cosθ+isinθ\text{cis}\,\theta = \cos\theta + i\sin\theta. Multiplication multiplies moduli and adds arguments; division divides moduli and subtracts arguments:

z1z2=r1r2cis(θ1+θ2),z1z2=r1r2cis(θ1θ2).z_1 z_2 = r_1 r_2\,\text{cis}(\theta_1 + \theta_2), \qquad \frac{z_1}{z_2} = \frac{r_1}{r_2}\,\text{cis}(\theta_1 - \theta_2).

For the nn distinct nnth roots of w=Rcisϕw = R\,\text{cis}\,\phi, solve zn=wz^n = w:

zk=R1/ncis ⁣(ϕ+2πkn),k=0,1,,n1.z_k = R^{1/n}\,\text{cis}\!\left(\frac{\phi + 2\pi k}{n}\right), \quad k = 0, 1, \dots, n - 1.

The roots all have modulus R1/nR^{1/n} and are spaced 2πn\tfrac{2\pi}{n} apart, so they sit on the vertices of a regular polygon.