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Planar graphs and Euler's formula in WACE Mathematics Applications Unit 3

Syllabus dot point

“Identify planar graphs, count vertices, edges and faces, and verify and apply Euler's formula v minus e plus f equals 2.”

WACEMathematics ApplicationsUnit 37 min read

Quick answer

A planar graph is one that can be drawn with no edges crossing. When drawn that way it divides the plane into faces (regions), including the unbounded outer face. For any connected planar graph, Euler's formula links the counts: v−e+f=2v - e + f = 2, where vv is vertices, ee is edges and ff is faces. You can find any one of the three counts given the other two.

Jump to a section
  1. What this dot point is asking
  2. Planar graphs
  3. Counting faces
  4. Euler's formula
  5. When Euler's formula applies
  6. Degree of a face and the edge-face relationship
  7. Why planarity matters in applications
  8. Exam-style questions

What this dot point is asking

You must recognise planar graphs, count vertices, edges and faces correctly, and apply Euler's formula.

Planar graphs

A graph is planar if it can be drawn in the plane so that no two edges cross. A graph drawn with crossings may still be planar if it can be redrawn without them.

Planar graph

A planar graph is one that can be drawn so no edges intersect except at shared vertices. Crossings in a particular drawing do not make a graph non-planar; you test by attempting a crossing-free redraw.

When a planar graph is drawn without crossings, the edges divide the plane into regions called faces.

Counting faces

A face is a region bounded by edges. The crucial point is that the single unbounded region surrounding the whole graph counts as one face.

Always count the outer face

A planar drawing has enclosed faces plus exactly one outer (infinite) face. Forgetting the outer face is the most common error, giving an ff that is one too small and breaking Euler's formula.

For example, a triangle with one vertex inside joined to all three corners has 33 small inner faces plus the outer face, so f=4f = 4.

Euler's formula

For any connected planar graph, the three counts are tied together.

Euler's formula

v−e+f=2v - e + f = 2, where vv is the number of vertices, ee the number of edges, and ff the number of faces (including the outer face).

Rearrange to find any one count: f=2−v+ef = 2 - v + e, or e=v+f−2e = v + f - 2, or v=2−f+ev = 2 - f + e.

Worked example

Verifying and applying Euler's formula

A connected planar graph is drawn for a road map with 66 intersections (vertices) and 99 roads (edges).

Find the number of faces

Apply v−e+f=2v - e + f = 2 with v=6v = 6, e=9e = 9: 6−9+f=26 - 9 + f = 2, so f=2+3=5f = 2 + 3 = 5.

Interpret the faces

There are 55 faces: 44 enclosed regions bounded by roads, plus the 11 outer region surrounding the whole map.

Check by drawing

If you sketch a connected graph with 66 vertices and 99 edges with no crossings and count the regions, you should find exactly 55, including the outside. If you count only 44, you forgot the outer face.

Find edges for a different graph

If a connected planar graph has 1010 vertices and 77 faces, then e=v+f−2=10+7−2=15e = v + f - 2 = 10 + 7 - 2 = 15 edges.

When Euler's formula applies

Euler's formula needs the graph to be connected and planar (drawn without crossings). For a graph that is not connected, the formula adjusts by the number of separate components, but in SCSA Mathematics Applications you apply it to connected planar graphs. If a face count does not satisfy v−e+f=2v - e + f = 2, recheck whether you counted the outer face or whether the graph is actually connected.

Degree of a face and the edge-face relationship

Each face is bounded by a number of edges, called the degree of the face. Just as the handshake rule sums vertex degrees to twice the edges, the sum of all face degrees also equals twice the number of edges, because each edge borders exactly two faces. So ∑(face degrees)=2e\sum (\text{face degrees}) = 2e. This gives a second way to check a planar drawing: count the edges around every region (including the outer one) and confirm the total is 2e2e.

For example, in a connected planar graph with 44 faces totalling face degrees 3+3+4+6=163 + 3 + 4 + 6 = 16, the number of edges is 162=8\dfrac{16}{2} = 8, which you can then confirm against v−e+f=2v - e + f = 2.

Why planarity matters in applications

Planar graphs model situations that must be drawn or built without crossings: printed circuit boards where wires cannot overlap, road interchanges without overpasses, and map regions sharing borders. Euler's formula then links the counts of junctions, connections and enclosed regions, letting you deduce one count from the other two without redrawing. This is why SCSA pairs planarity with the formula: identify that a crossing-free drawing exists, then use v−e+f=2v - e + f = 2 to reason about the structure.

Common errors
Forgetting the outer face
The unbounded region is a face; include it or ff is too small.
Assuming a drawing with crossings is non-planar
Try to redraw without crossings before concluding a graph is not planar.
Applying the formula to a disconnected graph
Euler's v−e+f=2v - e + f = 2 is for connected planar graphs.
Miscounting edges or vertices
Recount carefully; one miscount throws off the whole relation and any value you solve for.

Exam-style questions

Questions in the style of SCSA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.

WACE 2022-style5 marks
A connected planar graph has 88 vertices and 1313 edges. (a) Use Euler's formula to find the number of faces. (b) State what is meant by a face, and confirm that the outer region is included in your count.
Show worked answer →

Euler's formula links the three counts for any connected planar graph.

(a) Euler's formula: v−e+f=2v - e + f = 2. Substitute v=8v = 8, e=13e = 13: 8−13+f=28 - 13 + f = 2, so f=2+5=7f = 2 + 5 = 7 faces. (3 marks)

(b) A face is a region bounded by edges, including the single unbounded outer region. So of the 77 faces, 66 are enclosed and 11 is the outer face. (2 marks)

Markers reward the correct substitution into v−e+f=2v - e + f = 2 and including the outer region in the face count.

WACE 2024-style4 marks
A graph is drawn with three edges crossing. Explain how you would determine whether the graph is planar, and verify Euler's formula for a cube graph with 88 vertices, 1212 edges and 66 faces.
Show worked answer →

Planarity is about whether crossings can be removed, not whether a particular drawing has them.

A graph is planar if it can be redrawn so that no edges cross. The presence of crossings in one drawing does not prove non-planarity; you attempt to redraw it without crossings. (2 marks)

For the cube graph: v−e+f=8−12+6=2v - e + f = 8 - 12 + 6 = 2, which satisfies Euler's formula, confirming it is a connected planar graph. (2 marks)

Markers reward defining planarity as redrawable without crossings and a correct Euler check.

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