How does splitting a rational function into simpler fractions make it integrable?
Decompose rational functions into partial fractions and use the decomposition to integrate them.
Decomposing a proper rational function into partial fractions over linear factors, finding the unknown constants, and integrating the pieces to logarithms.
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What this dot point is asking
You need to decompose rational functions into partial fractions and use the decomposition to integrate them.
When and how to decompose
Partial fractions apply to a proper rational function (numerator degree less than denominator degree). If the function is improper, do polynomial division first and decompose the remaining proper part.
Finding the constants
Two reliable methods: substitute strategic -values (the cover-up idea), or expand and equate coefficients of like powers.
Integrating the pieces
Each integrates to , using . So once decomposed, the integral is a sum of logarithms.
Improper rational functions
If the numerator degree is at least the denominator degree, divide first. For instance is improper; dividing gives , and only the proper remainder is decomposed.
Exam-style practice questions
Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2017 SACE Stage 21 marksShow that 1/(x-2) - 1/(x+3) = 5/((x-2)(x+3)).Show worked answer β
Combine the two fractions on the left over the common denominator (x-2)(x+3):
1/(x-2) - 1/(x+3) = [(x+3) - (x-2)] / ((x-2)(x+3)).
Simplify the numerator: (x+3) - (x-2) = x + 3 - x + 2 = 5.
So 1/(x-2) - 1/(x+3) = 5/((x-2)(x+3)), as required. This is the partial-fraction decomposition of 5/((x-2)(x+3)) read in reverse. [1 mark]
2025 SACE Stage 22 marksShow that 1/((X-8)(X-4)) = (1/4)(1/(X-8) - 1/(X-4)).Show worked answer β
Decompose 1/((X-8)(X-4)) = A/(X-8) + B/(X-4). Multiplying through by (X-8)(X-4) gives 1 = A(X-4) + B(X-8). [1 mark]
Use convenient values of X:
Let X = 8: 1 = A(8-4) + B(0) = 4A, so A = 1/4.
Let X = 4: 1 = A(0) + B(4-8) = -4B, so B = -1/4.
Therefore 1/((X-8)(X-4)) = (1/4)/(X-8) - (1/4)/(X-4) = (1/4)(1/(X-8) - 1/(X-4)), as required. [1 mark]