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How do different patterns of inheritance produce predictable ratios of offspring?

Apply patterns of inheritance including dihybrid, codominance, multiple alleles, sex linkage and polygenic inheritance

A focused answer to the WACE Year 12 Biology dot point on patterns of inheritance. Covers dihybrid crosses, codominance and incomplete dominance, multiple alleles such as ABO blood groups, sex linkage and polygenic inheritance with Australian examples.

Reviewed by: AI editorial process; not yet individually human-reviewed

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What this dot point is asking

SCSA wants you to recognise which pattern a cross follows, predict genotype and phenotype ratios using Punnett squares, and explain why some traits do not follow simple Mendelian dominance. A strong answer chooses the right symbols and links the pattern to the underlying allele behaviour.

Dihybrid inheritance

A dihybrid cross follows two genes at once. When an individual heterozygous for both genes is crossed with another (for example RrYy by RrYy), the offspring show a characteristic 9:3:3:1 phenotype ratio, provided the two genes assort independently. This ratio reflects independent assortment in meiosis, where the alleles of one gene separate independently of the other.

Codominance and incomplete dominance

These describe what happens when neither allele is fully dominant.

  • Codominance: both alleles are expressed fully and separately in the heterozygote. In cattle, a red animal crossed with a white animal can give roan offspring showing both red and white hairs.
  • Incomplete dominance: the heterozygote shows an intermediate, blended phenotype, such as a pink flower from red and white parents.

Multiple alleles: ABO blood groups

A gene can have more than two alleles in a population, even though any individual carries only two. The human ABO blood group is the classic example: the alleles are IAI^A, IBI^B and ii. The IAI^A and IBI^B alleles are codominant with each other, and both are dominant over ii. This gives four blood groups (A, B, AB and O) from three alleles.

Sex linkage

Genes on the sex chromosomes, especially the X chromosome, show sex-linked inheritance. Because males are XY and have only one X, a single recessive allele on the X is expressed in males, while females (XX) need two copies. This is why X-linked recessive conditions such as red-green colour blindness and haemophilia are far more common in males.

Polygenic inheritance

Some traits are controlled by many genes acting together, each adding a small effect. The result is continuous variation, a smooth range rather than distinct categories. Human height and skin colour are polygenic, which is why they form a bell-shaped distribution in a population rather than falling into a few discrete classes.

Choosing the right pattern

The key skill is reading a problem and identifying the pattern: a 3:1 ratio suggests simple dominance, 9:3:3:1 suggests a dihybrid cross, three phenotypes from a cross of two heterozygotes suggests incomplete dominance or codominance, a trait far more common in males suggests sex linkage, and a continuous range suggests polygenic inheritance. Once the pattern is clear, the correct symbols and Punnett square follow.

Exam-style practice questions

Practice questions written in the style of SCSA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

WACE 20227 marksHuman ABO blood group is controlled by three alleles: IAI^A and IBI^B are codominant and both are dominant over ii. A woman with blood group AB has children with a man with blood group O. Using a Punnett square, determine the possible blood groups of their children and their expected ratio, and explain why no child can be group AB or O.
Show worked answer →

A 7 mark answer needs the genotypes, the cross and the reasoning.

Parental genotypes
Group AB is IAIBI^A I^B. Group O is iiii (the only genotype giving O).
Gametes
The AB parent makes IAI^A and IBI^B gametes; the O parent makes only ii gametes.
Punnett square outcome
Offspring are IAiI^A i and IBiI^B i, in a 1:11 : 1 ratio.
Phenotypes
IAiI^A i is group A; IBiI^B i is group B. So children are 50%50\% group A and 50%50\% group B.
Why not AB or O
A child could only be AB by inheriting both IAI^A and IBI^B, but the O parent can only pass ii. A child could only be O (iiii) by inheriting ii from both parents, but the AB parent has no ii allele to pass.

Markers reward correct parental genotypes, the 1:11 : 1 A to B ratio and the explanation that the O parent contributes only ii.

WACE 20245 marksExplain the difference between codominance and incomplete dominance, giving an example of each, and explain why polygenic traits such as human height show continuous variation.
Show worked answer →

A 5 mark answer needs both distinctions plus the polygenic reasoning.

Codominance
Both alleles are fully and separately expressed in the heterozygote. Example: roan cattle, where a heterozygote shows both red and white hairs (both visible, not blended).
Incomplete dominance
The heterozygote shows a blended, intermediate phenotype. Example: a pink flower produced from red and white parents.
Polygenic variation
A polygenic trait is controlled by many genes, each adding a small effect. The many genes combine with environmental influence to produce a smooth range of phenotypes (a bell-shaped distribution) rather than a few discrete classes, which is why human height varies continuously.

Markers reward the both-visible versus blended distinction with examples and the many-small-effects reasoning for continuous variation.

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