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Mathematical Induction (HSC Maths Extension 1, 2026) quiz

10questions. Pick an answer and you'll see why right away.

  1. Which four parts make up the standard structure of a proof by mathematical induction?

  2. In a proof that the statement P(n)P(n) holds, what does the inductive hypothesis assume?

  3. Proving βˆ‘i=1ni2=n(n+1)(2n+1)6\sum_{i=1}^{n} i^2 = \frac{n(n+1)(2n+1)}{6}, what is the base case value at n=1n = 1 for both sides?

  4. In proving βˆ‘i=1n(2iβˆ’1)=n2\sum_{i=1}^{n} (2i-1) = n^2, the (k+1)(k+1)-th term added to the sum is:

  5. Proving 7nβˆ’17^n - 1 is divisible by 66, the hypothesis gives 7k=6M+17^k = 6M + 1. What is 7k+1βˆ’17^{k+1} - 1 in factored form?

  6. Proving 5n+35^n + 3 is divisible by 44, what is the base case n=1n = 1 value of 5n+35^n + 3?

  7. Proving 2n>n22^n > n^2 for nβ‰₯5n \ge 5 by induction, why must the base case be n=5n = 5 rather than n=1n = 1?

  8. Proving 9nβˆ’19^n - 1 is divisible by 88, the hypothesis is 9k=8M+19^k = 8M + 1. What is 9k+1βˆ’19^{k+1} - 1 in factored form?

  9. Proving βˆ‘i=1n2i=2n+1βˆ’2\sum_{i=1}^{n} 2^i = 2^{n+1} - 2, adding the term 2k+12^{k+1} to (2k+1βˆ’2)(2^{k+1} - 2) gives:

  10. For the sequence a1=1a_1 = 1, an+1=3an+2a_{n+1} = 3 a_n + 2, applying the recursion to the hypothesis ak=2β‹…3kβˆ’1βˆ’1a_k = 2 \cdot 3^{k-1} - 1 gives ak+1a_{k+1} equal to: