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Module 6: Electromagnetism

Quick questions on Charged particles in electric fields explained: HSC Physics Module 6

12short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is the uniform field between parallel plates?
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Two parallel conducting plates held at a potential difference $V$ and separated by a distance $d$ produce a nearly uniform electric field in the region between them:
What is force and acceleration?
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A particle of charge $q$ in the field experiences a force:
What is work done by the field?
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If the charge moves a distance $d$ in the direction of the field (or, equivalently, through a potential difference $V$ between its start and end positions):
What is kinetic energy and final speed?
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By the work-energy theorem, the work done by the net force equals the change in kinetic energy:
What is two motion regimes you must distinguish?
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Parallel acceleration. The particle enters along the field direction (or starts at rest). Motion is one-dimensional, constant acceleration. Use $v^2 = u^2 + 2as$ with $s = d$, or use energy: $qV = \frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2$.
What is parallel acceleration?
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The particle enters along the field direction (or starts at rest). Motion is one-dimensional, constant acceleration. Use $v^2 = u^2 + 2as$ with $s = d$, or use energy: $qV = \frac{1}{2} m v_f^2 - \frac{1}{2} m v_i^2$.
What is transverse deflection?
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The particle enters horizontally between the plates with speed $v_x$, and the field is vertical. The horizontal speed is constant, the vertical motion has constant acceleration $a = qE/m$. After time $t = L / v_x$ in plates of length $L$, the vertical deflection is $y = \frac{1}{2} a t^2$.
What is forgetting that electrons accelerate opposite to $E$?
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The force on a negative charge is $-|q|E$, so an electron near a negative plate is pushed toward the positive plate.
What is mixing centimetres and metres?
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$E = V/d$ requires $d$ in metres. A 5 cm gap is 0.05 m, not 5.
What is using $W = Fd$ for the wrong $d$?
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The $d$ in $W = qEd$ is the distance moved along the field. Transverse motion does no work; only the component of displacement along $E$ counts.
What is including gravity?
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For electrons and protons in the electric fields of standard HSC problems, the gravitational force is many orders of magnitude smaller than the electric force and is usually neglected. State this assumption explicitly if asked.
What is quoting $W = qV$ with the wrong sign?
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$V$ is the potential difference through which the charge moves; a positive charge gains kinetic energy when moving from high to low potential, a negative charge gains kinetic energy when moving from low to high potential.

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