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QLDMath MethodsSyllabus dot point

How are arithmetic and geometric sequences analysed?

Define arithmetic and geometric sequences, find the nnth term and the sum of the first nn terms, and apply to real-world contexts

A focused answer to the QCE Math Methods Unit 1 dot point on sequences. States the nnth-term and sum formulas for arithmetic and geometric sequences, distinguishes the two types, and works the standard QCAA applications to salary growth, depreciation and convergent series.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. Arithmetic sequences
  3. Geometric sequences
  4. Identifying the sequence type
  5. Applications
  6. Sum to infinity
  7. In one sentence

What this dot point is asking

QCAA wants you to define and analyse arithmetic and geometric sequences, find the nnth term and the sum of the first nn terms, and apply both to real-world contexts such as loans, salaries, depreciation and population change. Sequences appear in Unit 1 problem-solving and modelling tasks and recur in the financial-mathematics content, so the formulas and the decision of which type applies are foundational skills.

Arithmetic sequences

An arithmetic sequence has a constant common difference dd between consecutive terms, so each term is the previous one plus dd. With first term T1=aT_1 = a,

Tn=a+(nβˆ’1)d.T_n = a + (n - 1)d.

The sum of the first nn terms is

Sn=n2[2a+(nβˆ’1)d]=n2(T1+Tn),S_n = \frac{n}{2}\big[2a + (n - 1)d\big] = \frac{n}{2}(T_1 + T_n),

the second form being the average of the first and last term multiplied by how many terms there are. The common difference can be found from any two terms by d=Tmβˆ’Tkmβˆ’kd = \dfrac{T_m - T_k}{m - k}.

Geometric sequences

A geometric sequence has a constant common ratio rr between consecutive terms, so each term is the previous one multiplied by rr. With first term T1=aT_1 = a,

Tn=a rnβˆ’1.T_n = a\,r^{n - 1}.

The sum of the first nn terms is

Sn=a rnβˆ’1rβˆ’1,rβ‰ 1.S_n = a\,\frac{r^n - 1}{r - 1}, \qquad r \neq 1.

When ∣r∣<1|r| < 1 the terms shrink toward zero and the infinite series converges:

S∞=a1βˆ’r.S_\infty = \frac{a}{1 - r}.

The common ratio is found by dividing any term by the one before it, r=Tn+1Tnr = \dfrac{T_{n+1}}{T_n}.

Identifying the sequence type

The first decision in any sequence problem is which type you have. Compute the differences and ratios of consecutive terms: constant differences signal arithmetic, constant ratios signal geometric, and if neither is constant the sequence is some other type (for example quadratic or recursively defined). Making this check explicitly avoids applying the wrong formula, which is the single most common error.

Applications

The two sequence types model different real-world growth. A fixed-dollar pay rise, straight-line depreciation, and a constant absolute population increase are all arithmetic, because the same amount is added each period. A percentage pay rise, compound interest, declining-balance depreciation, and constant-percentage population growth are all geometric, because the quantity is multiplied by the same factor each period. For compound interest at periodic rate ii, the balance forms a geometric sequence with r=1+ir = 1 + i.

Sum to infinity

For a convergent geometric series (∣r∣<1|r| < 1), the partial sums approach the limit S∞=a1βˆ’rS_\infty = \dfrac{a}{1 - r}. This models a total made up of ever-smaller contributions. A ball that rebounds to 80%80\% of its previous height (r=0.8r = 0.8) travels a total downward distance of h1βˆ’0.8=5h\dfrac{h}{1 - 0.8} = 5h before coming to rest. The formula fails when ∣r∣β‰₯1|r| \geq 1 because the terms do not shrink and the series diverges.

In one sentence

Arithmetic sequences have common difference dd with Tn=a+(nβˆ’1)dT_n = a + (n - 1)d and Sn=n2(T1+Tn)S_n = \tfrac{n}{2}(T_1 + T_n), while geometric sequences have common ratio rr with Tn=arnβˆ’1T_n = ar^{n-1}, Sn=arnβˆ’1rβˆ’1S_n = a\dfrac{r^n - 1}{r - 1}, and S∞=a1βˆ’rS_\infty = \dfrac{a}{1 - r} for ∣r∣<1|r| < 1.

Exam-style practice questions

Practice questions written in the style of QCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

QCAA 20224 marksPaper 2 (complex familiar). A worker is paid \45\,000inyear in year 1witha with a 4\%annualraise.(a)Determinethesalaryinyear annual raise. (a) Determine the salary in year 10.(b)Determinethetotalearnedoverthefirst. (b) Determine the total earned over the first 10$ years.
Show worked answer β†’

Geometric sequence with a=45 000a = 45\,000, r=1.04r = 1.04.

(a) T_{10} = 45\,000 \times (1.04)^9 = 45\,000 \times 1.4233 \approx \64,049.$

(b) S_{10} = a\,\dfrac{r^{10} - 1}{r - 1} = 45\,000 \times \dfrac{1.04^{10} - 1}{0.04} = 45\,000 \times 12.0061 \approx \540,275.$

Markers reward identifying aa and rr, the correct formula choice, and answers in dollars.

QCAA 20233 marksPaper 1 (technique). The third term of an arithmetic sequence is 1717 and the seventh term is 3333. (a) Determine the first term and common difference. (b) Determine the sum of the first 2020 terms.
Show worked answer β†’

(a) T3=a+2d=17T_3 = a + 2d = 17 and T7=a+6d=33T_7 = a + 6d = 33. Subtracting, 4d=164d = 16, so d=4d = 4 and a=17βˆ’2(4)=9.a = 17 - 2(4) = 9.

(b) S20=202[2(9)+19(4)]=10[18+76]=10Γ—94=940.S_{20} = \dfrac{20}{2}[2(9) + 19(4)] = 10[18 + 76] = 10 \times 94 = 940.

Markers reward setting up two equations, solving for aa and dd, and the sum-formula evaluation.

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