How can one organic family be converted into another through characteristic reactions?
Describe the characteristic reactions of organic families, including substitution, addition, oxidation and esterification, and combine them into multi-step pathways
A focused answer to the WACE Year 12 Chemistry dot point on substitution, addition, oxidation and esterification reactions and how to build multi-step organic pathways, with a worked route and common mistakes.
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What this dot point is asking
Each organic functional group reacts in characteristic ways. Knowing these reactions lets you predict products and design reaction pathways, sequences of steps that convert a starting material into a target compound.
Substitution (alkanes and haloalkanes)
Alkanes are unreactive but undergo substitution with halogens in ultraviolet light: an H atom is replaced by a halogen atom, e.g. . This is a free-radical reaction that gives a mixture of products.
Haloalkanes undergo substitution with aqueous hydroxide to form alcohols: . This is a useful way to introduce an OH group.
Addition (alkenes)
Alkenes are reactive because of the C=C double bond and undergo addition, where the double bond opens and atoms add across it:
- Hydrogenation: (nickel catalyst).
- Halogenation: addition of (the rapid decolourising of bromine water is the test for a C=C).
- Hydration: addition of water (steam, acid catalyst) gives an alcohol: .
- Hydrohalogenation: addition of gives a haloalkane.
Oxidation (alcohols)
Primary alcohols are oxidised (by acidified dichromate or permanganate) first to an aldehyde and then to a carboxylic acid. Secondary alcohols oxidise to a ketone. Tertiary alcohols are not readily oxidised, because the carbon bearing the OH has no H to remove. For example:
The orange dichromate turning green is the visual sign of oxidation.
Esterification (alcohol plus carboxylic acid)
A carboxylic acid reacts with an alcohol, with a concentrated sulfuric acid catalyst, to form an ester and water. This is a reversible condensation reaction:
Esters have characteristic sweet, fruity smells.
Building a pathway
A reaction pathway links these single steps. To plan one, identify the functional group of the start and target, then choose reactions that step from one family to the next. For example, to convert ethene to ethyl ethanoate, you would hydrate ethene to ethanol, oxidise some ethanol to ethanoic acid, then esterify the two.
When answering pathway questions in the WACE examination, give the reagents and conditions for every step, write balanced equations, and identify the functional group formed at each stage.
Exam-style practice questions
Practice questions written in the style of SCSA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
WACE 20228 marksOutline a synthesis of 1-chloropropane starting from propene , where the first step must produce propan-1-ol. (a) Give the reagents, conditions and equation for each step. (b) Identify the reaction type at each step. (c) Suggest one reason the overall yield of 1-chloropropane is less than .Show worked answer β
An 8 mark question rewards a valid two-step route with reagents, conditions, equations, types, and a yield comment.
Step 1 (propene to propan-1-ol): to obtain the primary alcohol (anti-Markovnikov product), this is best framed as hydration to give propan-1-ol; conditions are steam with an acid catalyst (or, in practice, a route via hydroboration, but at WACE level state addition of water across the double bond):
Reaction type: addition (hydration).
Step 2 (propan-1-ol to 1-chloropropane): substitution of the group. React the alcohol with a chlorinating agent (for example with a catalyst, or /):
Reaction type: substitution.
(c) The yield is below because of competing reactions (for example formation of the secondary alcohol/chloride from Markovnikov addition, or elimination to propene), incomplete reaction, and losses during separation and purification.
Markers reward the addition step with conditions and equation, the substitution step with conditions and equation, the two reaction types, and a sensible yield-loss reason.
WACE 20206 marksCompound is a haloalkane . Describe how can be converted in successive steps into (i) ethanol, (ii) ethanoic acid, and (iii) ethyl ethanoate. Give the reagents and conditions for each step and write the equation for step (iii).Show worked answer β
A 6 mark question rewards each conversion with correct reagents and conditions plus the final equation.
- (i) to ethanol (substitution)
- warm with aqueous sodium hydroxide; the hydroxide replaces the bromide: .
- (ii) ethanol to ethanoic acid (oxidation)
- heat under reflux with acidified potassium dichromate; the primary alcohol is oxidised fully to the carboxylic acid, (orange to green).
- (iii) esterification
- warm the ethanoic acid with ethanol and a concentrated sulfuric acid catalyst:
Markers reward the hydroxide substitution, the reflux-with-dichromate oxidation to the acid, and the acid-catalysed reversible esterification equation.
