Topic 3: Statistical inference
Understand the distribution of the sample mean, apply the central limit theorem to describe its shape, mean and standard deviation, and use these to compute probabilities for sample means drawn from a population
A focused answer to the QCE Specialist Mathematics Unit 4 dot point on the sampling distribution of the mean. Covers the mean and standard error of the sample mean, the central limit theorem, standardising to compute probabilities, and how sample size affects spread, with a verified worked example and the standard-error mistake QCAA markers watch for.
Reviewed by: AI editorial process; not yet individually human-reviewed
Have a quick question? Jump to the Q&A page
What this dot point is asking
QCAA wants you to understand that the sample mean is itself a random variable with its own distribution, to state and apply the central limit theorem, and to use the resulting normal model to compute probabilities about sample means. This is the foundation of statistical inference, assessed in IA3 and the external assessment, and it precedes confidence-interval work.
The answer
The sample mean is random
If you take a random sample of size from a population and compute its mean , a different sample gives a different mean. So is a random variable. Its distribution is called the sampling distribution of the mean, and it has its own mean and standard deviation.
Mean and standard error
If the population has mean and standard deviation , then for a sample of size :
The standard deviation of the sample mean, , is called the standard error. It is smaller than the population standard deviation, and it shrinks as grows: larger samples give more reliable estimates of . Crucially the divisor is , not .
The central limit theorem
The central limit theorem states that for a sufficiently large sample size , the distribution of the sample mean is approximately normal,
regardless of the shape of the original population. If the population is already normal, is exactly normal for any . A common rule of thumb takes as large enough for the approximation when the population is not too skewed.
Standardising to find probabilities
To compute a probability for , standardise using the standard error:
This has the standard normal distribution , so probabilities follow from the normal model. The only change from a single-observation calculation is dividing by rather than .
Effect of sample size
Because the standard error is , quadrupling the sample size halves the spread of . This is why larger samples produce tighter estimates and narrower confidence intervals: the sampling distribution concentrates around .
Working backwards to find a sample size
A favourite extended-response task gives a probability statement about and asks for the sample size. The method reverses standardising: convert the probability to a critical -value, then solve for . Because must be a whole number of observations, round the result, and state explicitly that a sample size is an integer. Reading the correct from the stated tail probability (lower tail, upper tail, or central region) is where care is needed, and a sketch of the normal curve with the area shaded prevents sign errors.
Normal population versus the central limit theorem
It is worth distinguishing two reasons might be normal. If the population itself is normal, then is exactly normal for every sample size, however small, because a sum of normal variables is normal. If the population is not normal, is only approximately normal, and only for a large enough , by the central limit theorem. An exam question that asks you to justify normality is testing exactly this distinction: cite the normal population if one is given, and cite the central limit theorem only when the population shape is unknown or non-normal and is large.
Single observation versus the mean of a sample
The most consequential modelling decision is whether a question concerns one randomly chosen value or the average of a sample. A single observation has standard deviation ; the sample mean has the much smaller standard error . Using the wrong one is the difference between a correct and an incorrect probability. Read the wording carefully: phrases like "the mean of the sample" or "the average" signal , while "a randomly selected" individual signals .
Exam-style practice questions
Practice questions written in the style of QCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
QCAA 20245 marksPaper 2 (complex familiar). Heights of Year 12 students are normal with mean cm and standard deviation cm. A random sample of is taken. (a) Explain why the sample mean is normally distributed. (b) Determine . (c) If there is a probability that lies within of the mean, determine . (d) Hence determine .Show worked answer →
Standard error cm; mean .
(a) Because the population is itself normal, is normal for any sample size, not relying on a large .
(b) , so
(c) The central leaves in the two tails, so each tail is ;
(d) The upper critical value for a tail is , so cm.
Markers reward the normality reason, the standardised probability, the tail logic, and the value of .
QCAA 20237 marksPaper 2 (complex unfamiliar). University travel times are normal with mean min and standard deviation min. A random sample of gives . (a) Determine . (b) Given , determine . (c) A second sample has ; determine its size.Show worked answer →
First sample: standard error min; mean .
(a) -values and , so
(b) For a lower area , , so min.
(c) puts at : , so , giving
Markers reward the standard error, both standardisations, and solving for with rounding to a whole sample size.
