Alcohols: WACE Year 12 Chemistry
“Classify alcohols as primary, secondary or tertiary and describe their characteristic reactions including oxidation, dehydration and combustion”
Alcohols contain the hydroxyl group -OH. They are classified by how many carbon atoms are attached to the carbon bearing the -OH: primary (one), secondary (two) or tertiary (three). Primary alcohols oxidise to aldehydes then carboxylic acids, secondary alcohols oxidise to ketones, and tertiary alcohols resist oxidation. Alcohols also dehydrate to alkenes and burn in oxygen.
What this dot point is asking
An alcohol contains the hydroxyl functional group, -OH, attached to a carbon atom. The -OH group makes alcohols polar and able to hydrogen bond, and it is the reactive site for their characteristic reactions.
Classifying alcohols
Alcohols are classified by the number of carbon atoms bonded to the carbon that carries the -OH group:
- Primary (1 degree): the -OH carbon is attached to one other carbon (for example ethanol).
- Secondary (2 degrees): the -OH carbon is attached to two other carbons (for example propan-2-ol).
- Tertiary (3 degrees): the -OH carbon is attached to three other carbons (for example 2-methylpropan-2-ol).
The class of an alcohol determines what it oxidises to. Primary alcohols oxidise to aldehydes and then carboxylic acids; secondary alcohols oxidise to ketones; tertiary alcohols cannot be oxidised by acidified dichromate or permanganate because there is no hydrogen on the -OH carbon to remove.
Oxidation
Oxidation uses an oxidising agent such as acidified potassium dichromate (orange, turning green) or permanganate (purple, turning colourless).
- Primary: ethanol oxidises first to ethanal (an aldehyde), then with further oxidation to ethanoic acid (a carboxylic acid).
- Secondary: propan-2-ol oxidises to propanone (a ketone), which does not oxidise further easily.
- Tertiary: no reaction; the carbon bearing -OH has no hydrogen to lose.
The removal of hydrogen (or addition of oxygen) from the carbon bearing the -OH group, converting the C-OH into a C=O. It requires a hydrogen on that carbon, which tertiary alcohols lack.
Dehydration
Heating an alcohol with a suitable acid catalyst (such as concentrated sulfuric acid) removes a water molecule to form an alkene. This is an elimination reaction; for example ethanol dehydrates to ethene:
Combustion
Like all organic compounds, alcohols burn. Complete combustion in plentiful oxygen gives carbon dioxide and water and releases a large amount of energy, which is why ethanol is used as a fuel:
Question
An unknown alcohol is warmed with acidified potassium dichromate. The orange solution turns green, and the only organic product is a ketone. Classify the alcohol and explain.
Solution
The colour change from orange (dichromate) to green (chromium(III)) confirms oxidation has occurred, so the alcohol is not tertiary (tertiary alcohols give no reaction).
The single organic product is a ketone. Only a secondary alcohol oxidises to a ketone (a primary alcohol would give an aldehyde then a carboxylic acid). Therefore the unknown is a secondary alcohol, with the -OH carbon bonded to two other carbon atoms.
Reflux versus distillation in oxidation
A practical detail WACE rewards is controlling how far a primary alcohol oxidises. To stop at the aldehyde, the aldehyde is distilled off as it forms, because its boiling point is lower than the alcohol's and it escapes the mixture before it can be oxidised further. To go all the way to the carboxylic acid, the mixture is heated under reflux (vapours condense and return to the flask) with excess oxidising agent, so the aldehyde stays in contact with the dichromate and is oxidised completely. The same reagent therefore gives different products depending on the apparatus, which is a classic short-answer point.
Physical properties from the hydroxyl group
The group also explains the physical behaviour of alcohols. Because allows hydrogen bonding between molecules, alcohols have much higher boiling points than alkanes of similar molar mass and the smaller alcohols (methanol, ethanol, propanol) are fully miscible with water. As the carbon chain lengthens, the non-polar hydrocarbon part dominates and water solubility falls, so longer-chain alcohols behave more like hydrocarbons. This trend connects directly to the intermolecular-forces reasoning used throughout Unit 4.
Why this matters
Alcohols sit at the centre of organic synthesis: they can be made from alkenes (hydration) or haloalkanes (substitution), and converted into aldehydes, ketones, carboxylic acids, esters and alkenes. Their reactions are essential building blocks for the multi-step pathways examined in Unit 4.
The most common error is oxidising a tertiary alcohol; it has no hydrogen on the -OH carbon, so it does not react with dichromate or permanganate and the orange colour stays. Another is stopping primary alcohol oxidation at the aldehyde when conditions allow further oxidation to the carboxylic acid, or vice versa. Always state the class first, then predict the product.
Exam-style questions
Questions in the style of SCSA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.
WACE 2021-style6 marksThree bottles contain butan-1-ol, butan-2-ol and 2-methylpropan-2-ol, but the labels have come off. (a) Classify each alcohol. (b) Describe how acidified potassium dichromate could be used to distinguish them, stating the observation and organic product for each. (c) Write the equation for the complete combustion of butan-1-ol ().Show worked answer →
A 6 mark question rewards the classifications, the dichromate observations, and a balanced combustion equation.
(a) Butan-1-ol is primary (the carbon has one carbon attached), butan-2-ol is secondary (two carbons attached), and 2-methylpropan-2-ol is tertiary (three carbons attached).
(b) With warm acidified (orange):
- Primary butan-1-ol: orange to green; oxidised to butanal, then on further oxidation to butanoic acid.
- Secondary butan-2-ol: orange to green; oxidised to butanone (a ketone), no further reaction.
- Tertiary 2-methylpropan-2-ol: no colour change (stays orange); it is not oxidised.
So the bottle that does not change colour is the tertiary alcohol. The other two both turn green but the primary one can be distilled to a carboxylic acid; this difference is used to tell them apart.
(c) .
Markers reward the three classifications, the orange-to-green (or no change) observations with the correct products, and the balanced combustion equation.
WACE 2023-style5 marksEthanol can be dehydrated to ethene or oxidised to ethanoic acid. (a) Write equations and state the conditions for each reaction. (b) Explain, in terms of the reaction type, why dehydration is classified as elimination and oxidation changes the functional group.Show worked answer →
A 5 mark answer needs both equations with conditions and the reasoning.
(a) Dehydration: , using concentrated sulfuric acid (or hot phosphoric acid catalyst) at high temperature.
Oxidation: (via ethanal), using acidified potassium dichromate, heated under reflux to take it all the way to the acid.
(b) Dehydration is an elimination because a small molecule (water) is removed from a single reactant and a C=C double bond forms, with no other molecule adding. Oxidation changes the functional group from a hydroxyl () to a carbonyl-containing acid () by removing hydrogen from the carbon and adding oxygen, so the class of compound is changed (alcohol to carboxylic acid).
Markers reward both equations with conditions, elimination defined by loss of water forming a double bond, and oxidation defined by the functional-group change.