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TASMath MethodsSyllabus dot point

How do we reverse the derivatives of exponential and trigonometric functions to find their antiderivatives?

Find antiderivatives of exponential and trigonometric functions and apply them in definite integrals.

The standard antiderivatives of e^kx, sin and cos functions, why each carries a reciprocal factor, and how to apply them in definite integrals for TCE Mathematics Methods Unit 4.

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What this dot point is asking

Integration is antidifferentiation, so every derivative rule you learned in Unit 3 reverses into an integration rule. This dot point collects the antiderivatives of the exponential and trigonometric functions, completing the toolkit alongside the power and reciprocal rules.

Reversing each derivative

Because ddx(ekx)=kekx\dfrac{d}{dx}(e^{kx}) = ke^{kx}, integrating ekxe^{kx} must divide by kk to cancel that factor. The trigonometric antiderivatives follow the same logic, with the added care that integrating sine introduces a minus sign.

Checking by differentiating back

The reliable way to confirm any antiderivative is to differentiate your answer and check you recover the original integrand. For instance, differentiating 13cos(3x)-\tfrac{1}{3}\cos(3x) gives 13(3sin(3x))=sin(3x)-\tfrac{1}{3}\cdot(-3\sin(3x)) = \sin(3x), which confirms the antiderivative of sin(3x)\sin(3x).

Worked example

Where these antiderivatives are used

These rules let you find areas under exponential and trigonometric curves, recover totals from exponential or oscillating rates of change, and compute the mean of a continuous random variable whose density involves ekxe^{-kx}. They also combine with the area-between-curves method whenever one of the boundaries is an exponential or trigonometric graph.

Summary

Reverse each derivative: dividing by kk for ekxe^{kx} and for sin(kx)\sin(kx) or cos(kx)\cos(kx), and remembering that the integral of sine carries a minus sign while the integral of cosine does not. Always verify by differentiating back. With these antiderivatives added to the power and reciprocal rules, you can integrate any standard function in the course and apply it in definite integrals.

Exam-style practice questions

Practice questions written in the style of TASC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2023 TASC4 marksEvaluate the following integrals: b) integral of -cos((pi/3) x) dx; c) the definite integral from 1/2 to 1 of e^(2x - 1) dx.
Show worked answer →

b) The antiderivative of cos(kx) is (1/k) sin(kx). Here k = pi/3, so 1/k = 3/pi:
integral of -cos((pi/3) x) dx = -(3/pi) sin((pi/3) x) + C.
The reciprocal factor 3/pi comes from reversing the chain rule.

c) The antiderivative of e^(2x - 1) is (1/2) e^(2x - 1) (divide by the coefficient of x).
Evaluate from 1/2 to 1: (1/2) e^(2(1) - 1) - (1/2) e^(2(1/2) - 1)
= (1/2) e^1 - (1/2) e^0 = (1/2)(e - 1).
Marks reward the correct reciprocal factor in each case and the correct substitution of limits in c).

2024 TASC4 marksa) Evaluate the integral of sqrt(2x - 3) dx. b) Evaluate the integral of e^(5x + 1) / e^(2x - 3) dx.
Show worked answer →

a) Write sqrt(2x - 3) = (2x - 3)^(1/2). Antidifferentiate using the rule for a linear inner function: raise the power and divide by the new power, then divide by the coefficient of x (which is 2):
integral = (1/2) times (2/3)(2x - 3)^(3/2) + C = (1/3)(2x - 3)^(3/2) + C.

b) First simplify the integrand using index laws: e^(5x + 1) / e^(2x - 3) = e^((5x + 1) - (2x - 3)) = e^(3x + 4).
integral of e^(3x + 4) dx = (1/3) e^(3x + 4) + C.
The key step in b) is simplifying to a single exponential before integrating; one mark for that, one for the antiderivative.