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WASpecialist MathematicsSyllabus dot point

How do the exponential and logistic differential equations model unrestricted and limited growth?

Set up and solve the exponential growth-decay equation and the logistic equation and interpret their solutions

WACE Specialist Unit 4 growth models: the exponential equation dy/dt equal to ky and its solution, the logistic equation with a carrying capacity, the S-shaped solution curve, equilibria, and interpreting parameters, with a worked example.

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  1. What this dot point is asking
  2. The exponential model
  3. The logistic model
  4. Equilibria and the S-curve

What this dot point is asking

SCSA wants you to set up these two models from a description, solve them (logistic via separation and partial fractions), and interpret the parameters and long-term behaviour.

The exponential model

When the rate of change is proportional to the current amount, dydt=ky\tfrac{dy}{dt} = ky. Separating variables and integrating gives

where y0y_0 is the initial value and kk is the constant of proportionality. Positive kk models unrestricted growth; negative kk models decay such as radioactive half-life. This model has no upper bound, which is unrealistic over long times.

The logistic model

Real populations are limited by resources. The logistic equation adds a braking factor:

where MM is the carrying capacity. When PP is small the bracket is near 11 and growth is nearly exponential; as PP approaches MM the bracket approaches 00 and growth slows to a halt.

Equilibria and the S-curve

Solving the logistic equation uses separation of variables with a partial-fraction decomposition of 1P(1P/M)\tfrac{1}{P(1 - P/M)}, leading to a solution of the form P=M1+AektP = \tfrac{M}{1 + A e^{-kt}}.