Sample proportions and confidence intervals: QCE Maths Methods Unit 4
“Apply the sampling distribution of the sample proportion (mean , standard deviation ) and construct approximate confidence intervals for a population proportion”
The sample proportion has mean and SD , and for large (with and ) is approximately normal; an approximate confidence interval for the population proportion is with for the 90, 95, 99 percent levels, interpreted as the long-run procedure containing the true in approximately of repeated samples.
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What this dot point is asking
QCAA wants you to treat the sample proportion as a random variable, apply the normal approximation to its sampling distribution, construct confidence intervals for a population proportion, and interpret the interval correctly. The dot point bridges Unit 3 binomial probability with Unit 4 statistical inference, and is heavily examined in PSMT and EA.
Sample proportion
If a population has true proportion of "successes" and a random sample of is drawn with successes, the sample proportion is:
Because is random, is a random variable: it varies from sample to sample.
Sampling distribution of
Mean. . The sample proportion is an unbiased estimator of .
Standard deviation. .
Two takeaways:
- SD falls as : quadruple to halve SD.
- SD is maximised at ; minimised at or .
Normal approximation
For large :
Conditions for the approximation (QCAA convention):
When these conditions hold, is approximately normal with mean and SD . Standardise via to compute probabilities.
Confidence intervals
A confidence interval for a population proportion combines:
- The point estimate (centre).
- The standard error: (using in place of unknown ).
- The critical value for the confidence level.
The formula:
The margin of error is .
Standard values
| Level | |
|---|---|
| 90% | 1.6449 (round to 1.645) |
| 95% | 1.9600 (round to 1.96) |
| 99% | 2.5758 (round to 2.58) |
Interpretation
A confidence interval has the long-run interpretation:
Approximately of intervals constructed by this procedure across repeated samples would contain the true population proportion.
This is NOT:
- "There is a probability that is in this interval." (Once the interval is constructed, either is or is not in it.)
- " of the population have proportions in this interval." (The interval is about the parameter, not about individuals.)
The correct language refers to the long-run success rate of the procedure.
Sample size design
To achieve a margin of error at most at confidence:
If is unknown in advance, use (worst case) for a conservative design.
Always round up to the next integer (cannot sample a fractional person).
A study estimates the proportion of adults who exercise daily. A random sample of adults gives 120 who do.
.
SE: .
For 95 percent: . Margin: .
CI: .
Interpretation: approximately 95 percent of intervals constructed by this procedure would contain the true population proportion of adults who exercise daily.
Trade-offs
Confidence vs precision. Higher confidence (99 percent) requires a wider interval. Lower confidence (90 percent) gives a narrower interval. To improve both, increase .
Sample size economics. Doubling reduces SE by a factor of . Quadrupling halves SE. Diminishing returns above for opinion polling.
When the normal approximation fails
For very small samples or proportions near 0 or 1, the approximation can be poor. QCAA conventions ( and ) ensure validity. Outside these conditions, an exact (binomial-based) interval would be needed, beyond Methods scope.
- Wrong for the level
- 1.96 for 95 percent; 1.645 for 90 percent. Mixing them up gives wrong widths.
- Probability misinterpretation
- "The probability is in this interval" is wrong. Use long-run-procedure language.
- Sample size not rounded up
- becomes , not 384.
- vs in formulas
- In the sampling distribution SD: use (when known). In the CI standard error: use (when unknown).
- Forgetting worst-case
- When no prior estimate of exists for sample-size design, use to maximise for the most conservative .
Exam-style questions
Questions in the style of QCAA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.
Practice5 marksA poll of 600 voters found 354 supported candidate X. (a) Compute a 95 percent confidence interval for the true proportion. (b) Interpret the interval. (c) Find the smallest sample size needed to achieve a 95 percent confidence interval of half-width 0.02, assuming the true proportion is around 0.5.Show worked answer →
(a) Confidence interval.
.
SE: .
for 95 percent.
Margin: .
CI: , approximately .
(b) Interpretation. If many similar samples of 600 voters were drawn and 95 percent confidence intervals were constructed from each, approximately 95 percent of these intervals would contain the true population proportion of voters supporting candidate X. (Avoid: "there is a 95 percent probability the true proportion is in this interval", which is incorrect.)
(c) Sample size. Margin: . With worst-case :
.
Smallest .
Markers reward correct SE formula, correct for 95 percent, the correct interpretation language, and rounding up to integer for sample size.