Unit 2: Calculus

QLDMath MethodsSyllabus dot point

Topic 2: Trigonometric functions

Sketch and analyse graphs of $y = a \sin(b(x - h)) + k$ and $y = a \cos(b(x - h)) + k$, identifying amplitude, period, phase shift and vertical translation

A focused answer to the QCE Math Methods Unit 2 dot point on trig graphs. Sketches $y = \sin x$ and $y = \cos x$, identifies amplitude $|a|$, period $2\pi/b$, horizontal phase shift $h$ and vertical translation $k$ in the transformed forms, and works the QCAA-style modelling problem with periodic temperature.

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What this dot point is asking

QCAA wants you to sketch and analyse transformed sine and cosine graphs, identifying the four key parameters (amplitude, period, phase shift, vertical translation) and using them to model periodic phenomena like tides, temperatures or pendulum displacement.

The parent functions y=sinxy = \sin x and IMATH_1

For sinx\sin x:

  • Domain: all real xx.
  • Range: [1,1][-1, 1].
  • Period: 2π2\pi.
  • Amplitude: 11.
  • Zeros at x=nπx = n\pi for integer nn.
  • Maximum 11 at x=π/2+2nπx = \pi/2 + 2n\pi. Minimum 1-1 at x=3π/2+2nπx = 3\pi/2 + 2n\pi.

For cosx\cos x:

  • Same domain, range, period, amplitude.
  • Zeros at x=π/2+nπx = \pi/2 + n\pi.
  • Maximum 11 at x=2nπx = 2n\pi. Minimum 1-1 at x=(2n+1)πx = (2n+1)\pi.

cosx=sin(x+π/2)\cos x = \sin(x + \pi/2), so the cosine graph is the sine graph shifted left by π/2\pi/2.

The transformed form IMATH_21

Each parameter has a distinct effect.

  • IMATH_22 : amplitude. Vertical dilation. Range becomes [ka,k+a][k - |a|, k + |a|]. If a<0a < 0, the graph is reflected vertically.
  • IMATH_25 : angular frequency. Period =2π/b= 2\pi / |b|. Larger b|b| compresses the graph horizontally.
  • IMATH_28 : horizontal phase shift. Graph moves hh units right (if h>0h > 0).
  • IMATH_31 : vertical translation. Centre line moves to y=ky = k.

The same parameters apply to y=acos(b(xh))+ky = a \cos(b(x - h)) + k.

Key features for sketching

For y=asin(b(xh))+ky = a \sin(b(x-h)) + k:

  • Centre line: y=ky = k.
  • Maximum: y=k+ay = k + |a|.
  • Minimum: y=kay = k - |a|.
  • Period: 2π/b2\pi / |b|.
  • A complete cycle goes: centre, max, centre, min, centre.
  • First zero of the parent sine occurs at x=hx = h.

For cosine, replace "centre" first with "maximum" first.

Worked example

Sketch y=3cos(2(xπ/4))+5y = -3 \cos(2(x - \pi/4)) + 5.

Parameters: a=3a = -3, b=2b = 2, h=π/4h = \pi/4, k=5k = 5.

  • Amplitude 33, range [2,8][2, 8].
  • Period 2π/2=π2\pi / 2 = \pi.
  • Phase shift: π/4\pi/4 right.
  • Reflection (because a<0a < 0): the cosine starts at a minimum at x=π/4x = \pi/4 instead of a maximum.

Key points within one period:

  • IMATH_51 minimum.
  • IMATH_52 centre line crossing (rising).
  • IMATH_53 maximum.
  • IMATH_54 centre line crossing (falling).
  • IMATH_55 next minimum.

Periodic modelling

Worded scenarios (tides, temperature, alternating current) give the maximum, minimum and the time of one extremum. From those:

  • IMATH_56 = (max + min) / 2 (centre line).
  • IMATH_57 = (max - min) / 2 (amplitude).
  • IMATH_58 period.
  • IMATH_59 = time at which the sine starts at zero rising, or the cosine starts at maximum.

Common traps

Confusing bb with the period. Period is 2π/b2\pi / b, not bb itself.

Forgetting that hh shifts in the same direction as its sign. sin(2(xπ/4))\sin(2(x - \pi/4)) shifts right by π/4\pi/4, not left.

Missing the reflection when a<0a < 0. Negative aa flips the graph; max becomes min and vice versa.

Reading the model in degrees by accident. QCAA Math Methods always uses radians.

In one sentence

For y=asin(b(xh))+ky = a \sin(b(x-h)) + k and y=acos(b(xh))+ky = a \cos(b(x-h)) + k, the amplitude is a|a|, the period is 2π/b2\pi/|b|, the phase shift is hh (right if positive), and the centre line is y=ky = k, with the range [ka,k+a][k - |a|, k + |a|].

Past exam questions, worked

Real questions from past QCAA papers on this dot point, with our answer explainer.

Year 11 SAC5 marksThe temperature in a town is modelled by $T(t) = 6 \sin(\pi t / 12) + 18$, where $T$ is in degrees Celsius and $t$ is hours after $6$ am. Find (a) the amplitude, (b) the period, (c) the maximum and minimum temperatures, and (d) the temperature at $3$ pm.
Show worked answer →

(a) Amplitude. a=6a = 6. Amplitude = a=6°|a| = 6°C.

(b) Period. b=π/12b = \pi/12. Period =2π/b=2π/(π/12)=24= 2\pi/b = 2\pi/(\pi/12) = 24 hours.

(c) Max and min. Range: k±a=18±6k \pm |a| = 18 \pm 6. Maximum 24°24°C, minimum 12°12°C.

(d) Temperature at 33 pm. t=9t = 9 hours after 66 am.

T(9)=6sin(9π/12)+18=6sin(3π/4)+18=6(2/2)+18=32+1822.2°T(9) = 6 \sin(9\pi/12) + 18 = 6 \sin(3\pi/4) + 18 = 6 (\sqrt{2}/2) + 18 = 3\sqrt{2} + 18 \approx 22.2°C.

Markers reward identifying parameters explicitly, period from 2π/b2\pi / b, and the exact-value substitution at 3π/43\pi/4.

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