Circular functions extended (VCE Maths Methods Unit 2)
“Sketch and analyse trigonometric functions and , identifying amplitude, period, phase and vertical translation, and solve trig equations over a specified interval”
For (and the cosine version): amplitude is , period is , is the phase shift and is the centre line. To solve equations like on an interval, expand the interval for , find all solutions, then divide by .
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What this dot point is asking
VCAA wants you to sketch and analyse transformed sine and cosine functions, identifying amplitude, period, phase shift and vertical translation, and to solve trigonometric equations over a specified interval.
Parent functions
and :
- Domain: all real . Range: .
- Period: . Amplitude: .
Transformed form
| Parameter | Effect |
|---|---|
| Amplitude. Range . If , vertical reflection. | |
| Period = . Larger compresses horizontally. | |
| Phase shift; graph moves right (if positive). | |
| Vertical translation; centre line . |
Same parameters apply to .
Solving trig equations over a stated interval
- Isolate the trig function.
- Find the principal solution.
- Use symmetry and periodicity to find all solutions in the stated interval.
- If the equation involves , list all solutions for in the expanded interval and divide by .
Reference angles and quadrant signs
The engine of trig equation solving is the reference angle, the acute angle whose sine, cosine or tangent has the same magnitude as the required value. Find it from the positive value, then place solutions in the correct quadrants using the sign of the original equation: sine is positive in quadrants 1 and 2, cosine in quadrants 1 and 4, and tangent in quadrants 1 and 3. The standard placements are (quadrant 2), (quadrant 3) and (quadrant 4). Exact values from the special triangles () appear constantly, so commit them to memory for tech-free Exam 1.
Sketching transformed graphs
A reliable sketch shows the centre line , the maximum and minimum , and one full period of width starting from the phase shift . Mark the five key points across a period (the quarter, half and three-quarter points), since these locate the maxima, minima and crossings of the centre line. Reading , , and directly off the equation, then plotting these features, is exactly the method VCAA rewards.
Step 1: Isolate the trigonometric function
We are given for . Before we can use any trig identity or reference angle, we must rearrange so that stands alone on one side. Subtracting and dividing by :
Step 2: Find the reference angle
The reference angle is the acute angle (between and ) whose cosine has the same magnitude as the value on the right-hand side. We ignore the negative sign for now and ask: for which angle is ? From the special triangle for :
Step 3: Place solutions in the correct quadrants
Cosine is negative in quadrants 2 and 3, because in those quadrants the -coordinate on the unit circle is negative. Using the standard quadrant-placement formulas, the two solutions in are:
Step 4: State all solutions in the interval
Both values lie within , and cosine has period so there are no further solutions in this interval. We check: and , confirming both are correct.
Final answer: or .
- Confusing with the period
- The period is , not .
- Forgetting to expand the interval
- Solving for requires all solutions for in before dividing by , otherwise half the solutions are lost.
- Missing solutions in the stated interval
- Sine and cosine are periodic; list every solution that falls in the interval, not just the principal one.
- Wrong quadrant from the sign
- Use the sign of the original equation, not the reference value, to choose quadrants.
In one sentence
Transformed circular functions have amplitude , period , phase shift and centre line ; solving trig equations over an interval uses the reference angle plus quadrant symmetry, and equations involving require finding solutions for in the expanded interval before dividing by .
Examples in context
Example 1. Tidal height model. A harbour's water depth (metres) is modelled by , where is hours after midnight. The amplitude is m about a mean depth of m, and the period is hours. High tide () first occurs when , i.e. , giving hours (3 am).
Example 2. Ferris wheel height. A rider's height is , i.e. metres, with in seconds. The period is s per rotation, amplitude m about a centre m. At , m (boarding height); the maximum m occurs at s.
Try this
Q1. State the amplitude, period and range of . [3 marks]
- Cue. Amplitude ; period ; range .
Q2. Solve for . [3 marks]
- Cue. ; .
Q3. A signal is modelled by . (a) State its period. (b) Find the first time when . [2+2 marks]
- Cue. (a) Period . (b) .
Exam-style questions
Questions in the style of VCAA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.
Practice4 marksSolve for .Show worked answer →
Let . Then and .
Solutions for in : .
Back-substitute : .
Markers reward the substitution, the expanded interval for , the four solutions in that interval, and back-substitution.
Practice5 marksThe temperature in a greenhouse is modelled by degrees Celsius, where is hours after midnight, . (a) State the maximum and minimum temperatures and the times they occur. (b) Find the times at which the temperature first reaches degrees.Show worked answer →
(a) The amplitude is about the centre line , so the maximum is degrees and the minimum is degrees. The minimum occurs where , i.e. (midnight); the maximum where , i.e. , so (noon).
(b) Set : , so . Let , with . Then or , giving and . The temperature first reaches degrees at (8 am).
Markers reward reading amplitude and centre line, the times of extremes, and solving the trig equation across the interval.