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Measuring biodiversity (species richness, evenness, Simpson's diversity index): VCE Environmental Science Unit 3

Syllabus dot point

“Measures of biodiversity including species richness, species evenness and the use of diversity indices to compare ecosystems”

8 min read

Quick answer

Biodiversity is measured using species richness (the number of species) and species evenness (how evenly individuals are spread), combined in a diversity index such as Simpson's index so two ecosystems can be compared objectively.

What this dot point is asking

VCAA wants you to define and distinguish species richness and species evenness, and to use a diversity index (most commonly Simpson's) to compare ecosystems quantitatively. You may be asked to calculate an index from a data table and interpret what it means.

Richness and evenness

Species richness is simply the number of different species recorded in a sample or site. A rockpool with 12 species is richer than one with 5. Richness ignores how common each species is.

Species evenness describes how equally individuals are distributed among the species present. If a site has 4 species with roughly equal numbers, evenness is high. If one species dominates (say 95 per cent of individuals) and three are rare, evenness is low.

Both matter. Two sites can have identical richness but very different diversity because one is dominated by a single species. A good measure of biodiversity combines richness and evenness, which is what a diversity index does. Evenness is sometimes reported on its own as a value between 00 and 11, where 11 means every species has exactly the same number of individuals, but in VCE it is most often captured through a combined diversity index rather than calculated separately.

Simpson's diversity index

Simpson's index gives a single number that accounts for both richness and evenness. The form VCAA prints on the exam and expects you to use is:

Simpson's index of diversity

SID=1−∑ni(ni−1)N(N−1)SID = 1 - \frac{\sum n_i(n_i - 1)}{N(N - 1)}

Here nin_i is the number of individuals of one species and NN is the total number of individuals of all species combined. SIDSID ranges from 00 (no diversity, a single species) to almost 11 (very high diversity). A higher SIDSID means greater biodiversity, because two randomly chosen individuals are less likely to belong to the same species.

The term ni(ni−1)N(N−1)\frac{n_i(n_i - 1)}{N(N - 1)} is the probability that two individuals drawn at random (without replacement) both belong to the same species. Summing this across every species and subtracting from 11 gives the probability that the two individuals belong to different species, so a higher SIDSID signals a more diverse, more even community. An equivalent proportion-based form, D=1−∑(ni/N)2D = 1 - \sum (n_i / N)^2, gives a very similar value for large samples, but the N(N−1)N(N - 1) version is the one VCAA supplies, so use it in the exam and show every substitution.

Calculating Simpson's index of diversity

A quadrat in a Victorian grassland records four species: kangaroo grass 2020, wallaby grass 1515, spear grass 1010, and an introduced annual 55, giving N=50N = 50.

Step 1: Find N, the total number of individuals

Add every count: N=20+15+10+5=50N = 20 + 15 + 10 + 5 = 50. This is the total of all individuals, not the number of species.

Step 2: Calculate the n(n - 1) term for each species

20×19=38020 \times 19 = 380; 15×14=21015 \times 14 = 210; 10×9=9010 \times 9 = 90; 5×4=205 \times 4 = 20.

Step 3: Sum the species terms and the N(N - 1) term

∑ni(ni−1)=380+210+90+20=700\sum n_i(n_i - 1) = 380 + 210 + 90 + 20 = 700. The denominator is N(N−1)=50×49=2450N(N - 1) = 50 \times 49 = 2450.

Step 4: Substitute and evaluate

SID=1−7002450=1−0.2857=0.71SID = 1 - \frac{700}{2450} = 1 - 0.2857 = 0.71 (to two decimal places). A degraded site where the introduced annual made up 4545 of 5050 individuals would give a much larger summed term and a much lower SIDSID near 0.180.18, showing far lower biodiversity even though richness is the same. This is why evenness matters as much as richness.

Sampling and comparing ecosystems

Index values are only meaningful when sampling is done consistently. Use the same quadrat or transect size, the same sampling effort, and random or systematic placement to avoid bias. Quadrats suit plants and slow or sessile organisms; transects are used to record how communities change along an environmental gradient such as distance from a creek. Larger or more numerous samples reduce the chance of missing rare species and give a more reliable estimate of richness, because rare species are easy to overlook in a single small quadrat.

Comparing the index between sites (for example, a grazed paddock versus a fenced conservation reserve, or upstream versus downstream of an outfall) lets you draw conclusions about the effect of a management practice or a threat. Because SIDSID is a single standardised value between 00 and 11, it allows objective comparison in a way that a raw species list cannot. A falling diversity index measured over several years is an early warning of ecosystem degradation, and a rising index after a restoration project is evidence that management is working.

Why ecologists prefer an index to a raw count

Species richness alone treats a site with one dominant weed and a few survivors the same as a balanced community, as long as the number of species matches. By folding evenness into the calculation, a diversity index rewards communities where individuals are spread across many species and penalises those dominated by one. This matters for management decisions: a reserve might keep the same number of species while a single invasive grass quietly takes over, and only an index that responds to evenness would reveal that the ecosystem is degrading. When you interpret an index in the exam, comment on both richness and evenness, and always read it alongside the species list so you can tell whether the species present are native or introduced.

Common traps
Forgetting to square the proportion
The formula squares (n / N) before summing. Skipping the square gives a meaningless answer.
Reporting D backwards
With D = 1 - sum, a higher value means more diversity. With some other versions of Simpson's index a lower value means more diversity, so always state which form you are using.
Comparing indices from different-sized samples
Richness rises with sample size, so an index from a small quadrat cannot be fairly compared with one from a large transect. Standardise the sampling method first.
Treating the index as the whole story
A diversity index does not tell you which species are present or whether they are native or introduced. Always interpret it alongside the species list.

Exam-style questions

Questions in the style of VCAA exam questions on this dot point, each with a worked answer. They are written by ExamExplained unless tagged "Past paper"; the year shows the paper a question is modelled on.

2025 VCAA-style2 marks
A group of Environmental Science students aimed to measure the species diversity at their local park. They used one 2 x 2 m quadrat and counted the variety of species present. Calculate Simpson's Index of Diversity (SID) for this sample. Species (ni): exotic separated tussock grass 25, exotic bearded oatgrass 2, endemic rough spear grass 3, native housefly 2, native ant 2.
Show worked answer →

The VCAA form is SID = 1 - [sum of ni(ni - 1)] / [N(N - 1)].

1 mark: find the totals. N = 25 + 2 + 3 + 2 + 2 = 34. The sum of ni(ni - 1) = 25(24) + 2(1) + 3(2) + 2(1) + 2(1) = 600 + 2 + 6 + 2 + 2 = 612.

1 mark: substitute and evaluate. N(N - 1) = 34 x 33 = 1122. SID = 1 - (612 / 1122) = 1 - 0.5455 = 0.45 (to two decimal places).

A low SID near 0.45 reflects that one exotic species (tussock grass) dominates the quadrat, so two randomly chosen individuals are fairly likely to be the same species. Show full working, as marks are for the method as well as the final value.

2023 VCAA-style1 mark
The formula for SID is SID = 1 - [sum of ni(ni - 1)] / [N(N - 1)]. What does 'N' represent in the formula?
Show worked answer →

1 mark: N represents the total number of individual organisms of all species counted in the sample (the total of all individuals across every species present), not the number of different species.

The term ni is the number of individuals of one particular species, so summing ni across every species gives N. Confusing N (total individuals) with the number of species is the most common error, and it makes the whole calculation wrong.

2022 VCAA-style3 marks
A sampling study determined the effect of elevation on species diversity in an alpine area. The graph indicated average species richness and average Simpson's Index of Diversity (SID) at sites of increasing elevation. Explain why the SID and species richness data follow a similar trend, in terms of the calculation of SID.
Show worked answer →

A 3 mark response links the trend to how SID is calculated.

1 mark: state that species richness is the number of different species present, while SID combines richness and evenness into a single value between 0 and 1.

1 mark: explain that SID increases as more species are added, because each extra species lowers the proportion that any one species contributes, reducing the summed term [sum of ni(ni - 1)] / [N(N - 1)].

1 mark: conclude that because adding species both raises richness and raises SID, the two measures rise and fall together, so they follow a similar trend across the elevation gradient. A higher richness generally produces a higher SID when evenness is broadly similar.

Practise this

Sources & how we know this

ExamExplained