How do we differentiate sine, cosine and tangent, and combine them with the chain, product and quotient rules?
Establish and use the derivatives of sin x, cos x and tan x, including with the chain, product and quotient rules.
Derivatives of sin x, cos x and tan x, why radians are required, and how to combine them with the chain, product and quotient rules for TCE Mathematics Methods Unit 3.
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What this dot point is asking
This dot point completes your library of standard derivatives by adding the three core trigonometric functions. Once you have these alongside powers, exponentials and logarithms, you can differentiate almost any function in the course.
The three standard derivatives
The results you must memorise are short, but the minus sign and the radian requirement trip up many students.
Notice the symmetry: differentiating sine gives cosine, and differentiating cosine gives negative sine. Differentiating twice more returns you to where you started, so the fourth derivative of is again.
Combining with the chain rule
For a function of the form , the chain rule multiplies by the derivative of the inside:
So and . The inner derivative is exactly the factor students most often drop.
Combining with product and quotient rules
Trigonometric terms appear inside products and quotients constantly. Apply the product rule or the quotient rule exactly as for any other functions, treating , or as one of the factors.
Where these are used
The derivatives of trigonometric functions feed straight into curve sketching (finding stationary points of , for example), into optimisation problems with periodic models, and into rates of change for anything oscillating such as a tide height or an alternating current. They also pair with integration in Unit 4, where reversing each derivative gives the corresponding antiderivative.
Summary
Learn the three standard derivatives, keep your calculator in radian mode, and treat the trigonometric function as just another piece when you apply the chain, product or quotient rule. The two recurring slips are the missing minus sign on the derivative of cosine and the missing inner factor from the chain rule, so build a habit of checking both every time.
Exam-style practice questions
Practice questions written in the style of TASC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2024 TASC2 marksDifferentiate y = 3 cos(pi x) + 6 tan(2x).Show worked answer →
Differentiate term by term, applying the standard derivatives with the chain rule for the inner linear functions.
Term 1: d/dx[3 cos(pi x)] = 3 times (-sin(pi x)) times pi = -3 pi sin(pi x). The chain rule brings down the factor pi, the derivative of the inside pi x.
Term 2: d/dx[6 tan(2x)] = 6 times sec^2(2x) times 2 = 12 sec^2(2x). The derivative of tan u is sec^2(u), and the chain rule brings down the factor 2.
So dy/dx = -3 pi sin(pi x) + 12 sec^2(2x). One mark is for each correctly differentiated term, including the chain-rule factors. These results require x to be in radians.
2023 TASC2 marksDifferentiate (no simplification required): y = ln(4x + 1) + sin(3x^2).Show worked answer →
Differentiate each term using the chain rule.
Term 1: d/dx[ln(4x + 1)] = (1/(4x + 1)) times 4 = 4/(4x + 1). The derivative of ln(u) is u'/u with u = 4x + 1, so u' = 4.
Term 2: d/dx[sin(3x^2)] = cos(3x^2) times 6x = 6x cos(3x^2). The derivative of sin(u) is cos(u) times u', with u = 3x^2 giving u' = 6x.
So dy/dx = 4/(4x + 1) + 6x cos(3x^2). One mark per term. Markers accept the unsimplified form here, but the chain-rule factor on each term is essential.