How are alcohols classified, and what reactions do they undergo?
Classify alcohols as primary, secondary or tertiary and describe their characteristic reactions including oxidation, dehydration and combustion
A focused answer to the WACE Year 12 Chemistry dot point on alcohols, their classification as primary, secondary and tertiary, and their key reactions including oxidation to carbonyl compounds, dehydration to alkenes, and combustion, with a worked example and common exam mistakes.
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What this dot point is asking
An alcohol contains the hydroxyl functional group, -OH, attached to a carbon atom. The -OH group makes alcohols polar and able to hydrogen bond, and it is the reactive site for their characteristic reactions.
Classifying alcohols
Alcohols are classified by the number of carbon atoms bonded to the carbon that carries the -OH group:
- Primary (1 degree): the -OH carbon is attached to one other carbon (for example ethanol).
- Secondary (2 degrees): the -OH carbon is attached to two other carbons (for example propan-2-ol).
- Tertiary (3 degrees): the -OH carbon is attached to three other carbons (for example 2-methylpropan-2-ol).
Oxidation
Oxidation uses an oxidising agent such as acidified potassium dichromate (orange, turning green) or permanganate (purple, turning colourless).
- Primary: ethanol oxidises first to ethanal (an aldehyde), then with further oxidation to ethanoic acid (a carboxylic acid).
- Secondary: propan-2-ol oxidises to propanone (a ketone), which does not oxidise further easily.
- Tertiary: no reaction; the carbon bearing -OH has no hydrogen to lose.
Dehydration
Heating an alcohol with a suitable acid catalyst (such as concentrated sulfuric acid) removes a water molecule to form an alkene. This is an elimination reaction; for example ethanol dehydrates to ethene:
Combustion
Like all organic compounds, alcohols burn. Complete combustion in plentiful oxygen gives carbon dioxide and water and releases a large amount of energy, which is why ethanol is used as a fuel:
Reflux versus distillation in oxidation
A practical detail WACE rewards is controlling how far a primary alcohol oxidises. To stop at the aldehyde, the aldehyde is distilled off as it forms, because its boiling point is lower than the alcohol's and it escapes the mixture before it can be oxidised further. To go all the way to the carboxylic acid, the mixture is heated under reflux (vapours condense and return to the flask) with excess oxidising agent, so the aldehyde stays in contact with the dichromate and is oxidised completely. The same reagent therefore gives different products depending on the apparatus, which is a classic short-answer point.
Physical properties from the hydroxyl group
The group also explains the physical behaviour of alcohols. Because allows hydrogen bonding between molecules, alcohols have much higher boiling points than alkanes of similar molar mass and the smaller alcohols (methanol, ethanol, propanol) are fully miscible with water. As the carbon chain lengthens, the non-polar hydrocarbon part dominates and water solubility falls, so longer-chain alcohols behave more like hydrocarbons. This trend connects directly to the intermolecular-forces reasoning used throughout Unit 4.
Why this matters
Alcohols sit at the centre of organic synthesis: they can be made from alkenes (hydration) or haloalkanes (substitution), and converted into aldehydes, ketones, carboxylic acids, esters and alkenes. Their reactions are essential building blocks for the multi-step pathways examined in Unit 4.
Exam-style practice questions
Practice questions written in the style of SCSA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
WACE 20216 marksThree bottles contain butan-1-ol, butan-2-ol and 2-methylpropan-2-ol, but the labels have come off. (a) Classify each alcohol. (b) Describe how acidified potassium dichromate could be used to distinguish them, stating the observation and organic product for each. (c) Write the equation for the complete combustion of butan-1-ol ().Show worked answer β
A 6 mark question rewards the classifications, the dichromate observations, and a balanced combustion equation.
(a) Butan-1-ol is primary (the carbon has one carbon attached), butan-2-ol is secondary (two carbons attached), and 2-methylpropan-2-ol is tertiary (three carbons attached).
(b) With warm acidified (orange):
- Primary butan-1-ol: orange to green; oxidised to butanal, then on further oxidation to butanoic acid.
- Secondary butan-2-ol: orange to green; oxidised to butanone (a ketone), no further reaction.
- Tertiary 2-methylpropan-2-ol: no colour change (stays orange); it is not oxidised.
So the bottle that does not change colour is the tertiary alcohol. The other two both turn green but the primary one can be distilled to a carboxylic acid; this difference is used to tell them apart.
(c) .
Markers reward the three classifications, the orange-to-green (or no change) observations with the correct products, and the balanced combustion equation.
WACE 20235 marksEthanol can be dehydrated to ethene or oxidised to ethanoic acid. (a) Write equations and state the conditions for each reaction. (b) Explain, in terms of the reaction type, why dehydration is classified as elimination and oxidation changes the functional group.Show worked answer β
A 5 mark answer needs both equations with conditions and the reasoning.
(a) Dehydration: , using concentrated sulfuric acid (or hot phosphoric acid catalyst) at high temperature.
Oxidation: (via ethanal), using acidified potassium dichromate, heated under reflux to take it all the way to the acid.
(b) Dehydration is an elimination because a small molecule (water) is removed from a single reactant and a C=C double bond forms, with no other molecule adding. Oxidation changes the functional group from a hydroxyl () to a carbonyl-containing acid () by removing hydrogen from the carbon and adding oxygen, so the class of compound is changed (alcohol to carboxylic acid).
Markers reward both equations with conditions, elimination defined by loss of water forming a double bond, and oxidation defined by the functional-group change.
