Why does every nonzero complex number have exactly n distinct nth roots, evenly spaced on a circle?
Find the nth roots of a complex number and the nth roots of unity, and represent them on the Argand plane
WACE Specialist Unit 3 roots of complex numbers: solving z to the n equals w with the general root formula, the nth roots of unity, equal spacing on a circle of radius the nth root of the modulus, and their sum, with a worked example.
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What this dot point is asking
SCSA wants you to solve for all roots, identify the roots of unity, and plot them as a regular polygon on the Argand plane.
The general root formula
To solve , write and let . By de Moivre , so matching moduli gives and matching arguments gives for integer . Hence
Taking to gives distinct roots; further values of repeat them. All roots share the modulus , so they lie on a circle of that radius, spaced apart. This is why they form a regular -gon.
The nth roots of unity
Setting gives the th roots of unity:
They all lie on the unit circle, include , and are equally spaced. Writing , every root is a power .
Plotting strategy
Find one root (usually ), then rotate by repeatedly to get the rest. You never recompute the modulus.