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QLDMath MethodsSyllabus dot point

How are surds and exponents simplified?

Simplify expressions involving surds and apply the laws of indices to rational and negative exponents

A focused answer to the QCE Math Methods Unit 1 dot point on surds and exponents. Simplifies surds, rationalises denominators, and applies the seven index laws to rational and negative powers; works the standard QCAA simplification problem.

Generated by Claude Opus 4.87 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Surd basics
  3. Adding and subtracting surds
  4. Rationalising denominators
  5. Index laws
  6. Rational and negative exponents
  7. Why rationalise with the conjugate
  8. In one sentence

What this dot point is asking

QCAA wants you to simplify expressions involving surds (including rationalising denominators) and apply the laws of indices to rational and negative exponents. These skills give exact answers, which Methods prefers over decimal approximations, and they recur whenever a calculation produces an irrational result or a fractional power.

Surd basics

A surd is an irrational root, such as 2\sqrt 2, that cannot be reduced to a rational number. Surds obey the multiplication and division rules

aβ‹…b=ab,ab=ab,\sqrt a \cdot \sqrt b = \sqrt{ab}, \qquad \frac{\sqrt a}{\sqrt b} = \sqrt{\frac{a}{b}},

valid for a,bβ‰₯0a, b \geq 0. To simplify a surd, extract the largest perfect-square factor: 72=36β‹…2=62\sqrt{72} = \sqrt{36 \cdot 2} = 6\sqrt 2. There is no corresponding rule for sums, so a+b\sqrt{a + b} does not split into a+b\sqrt a + \sqrt b, a distinction worth stating explicitly because it is a frequent error.

Adding and subtracting surds

Surds add and subtract only when they are "like", that is share the same radicand after simplifying. So 32+52=823\sqrt 2 + 5\sqrt 2 = 8\sqrt 2, but 2+3\sqrt 2 + \sqrt 3 cannot be combined. Often two surds look unlike but become like after simplification, for example 8+18=22+32=52\sqrt{8} + \sqrt{18} = 2\sqrt 2 + 3\sqrt 2 = 5\sqrt 2, so always simplify each surd before deciding whether terms combine.

Rationalising denominators

Eliminate surds from the denominator.

Monomial: 13=33\dfrac{1}{\sqrt 3} = \dfrac{\sqrt 3}{3}.

Binomial: multiply by conjugate. 15βˆ’1=5+14\dfrac{1}{\sqrt 5 - 1} = \dfrac{\sqrt 5 + 1}{4}.

Index laws

The index laws combine powers that share a base, and they are the backbone of all exponent simplification:

aman=am+n,aman=amβˆ’n,(am)n=amn,a^m a^n = a^{m+n}, \qquad \frac{a^m}{a^n} = a^{m-n}, \qquad (a^m)^n = a^{mn},

(ab)n=anbn,(ab)n=anbn,a0=1Β (aβ‰ 0),aβˆ’n=1an.(ab)^n = a^n b^n, \qquad \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}, \qquad a^0 = 1\ (a \neq 0), \qquad a^{-n} = \frac{1}{a^n}.

The first move in almost any simplification is to express every quantity as a power of a common base (for example writing 88 as 232^3), because the laws only act on matching bases. Surds fit in through a=a1/2\sqrt a = a^{1/2}, so a surd expression can always be recast as an index expression and simplified with the same laws.

Rational and negative exponents

Fractional and negative powers extend the index laws so that roots and reciprocals fit the same framework:

a1/n=an,am/n=(an)m=amn,aβˆ’n=1an.a^{1/n} = \sqrt[n]{a}, \qquad a^{m/n} = \left(\sqrt[n]{a}\right)^m = \sqrt[n]{a^m}, \qquad a^{-n} = \frac{1}{a^n}.

The denominator of a fractional index is the root and the numerator is the power, so 82/3=(83)2=22=48^{2/3} = (\sqrt[3]{8})^2 = 2^2 = 4 and 163/4=(164)3=23=816^{3/4} = (\sqrt[4]{16})^3 = 2^3 = 8, while 5βˆ’2=1255^{-2} = \tfrac{1}{25}. This unification is what lets a single set of laws simplify any expression mixing roots, reciprocals and powers, which is the recurring task in this dot point.

Why rationalise with the conjugate

For a binomial surd denominator such as 5βˆ’2\sqrt 5 - \sqrt 2, multiplying by the conjugate 5+2\sqrt 5 + \sqrt 2 exploits the difference of squares: (5βˆ’2)(5+2)=5βˆ’2=3(\sqrt 5 - \sqrt 2)(\sqrt 5 + \sqrt 2) = 5 - 2 = 3, a rational number. The conjugate is the same two terms with the middle sign flipped, and this is the only multiplier that clears both surds at once. The same idea evaluates expressions of the form (a+b)(aβˆ’b)=a2βˆ’b(a + \sqrt b)(a - \sqrt b) = a^2 - b.

In one sentence

Surds simplify by extracting perfect-square factors and rationalising denominators (monomial: multiply by the surd; binomial: multiply by the conjugate); the index laws extend to rational (am/n=amna^{m/n} = \sqrt[n]{a^m}) and negative (aβˆ’n=1/ana^{-n} = 1/a^n) exponents.

Exam-style practice questions

Practice questions written in the style of QCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

QCAA 20223 marksPaper 1 (technique). Simplify 75+123\dfrac{\sqrt{75} + \sqrt{12}}{\sqrt 3}, leaving the answer in simplest form.
Show worked answer β†’

75=53\sqrt{75} = 5\sqrt 3 and 12=23\sqrt{12} = 2\sqrt 3, so the numerator is 53+23=735\sqrt 3 + 2\sqrt 3 = 7\sqrt 3.

Divide: 733=7\dfrac{7\sqrt 3}{\sqrt 3} = 7.

Markers reward simplifying each surd, collecting like surds, and the cancellation.

QCAA 20234 marksPaper 1 (technique). (a) Rationalise the denominator of 65+2\dfrac{6}{\sqrt 5 + \sqrt 2}. (b) Evaluate 27βˆ’2/327^{-2/3} as an exact fraction.
Show worked answer β†’

(a) Multiply by the conjugate 5βˆ’25βˆ’2\dfrac{\sqrt 5 - \sqrt 2}{\sqrt 5 - \sqrt 2}: denominator (5)2βˆ’(2)2=5βˆ’2=3(\sqrt 5)^2 - (\sqrt 2)^2 = 5 - 2 = 3, so 6(5βˆ’2)3=2(5βˆ’2)\dfrac{6(\sqrt 5 - \sqrt 2)}{3} = 2(\sqrt 5 - \sqrt 2).

(b) 27βˆ’2/3=1272/3=1(273)2=132=19.27^{-2/3} = \dfrac{1}{27^{2/3}} = \dfrac{1}{(\sqrt[3]{27})^2} = \dfrac{1}{3^2} = \dfrac{1}{9}.

Markers reward the conjugate, the difference-of-squares denominator, and applying the negative and fractional index laws.

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