Nomenclature and isomerism: TCE Chemistry (Tasmania)
“Apply IUPAC nomenclature and identify structural and stereo isomers of organic compounds.”
IUPAC naming uses a stem for the longest carbon chain containing the main functional group, a suffix for that group, and prefixes with locants for branches and other substituents. Isomers share a molecular formula but differ in connectivity (structural isomers) or in the spatial arrangement around a double bond (cis-trans isomers).
What this dot point is asking
TASC expects you to name organic compounds systematically and to identify and draw their structural and geometric isomers.
IUPAC naming rules
Build the name in three parts:
- Stem: the number of carbons in the longest chain that contains the main functional group (meth, eth, prop, but, pent, hex, and so on).
- Suffix: the main functional group (, , , , , , , , ).
- Prefixes: branches and other substituents, each with a locant (number) showing its position.
Number the chain from the end that gives the main functional group the lowest locant. List substituents alphabetically, and use di, tri and tetra for repeated groups (these multiplying prefixes are ignored when alphabetising).
Find the longest chain and suffix
Name . The longest chain bearing the has four carbons, so the stem is but and the suffix is .
Number for the lowest locant
Number from the end so the principal group gets the lowest locant: the is on carbon and a methyl branch is on carbon .
Assemble the name
Combine the prefix, stem and suffix: 3-methylbutan-1-ol.
Structural isomerism
Compounds with the same molecular formula but different connectivity. They divide into chain isomers (different carbon skeletons), positional isomers (the same group in a different place) and functional-group isomers (the same atoms forming a different functional group, such as an alcohol and an ether).
For example, exists as butane (straight chain) and 2-methylpropane (branched). Chain branching lowers the boiling point because branched molecules pack less closely, so the dispersion forces between them are weaker. Functional-group isomerism is why can be either ethanol (an alcohol) or methoxymethane (an ether), with very different properties.
Cis-trans (geometric) isomerism
A carbon-carbon double bond cannot rotate, so the groups attached to it are fixed in position. When each double-bond carbon carries two different groups, two arrangements exist: cis (matching groups on the same side) and trans (on opposite sides). These geometric isomers can have different physical properties, such as melting and boiling points, because their shapes and polarities differ; cis-2-butene, for instance, is slightly polar while trans-2-butene is non-polar.
Geometric (cis-trans) isomerism requires a double bond (which blocks rotation) and two different groups on each carbon of that bond. Single bonds rotate freely, so they do not give geometric isomers, and a double bond with two identical groups on one carbon shows no cis-trans isomerism.
Priority of functional groups
When a molecule contains more than one functional group, only one is the principal group (named as the suffix) and the others become prefixes. A simplified priority order, highest first, is: carboxylic acid, then ester, then aldehyde, then ketone, then alcohol, then amine. For example, a compound containing both a hydroxyl and a carboxyl group is named as a hydroxy-substituted acid (the acid takes the suffix), as in 2-hydroxypropanoic acid (lactic acid). Getting the priority right ensures the chain is numbered to give the most senior group the lowest locant.
How isomerism affects properties
Isomers can behave very differently despite sharing a molecular formula. Chain isomers differ in boiling point because branching changes how closely molecules pack and therefore the strength of dispersion forces. Positional and functional-group isomers can differ in chemical reactivity: a primary alcohol and a secondary alcohol of the same formula give different oxidation products, and an alcohol and its isomeric ether differ enormously in boiling point because only the alcohol can hydrogen bond. Recognising the isomer present is therefore essential before predicting reactions, and analytical techniques such as NMR and mass spectrometry are used to tell isomers apart.
A common error is to number the carbon chain to give a branch the lowest locant when the main functional group should take priority. Always give the principal functional group the lowest possible number first, then minimise the substituent locants. A second slip is forgetting to choose the longest chain that contains the functional group, which can change both the stem and the locants.
In the exam, identify and number the longest chain through the main functional group, name substituents alphabetically with locants, and check for chain, positional, functional-group and geometric isomers whenever you are asked for isomers of a formula.
Exam-style questions
Questions in the style of TASC exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.
Practice4 marksPropene reacts with hydrogen chloride. (a) Write a balanced equation for the addition of to propene. (b) Identify and name the two structural isomers of chloropropane that could form, and state how they are related.Show worked answer →
(a) Propene undergoes addition across the double bond: . (2 marks)
(b) The two isomers are 1-chloropropane, (chlorine on an end carbon), and 2-chloropropane, (chlorine on the middle carbon). They share the molecular formula but differ in the position of the chlorine, so they are positional structural isomers. (2 marks)
Practice4 marksTwo isomers of , A and B, both immediately decolourise bromine water. With steam ( catalyst), A gives two alcohols (one oxidisable to an aldehyde, one to a ketone) while B gives a single alcohol. (a) State what the bromine result shows. (b) Name and give the structure of A and of B, with reasoning.Show worked answer →
(a) Both decolourise bromine immediately, showing both contain a carbon-carbon double bond (they are alkenes undergoing addition). (1 mark)
(b) A gives two different hydration products because its double bond is unsymmetrical, so water can add either way, giving a primary alcohol (oxidised to an aldehyde) and a secondary alcohol (oxidised to a ketone): A is but-1-ene, . (2 marks)
B gives only one hydration product, consistent with the symmetrical but-2-ene, , where addition either way gives the same secondary alcohol (butan-2-ol). (1 mark)