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Polarisation of light: WACE Year 12 Physics Unit 4

Syllabus dot point

“Explain polarisation of light and how it provides evidence that light is a transverse wave”

8 min read

Quick answer

Light is a transverse electromagnetic wave, with its electric field oscillating perpendicular to the direction of travel. Ordinary light vibrates in all such directions; a polarising filter transmits only the component along its axis, producing polarised light. Two filters at right angles block light entirely. Only transverse waves can be polarised, so polarisation is direct evidence that light is transverse, not longitudinal.

What this dot point is asking

WACE wants you to explain what polarisation is, how filters produce and detect it, and why it proves light is transverse. This is the one wave property that distinguishes transverse from longitudinal waves.

Transverse waves and polarisation

In a transverse wave the oscillation is perpendicular to the direction of travel, so it has a definite orientation in the plane across the beam. Unpolarised light from a typical source contains electric-field oscillations in every direction perpendicular to travel, mixed randomly. Polarised light has its oscillation confined to a single direction.

How a polarising filter works

A polarising filter has a transmission axis and passes only the component of the electric field aligned with that axis, absorbing the perpendicular component. Sending unpolarised light through one filter therefore produces polarised light and roughly halves the intensity, because on average half the oscillation lies along the axis.

Crossed filters

If polarised light then meets a second filter (an analyser) whose axis is parallel to the first, it passes through. If the second axis is at right angles to the first, no component of the already-polarised light lies along it, so the light is completely blocked. Rotating one filter between these positions smoothly dims the light from bright to dark, which is the standard demonstration that the light has been polarised.

Why only transverse waves can be polarised

A longitudinal wave, such as sound, oscillates along its direction of travel and has no sideways orientation to select, so it cannot be polarised. The fact that light can be polarised therefore shows it must be transverse. This was important historical evidence pinning down the nature of light waves.

Everyday applications

Polarising sunglasses have a vertical transmission axis that blocks the strongly horizontal glare reflected off roads and water. Photographers use polarising filters to deepen sky contrast and cut reflections, and stress patterns in transparent plastics show up between crossed polarisers because the material rotates the plane of polarisation.

Light through two polarising filters

Crossing the analyser

Unpolarised light of intensity I0I_0 passes through a first polariser, then a second one whose axis is at 90∘90^\circ to the first. Track the intensity.

After the first filter, the light is polarised and its intensity is halved:

I1=12I0.I_1=\tfrac{1}{2}I_0.

The polarised light now meets a filter at right angles. The component of the polarised oscillation along this perpendicular axis is zero, so:

I2=0.I_2=0.

No light emerges through crossed filters, demonstrating the light was fully polarised by the first filter.

Malus's law and partial angles

For angles between parallel and crossed, the transmitted intensity follows Malus's law: if already-polarised light of intensity I1I_1 meets a filter whose axis is at angle θ\theta to the light's polarisation, the transmitted intensity is I=I1cos⁡2θI=I_1\cos^2\theta. This gives the full range smoothly: at θ=0\theta=0 the factor cos⁡20=1\cos^2 0=1 and all the light passes; at θ=45∘\theta=45^\circ the factor is 0.50.5 so half passes; at θ=90∘\theta=90^\circ the factor is 00 and the light is extinguished. Remember the first filter acting on unpolarised light is a special case: it always transmits half, regardless of orientation, because the source contains all directions equally. Only once the light is polarised does the cos⁡2θ\cos^2\theta rule apply to subsequent filters.

Explaining the evidence

When asked why polarisation matters, state clearly that it can occur only for transverse waves and therefore shows light is transverse. Describe the two-filter test, noting that the second filter dims the light as it rotates and blocks it completely when crossed.

Claiming a single filter blocks all the light

Students sometimes say one polarising filter stops the light. A single filter passing unpolarised light transmits about half of it, the component along its axis; the light is dimmed and polarised, not blocked. Full extinction needs a second filter crossed at right angles to the first.

Exam-style questions

Questions in the style of SCSA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.

WACE 2022-style6 marks
Unpolarised light of intensity I0I_0 passes through two polarising filters. The first has a vertical transmission axis; the second is at 30∘30^\circ to the vertical. (a) Determine the intensity of the light after the first filter. (b) Using Malus's law I=I1cos⁡2θI=I_1\cos^2\theta, calculate the intensity after the second filter in terms of I0I_0. (c) State what happens to the transmitted intensity as the second filter is rotated to 90∘90^\circ.
Show worked answer →

A 6 mark calculation rewards the half-intensity step, Malus's law and the crossed-filter result.

(a) After the first filter
Unpolarised light is halved and polarised: I1=12I0I_1=\tfrac{1}{2}I_0.
(b) After the second filter
Apply Malus's law with θ=30∘\theta=30^\circ:
I2=I1cos⁡2θ=12I0cos⁡230∘=12I0(0.866)2=12I0(0.75)=0.375 I0.I_2=I_1\cos^2\theta=\tfrac{1}{2}I_0\cos^2 30^\circ=\tfrac{1}{2}I_0(0.866)^2=\tfrac{1}{2}I_0(0.75)=0.375\,I_0.
(c) At 90∘90^\circ
cos⁡290∘=0\cos^2 90^\circ=0, so I2=0I_2=0: the filters are crossed and no light is transmitted.

Markers reward I1=12I0I_1=\tfrac{1}{2}I_0, the correct use of cos⁡230∘\cos^2 30^\circ giving 0.375 I00.375\,I_0, and zero transmission at 90∘90^\circ.

WACE 2021-style5 marks
Explain how the polarisation of light provides evidence that light is a transverse wave, and explain why sound cannot be polarised.
Show worked answer →

A 5 mark explanation needs the transverse-orientation argument applied to both light and sound.

Light is transverse. A transverse wave oscillates perpendicular to its direction of travel, so the oscillation has a definite orientation across the beam that a polariser can select. Light can be polarised: passing it through one filter confines the electric-field oscillation to one direction, and a second crossed filter then blocks it. The ability to select and block oscillation directions shows light has sideways oscillations, so it must be transverse.

Sound cannot. Sound is a longitudinal wave, oscillating along its direction of travel (compressions and rarefactions). There is no sideways orientation to select, so a polariser has nothing to filter and sound cannot be polarised.

Markers reward polarisation requiring a transverse oscillation, the filter demonstration, and sound being longitudinal with no transverse component.

Practise this

Sources & how we know this

ExamExplained