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WAPhysicsSyllabus dot point

How does light behave as a wave through diffraction and interference?

Explain diffraction, two-slit interference and the electromagnetic spectrum as evidence for the wave model of light

A focused answer to the WACE Year 12 Physics Unit 4 dot point on light as a wave. Diffraction, Young's double-slit interference and the path-difference condition, fringe spacing, and the electromagnetic spectrum.

Generated by Claude Opus 4.78 min answer

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What this dot point is asking

WACE wants you to use diffraction and two-slit interference as the historical and quantitative evidence that light is a wave, work with the path-difference conditions and the fringe-spacing formula, and place visible light within the broader electromagnetic spectrum. The skill being tested is connecting the geometry of the slits to the observed pattern.

Diffraction

Diffraction is the spreading of a wave as it passes an edge or through a gap. The effect is significant when the gap width is similar to or smaller than the wavelength: a wide gap gives little spreading, a narrow gap gives a lot. Because visible light has a tiny wavelength (hundreds of nanometres), noticeable diffraction needs very narrow slits, which is why everyday light appears to travel in straight lines.

Two-slit interference

In Young's experiment, monochromatic light illuminates two narrow, closely spaced slits that act as coherent sources. The diffracted light from each slit overlaps and superposes, producing alternating bright and dark fringes on a distant screen. Bright fringes (constructive interference) occur where the path difference is a whole number of wavelengths,

dsinθ=mλ,m=0,1,2,d\sin\theta=m\lambda,\quad m=0,1,2,\dots

Dark fringes (destructive interference) occur at half-integer multiples, dsinθ=(m+12)λd\sin\theta=(m+\tfrac{1}{2})\lambda. Here dd is the slit separation and θ\theta the angle to the fringe.

Fringe spacing

For small angles and a screen a distance LL away, the spacing between adjacent bright fringes is

Δy=λLd.\Delta y=\frac{\lambda L}{d}.

So fringes spread out for longer wavelengths (red), a more distant screen, or closer slits. Measuring Δy\Delta y, LL and dd lets you calculate the wavelength of light, which is how the experiment first pinned down λ\lambda for visible light.

Coherence and monochromatic light

A clear pattern needs coherent sources: a constant phase relationship and a single wavelength. This is why a single source illuminating two slits (or a laser) works, while two independent lamps do not. White light produces overlapping coloured fringes because each wavelength has its own spacing.

The electromagnetic spectrum

Light is one part of a continuous spectrum of electromagnetic waves, all travelling in vacuum at c=3.0×108 m s1c=3.0\times10^{8}\ \text{m s}^{-1} and all obeying c=fλc=f\lambda. In order of increasing frequency (decreasing wavelength) the spectrum runs radio, microwave, infrared, visible, ultraviolet, X-ray and gamma. Visible light occupies only a narrow band from about 400 nm400\ \text{nm} (violet) to 700 nm700\ \text{nm} (red). All these waves are transverse oscillations of electric and magnetic fields.

Keeping the units straight

Slit separations are millimetres, fringe spacings millimetres, wavelengths nanometres, and the screen distance metres. Convert everything to metres before substituting, and decide whether a question is asking for a fringe position (use dsinθ=mλd\sin\theta=m\lambda) or a spacing (use Δy=λLd\Delta y=\frac{\lambda L}{d}).