Skip to main content
ExamExplained
WA · Mathematics Applications
Mathematics Applications study scene
§-Syllabus dot point
WAMathematics ApplicationsSyllabus dot point

How does money grow or shrink over time under interest and repayments?

Model and solve problems involving compound interest, depreciation, annuities, loans and investments using recursion and the financial solver.

How to set up recurrence relations for compound interest, depreciation, loans and annuities, and how to use the finance solver to find payments, balances and the number of periods.

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. One recurrence for every model
  3. Converting the rate
  4. Using the finance solver
  5. Which tool for which question
  6. Reading the wording for sign and rate

What this dot point is asking

You must recognise compound interest, depreciation, loans and annuities as one family of recurrence relations, set up the correct sign on the payment, and solve with recursion or the finance solver.

One recurrence for every model

The whole topic reduces to choosing RR and dd in the same recurrence.

The sign of dd is the decision that separates a loan from a savings plan. A repayment is subtracted, a deposit is added.

Converting the rate

Interest is quoted as a nominal annual rate but applied per compounding period. Divide by the number of periods per year: monthly uses rate12\dfrac{\text{rate}}{12}, quarterly rate4\dfrac{\text{rate}}{4}. Then count nn in those same periods.

Using the finance solver

The SCSA calculator-assumed section expects the built-in finance (TVM) solver for harder questions. The standard fields are present value PVPV, future value FVFV, payment PMTPMT, number of periods NN and interest rate per year I%I\% with a compounding setting. Sign convention: money you receive is positive, money you pay is negative. To find an unknown payment or the number of periods, enter the four known values and solve for the fifth.

For the loan above, set PV=10000PV = 10000, I%=12I\% = 12, compounding monthly, PMT=−900PMT = -900 and solve for NN to find the number of payments, then read the final small payment from the last balance.

Which tool for which question

The topic rewards picking the efficient method. For a single balance a few periods ahead, iterate the recurrence by hand. For a balance many periods ahead with no payments, use the explicit form An=A0RnA_n = A_0 R^n. For an unknown payment, number of periods, or present or future value in a loan or annuity, use the finance solver. For "when does the balance first reach a target", iterate (or solve for NN) and round to the next whole period. Recognising which of these a question wants saves time and avoids setting up the wrong calculation.

Reading the wording for sign and rate

Two reading skills decide every finance answer. First, the sign of the regular payment: words like "repay", "withdraw" and "pay off" mean a subtraction (negative dd); words like "deposit", "contribute" and "add" mean an addition (positive dd). Second, the compounding period: "compounding monthly" with an annual rate means divide by 1212 and count months; "quarterly" means divide by 44 and count quarters. Get these two right and the rest of the calculation is mechanical; get either wrong and the whole answer is off.

Exam-style practice questions

Practice questions written in the style of SCSA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WACE 20227 marksA loan of \25\,000istakenat is taken at 9\%perannumcompoundingmonthly,repaidbyequalmonthlypaymentsof per annum compounding monthly, repaid by equal monthly payments of \520520. (a) Write a recurrence relation for the balance AnA_n after nn payments. (b) Find the balance after the second payment. (c) Explain how you would use the recurrence to find how long the loan takes to repay.
Show worked answer →

A reducing-balance loan adds interest then subtracts the payment each month.

(a) Monthly rate =0.0912=0.0075= \dfrac{0.09}{12} = 0.0075, so An+1=1.0075 An−520A_{n+1} = 1.0075\,A_n - 520, with A0=25000A_0 = 25000. (2 marks)

(b) A1=1.0075×25000−520=25187.50−520=24667.50A_1 = 1.0075 \times 25000 - 520 = 25187.50 - 520 = 24667.50. A2=1.0075×24667.50−520=24852.51−520=24332.51A_2 = 1.0075 \times 24667.50 - 520 = 24852.51 - 520 = 24332.51, so $24 332.51\$24\,332.51. (3 marks)

(c) Iterate the recurrence, increasing nn until AnA_n first reaches zero or below; the value of nn at that point is the number of payments, and the last payment is reduced to clear the small remaining balance. (2 marks)

Markers reward the correct per-period rate, the recurrence with both interest and repayment, and accurate iteration.

WACE 20245 marks\400isdepositedattheendofeverymonthintoanaccountpaying is deposited at the end of every month into an account paying 3.6\%perannumcompoundingmonthly,startingfromazerobalance.Findthevalueoftheinvestmentafter per annum compounding monthly, starting from a zero balance. Find the value of the investment after 2$ years.
Show worked answer →

This is an annuity-investment: interest is added then a deposit is made each month.

Monthly rate =0.03612=0.003= \dfrac{0.036}{12} = 0.003, so An+1=1.003 An+400A_{n+1} = 1.003\,A_n + 400, with A0=0A_0 = 0, over n=24n = 24 months. (2 marks)

Iterating (or using the finance solver with PV=0PV = 0, PMT=−400PMT = -400, n=24n = 24, i=0.3%i = 0.3\%) gives a future value of about $9959\$9959. (3 marks)

Markers reward the annuity-investment recurrence with a positive deposit, the correct period rate and 2424 periods, and a balance near $9959\$9959.

ExamExplained