← Unit 1: Algebra, statistics and functions

QLDMath MethodsSyllabus dot point

How are polynomial functions analysed?

Sketch and analyse polynomial functions of degree 3 and 4, using factored form to read roots and multiplicities, and applying the factor and remainder theorems

A focused answer to the QCE Math Methods Unit 1 dot point on polynomial functions. Sketches cubics and quartics from factored form, applies the factor and remainder theorems, and works the standard QCAA factor-a-cubic problem.

Generated by Claude OpusReviewed by Better Tuition Academy5 min answer

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What this dot point is asking

QCAA wants you to sketch polynomial functions of degree 33 and 44, use the factor and remainder theorems to find factors, and read intercepts, end behaviour and root multiplicities from the factored form.

Remainder theorem

If P(x)P(x) is divided by (xβˆ’a)(x - a), the remainder is P(a)P(a).

Factor theorem

(xβˆ’a)(x - a) is a factor of P(x)P(x) if and only if P(a)=0P(a) = 0.

Rational roots theorem

For a polynomial with integer coefficients, any rational root p/qp/q (in lowest terms) has pp dividing the constant term and qq dividing the leading coefficient.

Procedure to factor a cubic

  1. Identify rational-root candidates.
  2. Test by computing P(a)P(a).
  3. Once a root aa is found, divide PP by (xβˆ’a)(x - a).
  4. Factor the resulting quadratic.

Polynomial division

Long division of P(x)P(x) by (xβˆ’a)(x - a). Synthetic division for linear divisors is a shortcut.

End behaviour

Set by leading term axnax^n:

  • IMATH_18 even, a>0a > 0: both ends +∞+\infty.
  • IMATH_21 even, a<0a < 0: both ends βˆ’βˆž-\infty.
  • IMATH_24 odd, a>0a > 0: left βˆ’βˆž-\infty, right +∞+\infty.
  • IMATH_28 odd, a<0a < 0: left +∞+\infty, right βˆ’βˆž-\infty.

Root multiplicities

For a factor (xβˆ’p)k(x - p)^k:

  • IMATH_33 : crosses the xx-axis.
  • IMATH_35 : touches and turns (double root).
  • IMATH_36 : crosses with a horizontal tangent (point of inflection on axis).

Sketching from factored form

  1. Read roots and multiplicities from the factors.
  2. Find yy-intercept by substituting x=0x = 0.
  3. Determine end behaviour from leading term.
  4. Sketch through the roots with the correct crossing/touching behaviour.

Worked example

Sketch y=(x+2)(xβˆ’1)2(xβˆ’3)y = (x + 2)(x - 1)^2 (x - 3).

Quartic, leading +1+1. Roots: βˆ’2-2 (crosses), 11 (touches), 33 (crosses). yy-intercept: y(0)=(2)(1)(βˆ’3)=βˆ’6y(0) = (2)(1)(-3) = -6. Both ends +∞+\infty.

Sketch enters from top left, crosses at βˆ’2-2, dips below, touches axis at 11, descends below, crosses at 33, exits top right.

Common traps

Wrong ZZ direction. Factor (x+2)(x + 2) corresponds to root βˆ’2-2, not +2+2.

Missing the constraints of rational-roots theorem. Trying x=5x = 5 when 55 does not divide the constant wastes time.

Forgetting multiplicities. A double root touches; a triple root has a horizontal tangent.

In one sentence

Polynomial functions of degree 33 or 44 are factored using the rational-roots theorem to find candidate roots, the factor theorem to verify ((xβˆ’a)(x - a) is a factor iff P(a)=0P(a) = 0), and polynomial division to extract the linear factor; sketches read roots and multiplicities from the factored form, yy-intercept from x=0x = 0, and end behaviour from the leading term.

Past exam questions, worked

Real questions from past QCAA papers on this dot point, with our answer explainer.

Year 11 SAC5 marksFactor $P(x) = 2x^3 + x^2 - 13x + 6$ completely and find all roots.
Show worked answer β†’

Try rational roots from divisors of 66 over divisors of 22.

P(2)=16+4βˆ’26+6=0P(2) = 16 + 4 - 26 + 6 = 0. So (xβˆ’2)(x - 2) is a factor.

Divide: 2x3+x2βˆ’13x+6=(xβˆ’2)(2x2+5xβˆ’3)=(xβˆ’2)(2xβˆ’1)(x+3)2x^3 + x^2 - 13x + 6 = (x - 2)(2x^2 + 5x - 3) = (x - 2)(2x - 1)(x + 3).

Roots: x=2,1/2,βˆ’3x = 2, 1/2, -3.

Markers reward rational-roots search, verification, division, and quadratic factoring.

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