Skip to main content
SAPhysicsSyllabus dot point

How does the gravitational attraction between two masses depend on their masses and separation?

Apply Newton's law of universal gravitation and the concept of gravitational field strength to interactions between masses.

Newton's inverse-square law of gravitation, how gravitational force depends on mass and separation, and the meaning of gravitational field strength, with worked examples.

Generated by Claude Opus 4.78 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The law
  3. Gravitational field strength
  4. Why it matters

What this dot point is asking

You need to apply Newton's law of universal gravitation to calculate the attractive force between two masses, understand its inverse-square dependence, and relate it to gravitational field strength.

The law

Key features:

  • The force is always attractive and acts along the line joining the two centres.
  • It is mutual: by Newton's third law each mass pulls the other with the same magnitude, regardless of how different the masses are.
  • It follows an inverse-square law: doubling the separation reduces the force to a quarter; tripling it reduces it to a ninth.
  • It is directly proportional to each mass: doubling one mass doubles the force.

For spherical bodies such as planets, rr is measured from centre to centre, so for an object on Earth's surface rr is the radius of the Earth.

Gravitational field strength

A mass creates a gravitational field around it. The field strength gg at a point is the force per unit mass placed there.

This is why g9.8 N kg1g \approx 9.8 \text{ N kg}^{-1} at Earth's surface, and falls off as you move to higher altitude or orbit.

Why it matters

This single law explains the fall of an apple and the orbit of the Moon - the same gravitational interaction governs both. Combined with the centripetal force requirement, it underpins satellite and planetary orbits (covered in the next dot point).

Exam-style practice questions

Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2023 SACE Stage 24 marksTitan has a mass of 1.35 x 10^23 kg and Saturn has a mass of 5.68 x 10^26 kg. (a) Calculate the magnitude of the gravitational forces between Titan and Saturn when their centres are separated by 1.24 x 10^9 m. (b) Explain how gravitational forces are consistent with Newton's Third Law of Motion.
Show worked answer →

(a) Apply Newton's law of universal gravitation, F = G m1 m2 / r squared, with G = 6.67 x 10^-11 N m2 kg-2.

F = (6.67 x 10^-11)(1.35 x 10^23)(5.68 x 10^26) / (1.24 x 10^9) squared
= (5.114 x 10^39) / (1.538 x 10^18) = 3.33 x 10^21 N. (2 marks)

(b) Newton's Third Law states that forces occur in equal and opposite pairs. Titan exerts a gravitational pull on Saturn, and Saturn exerts an equal magnitude force on Titan in the opposite direction. The G m1 m2 / r squared expression is symmetric in the two masses, so the force on each body has the same magnitude regardless of the difference in their masses. (2 marks)

2024 SACE Stage 22 marksTethys is a moon of Saturn with a mass of 6.17 x 10^20 kg, orbiting Saturn (mass 5.65 x 10^26 kg) at an orbital radius of 2.95 x 10^8 m. Calculate the magnitude of the gravitational forces between Tethys and Saturn.
Show worked answer →

Use Newton's law of universal gravitation: F = G m1 m2 / r squared, with G = 6.67 x 10^-11 N m2 kg-2.

F = (6.67 x 10^-11)(6.17 x 10^20)(5.65 x 10^26) / (2.95 x 10^8) squared.

Numerator = (6.67 x 10^-11)(6.17 x 10^20)(5.65 x 10^26) = 2.325 x 10^37.
Denominator = (2.95 x 10^8) squared = 8.70 x 10^16.

F = 2.325 x 10^37 / 8.70 x 10^16 = 2.67 x 10^20 N. (1 mark for correct substitution, 1 mark for the answer of about 2.67 x 10^20 N.)