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How do time and length change for observers in relative motion at high speed?

Apply special relativity to time dilation and length contraction at high relative speeds

A focused answer to the WACE Year 12 Physics Unit 4 content point on special relativity. Einstein's two postulates, the Lorentz factor, time dilation and length contraction, the proper-frame quantities, and evidence from fast-moving muons.

Reviewed by: AI editorial process; not yet individually human-reviewed

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What this dot point is asking

WACE wants you to state the postulates, use the Lorentz factor, and apply time dilation and length contraction, identifying which quantity is the proper one. These effects are negligible at everyday speeds and only matter near the speed of light.

The two postulates

Einstein built special relativity on two ideas. First, the principle of relativity: the laws of physics are identical in all inertial (non-accelerating) frames, so no experiment can tell you that you are "really" moving. Second, the constancy of light speed: light travels at cc in a vacuum for every observer, regardless of the motion of the source or observer. The strange consequences follow from taking these two seriously together.

The Lorentz factor

Both effects are governed by

γ=11v2c2.\gamma=\frac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}.

At low speeds γ1\gamma\approx1 and nothing measurable changes. As vv approaches cc, γ\gamma grows without bound, which is why effects become extreme only near light speed and why no massive object can reach cc.

Time dilation

A clock measures the shortest time, the proper time t0t_0, in the frame where it is at rest. An observer moving relative to that clock measures a longer time

t=γt0.t=\gamma t_0.

So a moving clock appears to run slow. The effect is reciprocal: each observer sees the other's clock running slow, because each considers themselves at rest.

Length contraction

An object has its greatest length, the proper length L0L_0, in its own rest frame. An observer past whom it moves measures a contracted length along the direction of motion

L=L0γ.L=\frac{L_0}{\gamma}.

Only the dimension along the motion contracts; dimensions perpendicular to the motion are unchanged.

Evidence from muons

Muons created high in the atmosphere have a short half-life and should mostly decay before reaching the ground at their speed. Yet far more arrive than classical physics predicts. From the ground frame, the muons' internal clocks run slow (time dilation), so they live longer. From the muon frame, the atmosphere is thin (length contraction), so there is less distance to cross. Both views agree the muons reach the surface, confirming the theory.

When relativistic effects matter

A useful skill is judging when relativity is needed at all. The Lorentz factor stays within 1%1\% of 11 for speeds below about 0.14c0.14c, which is still over 4×107 m s14\times10^{7}\ \text{m s}^{-1}, far faster than any everyday object. This is why time dilation and length contraction are completely undetectable for cars, planes or even satellites in ordinary problems, and Newtonian physics is an excellent approximation. The effects only become significant for particles in accelerators, cosmic-ray muons, and precision systems such as GPS satellites, where uncorrected relativistic clock differences would accumulate into navigation errors of kilometres per day. Being able to say why a given scenario does or does not need relativity, by estimating v/cv/c, is a frequent conceptual mark.

Spotting the proper quantity

The proper time is measured by a clock present at both events (the moving object's clock); the proper length is measured in the object's rest frame. Time dilation multiplies the proper time by γ\gamma; length contraction divides the proper length by γ\gamma. Choosing the wrong frame for the proper value inverts the result.

Exam-style practice questions

Practice questions written in the style of SCSA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WACE 20227 marksA spacecraft passes Earth at v=0.90cv=0.90c. In the spacecraft's frame the journey to a distant star takes 6.06.0 years. (a) Calculate the Lorentz factor. (b) Calculate the time for the journey as measured from Earth. (c) The star is measured from Earth to be 12.412.4 light-years away; calculate the distance as measured by the spacecraft crew.
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A 7 mark calculation rewards the Lorentz factor, time dilation and length contraction with the correct proper quantities.

(a) Lorentz factor
γ=11(0.90)2=110.81=10.19=2.29\gamma=\dfrac{1}{\sqrt{1-(0.90)^2}}=\dfrac{1}{\sqrt{1-0.81}}=\dfrac{1}{\sqrt{0.19}}=2.29.
(b) Earth time
The ship clock measures the proper time t0=6.0t_0=6.0 years (present at both events), so Earth measures t=γt0=2.29×6.0=13.8 yearst=\gamma t_0=2.29\times6.0=13.8\ \text{years}.
(c) Distance for the crew
The Earth-measured distance is the proper length L0=12.4L_0=12.4 light-years, so the crew measure the contracted distance L=L0γ=12.42.29=5.4 light-yearsL=\dfrac{L_0}{\gamma}=\dfrac{12.4}{2.29}=5.4\ \text{light-years}.

Markers reward γ=2.29\gamma=2.29, multiplying the proper time by γ\gamma for Earth time, and dividing the proper length by γ\gamma for the contracted distance.

WACE 20215 marksExplain how the detection of large numbers of muons at the Earth's surface provides evidence for special relativity, giving the explanation from both the ground frame and the muon frame.
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A 5 mark explanation needs both frames giving the same outcome.

The puzzle
Muons are created high in the atmosphere and have a short half-life. At their speed, classical physics predicts almost all should decay before reaching the ground, yet far more are detected at the surface than expected.
Ground frame (time dilation)
From the ground, the fast-moving muons' internal clocks run slow, t=γt0t=\gamma t_0, so their effective lifetime is extended and many survive the trip down.
Muon frame (length contraction)
From the muon's own frame, it is at rest and the atmosphere rushes past, contracted to a much shorter thickness L=L0/γL=L_0/\gamma. The reduced distance means the muon reaches the surface within its normal lifetime.
Agreement
Both frames predict the muons reach the surface, and the measured numbers match the relativistic prediction, confirming time dilation and length contraction.

Markers reward the short-lifetime puzzle, time dilation extending lifetime in the ground frame, length contraction shortening the distance in the muon frame, and the two frames agreeing.

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