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Topic 3: Statistical inference

Construct and interpret confidence intervals for a population mean using the sample mean and standard error, choosing the appropriate confidence level, and understand the meaning of the confidence level in repeated sampling

A focused answer to the QCE Specialist Mathematics Unit 4 dot point on confidence intervals. Covers the structure of an interval estimate, the critical value and margin of error, how confidence level and sample size affect width, the correct repeated-sampling interpretation, and a fully verified worked example with the common interpretation mistake QCAA penalises.

Reviewed by: AI editorial process; not yet individually human-reviewed

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What this dot point is asking

QCAA wants you to build an interval estimate for an unknown population mean from a sample, choose a confidence level, compute the margin of error, and interpret the interval correctly in repeated-sampling language. Confidence intervals are a major theme of IA3 and the external assessment, and the interpretation is examined as carefully as the calculation.

The answer

Point estimate versus interval estimate

A single sample mean xˉ\bar{x} is a point estimate of the population mean μ\mu, but it almost certainly is not exactly μ\mu. A confidence interval gives a range of plausible values for μ\mu, built around xˉ\bar{x}, together with a stated level of confidence.

Structure of the interval

A confidence interval for μ\mu (with known population standard deviation σ\sigma) is

xˉ±zσn,\bar{x} \pm z^{*}\,\frac{\sigma}{\sqrt{n}},

where σn\dfrac{\sigma}{\sqrt{n}} is the standard error and zz^{*} is the critical value from the standard normal distribution for the chosen confidence level. The quantity zσnz^{*}\dfrac{\sigma}{\sqrt{n}} is the margin of error, the half-width of the interval.

Critical values

The critical value zz^{*} cuts off the central proportion of the standard normal equal to the confidence level. The standard values are:

90%:z=1.645,95%:z=1.960,99%:z=2.576.90\%: z^{*} = 1.645, \qquad 95\%: z^{*} = 1.960, \qquad 99\%: z^{*} = 2.576.

A higher confidence level needs a larger zz^{*}, so the interval is wider. There is a trade-off: more confidence costs precision.

Width, sample size and confidence level

The interval width is 2zσn2z^{*}\dfrac{\sigma}{\sqrt{n}}. It widens with a higher confidence level (larger zz^{*}) and narrows with a larger sample (the n\sqrt{n} in the denominator). To halve the margin of error you must quadruple the sample size, because of the square root.

Interpreting the confidence level

The correct interpretation refers to the method over repeated sampling. A 95%95\% confidence level means that if many samples were taken and an interval constructed from each, about 95%95\% of those intervals would contain the true mean μ\mu. It does not mean there is a 95%95\% probability that μ\mu lies in this particular interval: μ\mu is a fixed number, and any single interval either contains it or does not. The confidence is in the long-run reliability of the procedure.

Using a sample standard deviation

In strict theory the formula uses the known population standard deviation σ\sigma. In practice σ\sigma is rarely known, so QCE uses the sample standard deviation ss in its place, writing the interval as xˉ±zsn\bar{x} \pm z^{*}\dfrac{s}{\sqrt{n}}. This is justified by the central limit theorem and the large samples used in assessment items: for the sample sizes QCAA sets, the normal critical values zz^{*} remain a good approximation, which is why the syllabus describes these as approximate confidence intervals. The standard error sn\dfrac{s}{\sqrt{n}} is the single most important quantity to compute correctly, since every other step depends on it.

Recovering missing information

Examiner-favoured problems give you an interval and ask you to work backwards. Because the half-width equals zsnz^{*}\dfrac{s}{\sqrt{n}}, knowing any three of the four quantities (half-width, zz^{*}, ss, nn) lets you solve for the fourth. A common task is to read the half-width as half the difference of the endpoints, then rearrange to find the sample size nn or the sample standard deviation ss. Once nn is recovered, you can rebuild the interval at a different confidence level using the same xˉ\bar{x} and ss, as the elephant-mass question above shows.

Making a decision from an interval

A confidence interval doubles as an informal hypothesis test. If a claimed value of the mean lies inside the interval, the data are consistent with the claim at that confidence level; if it lies outside, there is evidence against the claim. Phrasing matters: write that the value is or is not contained in the interval, and state the confidence level, rather than declaring the claim simply true or false. Because higher confidence widens the interval, a value can sit outside a 95%95\% interval yet inside a 99%99\% interval, so always tie the conclusion to the stated level.

Exam-style practice questions

Practice questions written in the style of QCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

QCAA 20244 marksPaper 2 (complex familiar). A company claims the mean battery life of a phone is 9.59.5 hours. A random sample of 4040 phones gives sample mean xˉ=9.31\bar{x} = 9.31 hours and standard deviation s=0.52s = 0.52 hours. (a) Determine an approximate 95%95\% confidence interval for the population mean. (b) Determine an approximate 99%99\% confidence interval. (c) Evaluate the claim that either interval could support the company.
Show worked answer →

Margin of error is zsnz^{*}\,\dfrac{s}{\sqrt{n}} with n=40n = 40, xˉ=9.31\bar{x} = 9.31, s=0.52s = 0.52.

(a) For 95%95\%, z=1.96z^{*} = 1.96. Margin =1.96×0.52400.16= 1.96 \times \dfrac{0.52}{\sqrt{40}} \approx 0.16. Interval =9.31±0.16=(9.15, 9.47)= 9.31 \pm 0.16 = (9.15,\ 9.47) hours.

(b) For 99%99\%, z=2.576z^{*} = 2.576. Margin 0.21\approx 0.21. Interval =(9.10, 9.52)= (9.10,\ 9.52) hours.

(c) The claimed 9.59.5 lies outside the 95%95\% interval but inside the 99%99\% interval, so the two give opposite conclusions. The comment is unreasonable: the conclusion depends on the confidence level chosen.

Markers reward both intervals and a justified evaluation that links the level to the conclusion.

QCAA 20234 marksPaper 2 (complex familiar). Wait times are assumed normally distributed. A random sample of 1212 customers gives xˉ=9.23\bar{x} = 9.23 minutes and s=2.384s = 2.384 minutes. (a) State the standard error. (b) Construct an approximate 95%95\% confidence interval and evaluate the company claim that the mean wait time is 7.67.6 minutes.
Show worked answer →

(a) Standard error =sn=2.384120.688= \dfrac{s}{\sqrt{n}} = \dfrac{2.384}{\sqrt{12}} \approx 0.688 minutes.

(b) With z=1.96z^{*} = 1.96: margin =1.96×0.6881.35= 1.96 \times 0.688 \approx 1.35. Interval =9.23±1.35=(7.89, 10.58)= 9.23 \pm 1.35 = (7.89,\ 10.58) minutes.

The claimed 7.67.6 lies below the lower limit 7.897.89, so it is not contained in the interval. There is evidence against the claim at the 95%95\% level.

Markers reward the standard error, the interval, and a decision justified by whether 7.67.6 lies inside it.

QCAA 20226 marksPaper 2 (complex unfamiliar). A sample of elephant masses has mean 52065206 kg and standard deviation 356356 kg. A 90%90\% confidence interval for the population mean is (5159.1, 5252.9)(5159.1,\ 5252.9) kg. Determine a 99%99\% confidence interval from the same data.
Show worked answer →

Recover nn from the 90%90\% interval. For 90%90\%, z=1.645z^{*} = 1.645, and the half-width is 5252.95159.12=46.9\dfrac{5252.9 - 5159.1}{2} = 46.9. So 1.645×356n=46.91.645 \times \dfrac{356}{\sqrt{n}} = 46.9, giving n=1.645×35646.912.49\sqrt{n} = \dfrac{1.645 \times 356}{46.9} \approx 12.49, so n156n \approx 156.

Build the 99%99\% interval with z=2.576z^{*} = 2.576: margin =2.576×35615673.4= 2.576 \times \dfrac{356}{\sqrt{156}} \approx 73.4. Interval =5206±73.4=(5132.6, 5279.4)= 5206 \pm 73.4 = (5132.6,\ 5279.4) kg.

The higher confidence level gives a wider interval, as expected. Markers reward recovering nn, the new margin, and the consistency comment.

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