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WASpecialist MathematicsSyllabus dot point

How does plotting a complex number reveal its size and direction through modulus and argument?

Represent complex numbers on the Argand plane and find modulus and argument, converting to polar form

WACE Specialist Unit 3 complex plane: plotting on the Argand diagram, the modulus as distance from the origin, the argument and principal argument in the interval negative pi to pi, quadrant checks, and conversion to polar form, with a worked example.

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  1. What this dot point is asking
  2. The Argand plane
  3. Modulus
  4. Argument
  5. Conversion to polar form

What this dot point is asking

SCSA wants you to plot complex numbers, compute modulus and argument correctly with attention to quadrant, and convert between Cartesian and polar form.

The Argand plane

The Argand plane represents z=x+iyz = x + iy as the point (x,y)(x, y), with the horizontal axis the real axis and the vertical axis the imaginary axis. Addition corresponds to vector addition and conjugation corresponds to reflection in the real axis. This geometric picture is what makes polar form and loci natural.

Modulus

The modulus is multiplicative: zw=zw|zw| = |z|\,|w| and zw=zw\left|\tfrac{z}{w}\right| = \tfrac{|z|}{|w|}. It also satisfies z2=zzˉ|z|^2 = z\bar z and the triangle inequality z+wz+w|z + w| \le |z| + |w|.

Argument

The argument of zz is the angle θ\theta, measured anticlockwise from the positive real axis, such that x=zcosθx = |z|\cos\theta and y=zsinθy = |z|\sin\theta. Because adding 2π2\pi returns the same point, the argument is only defined up to multiples of 2π2\pi. The principal argument Argz\operatorname{Arg} z is the unique value in (π,π](-\pi, \pi].

To find it, compute the reference angle α=tan1 ⁣yx\alpha = \tan^{-1}\!\left|\tfrac{y}{x}\right| and then place it in the correct quadrant by inspecting the signs of xx and yy. A sketch settles the sign every time.

Conversion to polar form

Once you have r=zr = |z| and θ=argz\theta = \arg z, the polar (modulus-argument) form is

z=r(cosθ+isinθ)=rcisθ.z = r(\cos\theta + i\sin\theta) = r\,\text{cis}\,\theta.

Going the other way, x=rcosθx = r\cos\theta and y=rsinθy = r\sin\theta recovers Cartesian form.