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TCE Chemistry Level 4 (CHM415115) deep dive: criteria 5 to 8 for the 2026 exam

TCEChemistryStudy guide20 min read

Revision deep dive for the four externally assessed criteria of TASC Chemistry Level 4: electrochemistry and corrosion, thermochemistry, kinetics, equilibrium and acids, organic and inorganic matter including spectroscopy and periodic trends, and quantitative problem solving, with worked examples and links to every TCE Chemistry dot point.

Jump to a section
  1. How this deep dive is organised
  2. Criterion 5: electrochemistry
  3. Criterion 6: thermochemistry, kinetics and equilibrium
  4. Criterion 7: properties and reactions of organic and inorganic matter
  5. Criterion 8: quantitative problems
  6. Common mistakes
  7. Check your knowledge

How this deep dive is organised

The TASC Chemistry Level 4 exam gives one rating for each of criteria 5 to 8, one section each. This guide follows the four criteria as the course document describes them and links every TCE Chemistry dot point on the site. Two site pages (buffers and solubility equilibria) go beyond the course document's list and are marked as background. For format and award rules, see the exam strategy guide.

Criterion 5: electrochemistry

Dot points: oxidation and reduction, balancing redox half-equations, electrochemistry, electrolysis and Faraday's laws, corrosion and its prevention.

  • Oxidation states: assign them (including hydrogen in metal hydrides, −1-1, and oxygen in peroxides, −1-1), identify what is oxidised and reduced, and rank oxidisers and reducers with the electrochemical series.
  • Half-equations in acidic solution: balance atoms, then O with H2O\text{H}_2\text{O}, H with H+\text{H}^+, and charge with electrons.
  • Galvanic cells: oxidation at the anode, reduction at the cathode, electrons through the external circuit from anode to cathode, the salt bridge maintaining electroneutrality, and cell diagrams with the anode on the left.
  • Electrolytic cells: predict products for molten salts and aqueous solutions (inert or reactive electrodes), including electrorefining and electroplating.
Oxidation state of manganese

Find the oxidation state of Mn in MnO4−\text{MnO}_4^- and in MnO2\text{MnO}_2, and decide which is the stronger oxidiser.

In MnO4−\text{MnO}_4^-: x+4(−2)=−1x + 4(-2) = -1, so x=+7x = +7. In MnO2\text{MnO}_2: x+2(−2)=0x + 2(-2) = 0, so x=+4x = +4.

Permanganate is the stronger oxidiser: with Mn in its highest oxidation state, it has the greatest tendency to gain electrons.

Corrosion: iron is oxidised at anodic sites (often stressed areas or where oxygen is scarce), and oxygen is reduced at cathodic sites where its concentration is highest; dissolved ions speed up the process. Rust is ionic, brittle and occupies more volume than steel. Prevention: paint, oil, polymer and metal coatings (noble or sacrificial), and cathodic protection with sacrificial anodes or an applied EMF.

Criterion 6: thermochemistry, kinetics and equilibrium

Dot points: enthalpy and thermochemistry, Hess's law and bond energies, collision theory and reaction rates, catalysts and reaction rate, chemical equilibrium and Le Chatelier, equilibrium constant calculations, acids, bases and pH, weak acids and Ka. Background: buffer solutions, solubility equilibria and Ksp.

  • Thermochemistry: bond breaking absorbs energy and bond forming releases it; draw enthalpy diagrams with activation energy; write thermochemical equations; use calorimetry, bond energies and Hess's law.
  • Kinetics: average rate is change in amount or concentration over time; collision theory explains the effects of concentration, surface area, temperature, the nature of the reactants and catalysts. A Maxwell-Boltzmann style distribution shows that a small temperature rise greatly increases the fraction of particles with energy above the activation energy.
  • Equilibrium: dynamic balance of forward and reverse rates; Le Chatelier's principle and its limitations; Kc calculations and the reaction quotient Q to predict direction.
pH of a weak acid

Find the pH of 0.10 mol L−1^{-1} ethanoic acid, Ka=1.8×10−5K_a = 1.8 \times 10^{-5}.

Ka=[H+][CH3COO−][CH3COOH]≈x20.10K_a = \dfrac{[\text{H}^+][\text{CH}_3\text{COO}^-]}{[\text{CH}_3\text{COOH}]} \approx \dfrac{x^2}{0.10}, so x=1.8×10−6≈1.34×10−3x = \sqrt{1.8 \times 10^{-6}} \approx 1.34 \times 10^{-3} mol L−1^{-1}.

pH=−log⁡(1.34×10−3)≈2.87\text{pH} = -\log(1.34 \times 10^{-3}) \approx 2.87. A strong monoprotic acid of the same concentration has pH 1.00, which is why the course notes that carboxylic acid solutions have a higher pH than strong acids of equal concentration.

Criterion 7: properties and reactions of organic and inorganic matter

Dot points: nomenclature and isomerism, organic families and reactions, reactions of alcohols, carboxylic acids and esters, polymers, analytical techniques, bonding and intermolecular forces.

  • Organic reactions: substitution of alkanes with halogens; addition to alkenes and alkynes (including asymmetric reagents such as hydrogen halides and steam, which can give isomeric products); complete and incomplete combustion; oxidation of primary alcohols to aldehydes (copper catalyst or limited dichromate) and then to carboxylic acids (stronger oxidisers such as permanganate), secondary alcohols to ketones, tertiary alcohols not oxidised; esterification and ester hydrolysis (including alkaline); addition polymers and polyesters.
  • Properties: hydrogen bonding raises boiling points of alcohols, amines and amides; polyalcohols boil much higher than simple alcohols; esters are insoluble and fragrant.
  • Analysis: mass spectra (molecular ion and fragments), infrared bands for functional groups, and X-ray crystallography, often combined.
  • Inorganic matter: gas properties and kinetic theory; the Bohr model; electron configurations with s, p and d subshells; ionisation energies; periodic trends in electronegativity, core charge, shielding, reactivity and atomic and ionic radii.
Explaining a periodic trend

Why does atomic radius decrease across period 3 from sodium to chlorine?

Across the period, protons are added to the nucleus while electrons are added to the same (third) shell. The core charge increases from +1 to +7 while shielding by inner electrons stays about the same, so the outer electrons are pulled closer to the nucleus and the radius decreases.

Criterion 8: quantitative problems

Dot points: stoichiometry and the mole, volumetric analysis calculations, acid-base titrations and curves, gas laws and molar volume, chemical synthesis.

The course document lists mass calculations, gravimetric analysis (precipitate mass, percentage purity and yield, water of crystallisation), primary standards and dilution, limiting reagents, acid-base and redox titrations, synthesis yield, and gas law calculations. It also states that calculations from criteria 5, 6 and 7 are examined here.

Faraday's law

A spoon is silver-plated with a current of 0.500 A for 20.0 minutes. Find the mass of silver deposited (F=96 500F = 96\,500 C mol−1^{-1}, M(Ag)=107.9M(\text{Ag}) = 107.9 g mol−1^{-1}).

Q=It=0.500×1200=600Q = It = 0.500 \times 1200 = 600 C. n(e−)=60096 500=6.22×10−3n(e^-) = \dfrac{600}{96\,500} = 6.22 \times 10^{-3} mol.

Ag++e−→Ag\text{Ag}^+ + e^- \rightarrow \text{Ag}, so n(Ag)=6.22×10−3n(\text{Ag}) = 6.22 \times 10^{-3} mol and m=6.22×10−3×107.9≈0.671m = 6.22 \times 10^{-3} \times 107.9 \approx 0.671 g.

Water of crystallisation

Heating 2.50 g of hydrated copper(II) sulfate, CuSO4⋅xH2O\text{CuSO}_4 \cdot x\text{H}_2\text{O}, leaves 1.60 g of anhydrous CuSO4\text{CuSO}_4. Find xx.

Mass of water lost =0.90= 0.90 g, so n(H2O)=0.9018.02=0.0499n(\text{H}_2\text{O}) = \dfrac{0.90}{18.02} = 0.0499 mol. n(CuSO4)=1.60159.6=0.0100n(\text{CuSO}_4) = \dfrac{1.60}{159.6} = 0.0100 mol.

Ratio =0.04990.0100≈5= \dfrac{0.0499}{0.0100} \approx 5, so the formula is CuSO4⋅5H2O\text{CuSO}_4 \cdot 5\text{H}_2\text{O}.

Common mistakes

Where criterion ratings slip
  • Criterion 5: forgetting that sulfate and nitrate cannot be oxidised further, so water is oxidised at the anode instead.
  • Criterion 6: saying a catalyst changes the equilibrium position, or that Kc changes with concentration.
  • Criterion 7: stopping the oxidation of a primary alcohol at the aldehyde when a strong oxidiser in excess is used.
  • Criterion 8: skipping the limiting reagent check, or rounding intermediate values too early.

Check your knowledge

  1. What is the oxidation state of hydrogen in sodium hydride, NaH? (Answer: −1-1.)
  2. Reversing a reaction with ΔH=−92\Delta H = -92 kJ gives what enthalpy change? (Answer: +92+92 kJ.)
  3. What is the molar volume of an ideal gas at SLC according to the information sheet? (Answer: 24.5 L mol−1^{-1}.)

Then try the criteria 5 to 8 quiz.

Sources & how we know this

  • chemistry
  • tce
  • tce-chemistry
  • electrochemistry
  • thermochemistry
  • equilibrium
  • organic-chemistry
  • stoichiometry
  • year-12
  • 2026
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