Why does an object moving at constant speed in a circle still accelerate, and what force keeps it on the circular path?
Describe uniform circular motion using centripetal acceleration and force, relating them to speed, radius and period.
Why circular motion at constant speed is accelerated motion, how centripetal acceleration and force point toward the centre, and how to relate them to speed, radius and period.
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What this dot point is asking
You need to explain why circular motion is accelerated even at constant speed, identify the centripetal force in a given situation, and calculate centripetal acceleration and force using speed, radius and period.
Why constant speed still means accelerating
Velocity is a vector. In circular motion the speed (the size of the velocity) is constant, but the direction is continuously changing, always tangent to the circle. A changing velocity is an acceleration, so the object is accelerating even though it is not speeding up or slowing down.
This acceleration points toward the centre of the circle. It is called centripetal ("centre-seeking") acceleration.
Period, frequency and speed
For an object completing circles, the period is the time for one revolution and the frequency . The speed is the circumference divided by the period:
Substituting into gives an equivalent form in terms of period:
Identifying the centripetal force
The centripetal force is whatever real force (or combination) provides the inward net force:
- A ball on a string: the tension points inward.
- A car turning on a flat road: friction between tyres and road.
- A satellite orbiting Earth: gravity.
- A passenger on a fairground ride: the normal force from the seat or wall.
If the required inward force is not available (e.g. not enough friction), the object cannot follow the circle and moves off tangentially in a straight line.
Banked tracks
On a banked curve the road is tilted so the normal force gains a horizontal component pointing toward the centre. This horizontal component supplies part or all of the centripetal force, reducing the reliance on friction. At the design speed, the horizontal component of the normal force alone supplies the entire , so the curve can be taken safely even on a frictionless (icy) surface.
The "centrifugal" misconception
There is no outward force on the object. In the rotating frame of a passenger it feels as if they are pushed outward, but in an inertial frame the only forces are real and the net force is inward. What the passenger feels is their own inertia (tendency to go straight) resisting the inward push of the seat.
How SACE assesses this
SACE Stage 2 circular-motion questions usually give two of speed, radius and period and ask for the centripetal acceleration or force, often in a real context such as a turbine blade, a fairground ride or a car on a bend. The dependable approach is to identify which real force provides the centripetal force (friction, tension, gravity or the normal force), then equate it to . Where the period is involved, convert between and with first. Several "show that" parts ask you to verify a period or acceleration, so quote the formula, substitute with units, and arrive visibly at the printed value rather than just stating it.
Exam-style practice questions
Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
SACE 20254 marksA wind turbine has three blades that move in a circular path. Each blade is long and the tips move at a constant speed of . (a) Show that the period of rotation of the blades is . (b) Calculate the magnitude of the acceleration of the tip of a blade.Show worked answer →
The blade tip moves in a circle of radius at constant speed .
(a) For circular motion , so
(b) The centripetal acceleration is
This acceleration points toward the centre (the hub) even though the speed is constant, because the velocity direction changes continuously.
SACE 20233 marksA racing car travels along a circular section of track of radius at a constant speed of . The friction force between the tyres and road, which provides the circular motion, has magnitude . Determine the mass of the car.Show worked answer →
Friction supplies the centripetal force, so .
Rearrange for mass: .
1 mark for identifying friction as the centripetal force, 1 mark for the rearrangement, 1 mark for the answer of about (or ).
