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the design and operation of galvanic cells, including primary cells, secondary (rechargeable) cells and fuel cells, with reference to the role of anode, cathode, electrolyte, salt bridge and external circuit, and the calculation of cell EMF (E°_cell) from standard electrode potentials at 25°C
A focused VCE Chemistry Unit 3 answer on galvanic cells. Covers the components of a galvanic cell, the distinction between primary, secondary and fuel cells, the direction of electron and ion flow, and the calculation of E°_cell from standard electrode potentials.
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What this dot point is asking
VCAA wants you to know the components of a galvanic cell (electrodes, electrolyte, salt bridge, external circuit), to distinguish primary cells, secondary cells and fuel cells, to identify anode, cathode and the direction of electron flow, and to calculate E°_cell from standard electrode potentials at 25°C.
The answer
What a galvanic cell does
A galvanic cell (also called a voltaic cell) converts the chemical energy of a spontaneous redox reaction into electrical energy. The two half-reactions are physically separated into half-cells so that the electrons released by the oxidation half-cell are forced to travel through an external circuit to reach the reduction half-cell. That moving charge is the electric current the cell delivers.
Components
A galvanic cell has five components:
- Anode: the electrode where oxidation occurs. The species with the more negative E° is oxidised here. The anode is the negative terminal of a galvanic cell.
- Cathode: the electrode where reduction occurs. The species with the more positive E° is reduced here. The cathode is the positive terminal of a galvanic cell.
- Electrolyte: the ionic solution in each half-cell that allows ions to flow and supplies the species being oxidised or reduced.
- Salt bridge: a porous tube or filter paper soaked in inert ionic solution (e.g. KNO3) that lets ions migrate between half-cells to keep both electrolytes electrically neutral. Without it the cell stops working within seconds.
- External circuit: the wire (often with a voltmeter or load) connecting the two electrodes. Electrons flow from anode to cathode here.
Memory aid: AN OX, RED CAT. The ANode is where OXidation happens; REDuction happens at the CAThode.
Direction of charge
- Electrons flow through the wire from anode to cathode (negative terminal to positive terminal in the external circuit).
- Conventional current is in the opposite direction (cathode to anode externally).
- Cations (positive ions) in the salt bridge flow towards the cathode half-cell.
- Anions (negative ions) in the salt bridge flow towards the anode half-cell.
The ion flow keeps each half-cell electrically neutral. As the anode half-cell builds up Zn^2+, anions move in to balance the charge; as the cathode half-cell consumes Ag^+, cations move in to replace the lost positive charge.
Calculating cell EMF
The EMF (or cell potential) E°_cell is the voltage the cell delivers under standard conditions (1 mol L^-1 solutions, 25°C, 1 atm for gases).
E°_cell = E°(cathode) - E°(anode)
where both E° values come from the data book as reduction potentials.
- If E°_cell > 0, the reaction is spontaneous as written.
- If E°_cell < 0, the reverse reaction is spontaneous; the cell as written will not produce current.
You do not multiply E° by stoichiometric coefficients. E° is a per-electron property that does not scale with the equation.
Primary, secondary and fuel cells
The three cell types in the VCE Study Design:
| Cell type | Reactants | Rechargeable? | Examples |
|---|---|---|---|
| Primary cell | Stored inside the cell | No (single use) | Alkaline AA, zinc carbon battery |
| Secondary cell | Stored inside, reactions reversible | Yes (rechargeable) | Lead acid car battery, lithium ion phone battery |
| Fuel cell | Supplied continuously from outside | No "charging"; runs while fuel supplied | Hydrogen oxygen fuel cell, methanol fuel cell |
Primary cells. The redox reaction is one way. Once the reactants are consumed, the cell is dead and discarded. Cheap, simple, used in low-drain applications (remote controls).
Secondary cells. The redox reaction is reversible. Applying an external voltage in reverse drives the reaction backwards, regenerating the original reactants. Higher initial cost, but cheaper per use over the cell's life. The lead acid battery in a petrol car is recharged by the alternator while the engine runs.
Fuel cells. A continuous supply of fuel (e.g. H2) and oxidant (O2) enters the cell. The cell runs as long as the supply continues. Often used where high efficiency, low emissions, or remote operation matter (buses, spacecraft, backup power for hospitals).
The hydrogen oxygen fuel cell
A widely examined example. In an acidic electrolyte:
- Anode: 2H2(g) -> 4H^+(aq) + 4e^-
- Cathode: O2(g) + 4H^+(aq) + 4e^- -> 2H2O(l)
- Overall: 2H2(g) + O2(g) -> 2H2O(l)
The only product is water. E°_cell is about +1.23 V. Advantages: high efficiency, only product is water, modular design. Disadvantages: hydrogen storage is difficult (low energy density as a gas, requires high-pressure tanks or chemical storage), platinum catalyst is expensive, and most hydrogen today is produced from natural gas (releasing CO2 upstream).
Worked example
A galvanic cell is built from a copper half-cell (Cu in 1.0 mol L^-1 Cu(NO3)2) and an aluminium half-cell (Al in 1.0 mol L^-1 Al(NO3)3), connected by a KNO3 salt bridge. Identify the anode and cathode, write the overall equation and calculate E°_cell.
From the data book:
Cu^2+(aq) + 2e^- -> Cu(s) E° = +0.34 V
Al^3+(aq) + 3e^- -> Al(s) E° = -1.66 V
Cu^2+ has the more positive E°, so Cu is the cathode (reduction) and Al is the anode (oxidation).
Half-equations (balancing electrons at 6 each):
Anode: 2Al(s) -> 2Al^3+(aq) + 6e^-
Cathode: 3Cu^2+(aq) + 6e^- -> 3Cu(s)
Overall:
2Al(s) + 3Cu^2+(aq) -> 2Al^3+(aq) + 3Cu(s)
E°_cell = +0.34 - (-1.66) = +2.00 V
The cell delivers 2.00 V under standard conditions. Electrons flow from the Al anode to the Cu cathode through the wire. K^+ from the salt bridge moves into the copper half-cell; NO3^- moves into the aluminium half-cell.
Common traps
Calling the anode positive. In a galvanic cell, the anode is negative and the cathode is positive. (In an electrolytic cell the polarity is reversed; this is a common point of confusion.)
Multiplying E° by coefficients. E° is a per-electron property. Multiplying or dividing the half-equation does not change E°.
Forgetting to subtract a negative E°. E°_cell = E°(cathode) - E°(anode). If the anode E° is negative, subtracting a negative gives a larger positive E°_cell. Sign errors here cost marks.
Reversing the salt bridge ion direction. Cations chase the cathode (cation goes to cathode). Anions stay with the anode (anion to anode).
Calling a fuel cell "rechargeable". A fuel cell is not recharged; it runs continuously while fuel is supplied. Secondary cells are recharged.
Drawing a cell with no salt bridge. Without the salt bridge the cell stops within seconds because charge cannot be balanced.
In one sentence
A galvanic cell converts spontaneous redox chemistry into electricity by separating oxidation at the anode (negative terminal) from reduction at the cathode (positive terminal), with electrons flowing through the external wire and ions through the salt bridge, and the EMF given by E°(cathode) minus E°(anode) from the electrochemical series.
Past exam questions, worked
Real questions from past VCAA papers on this dot point, with our answer explainer.
2024 VCE5 marksA galvanic cell is constructed using a zinc electrode in 1.0 mol L^-1 Zn(NO3)2 solution and a silver electrode in 1.0 mol L^-1 AgNO3 solution, connected by a salt bridge containing KNO3. Draw or describe the cell, write the half-equations and overall equation, identify anode and cathode, indicate electron flow, and calculate the cell EMF.Show worked answer →
A 5-mark answer needs the half-equations with E°, the cathode/anode labels, electron direction, salt bridge ion flow, and E°_cell.
From the data book:
Ag^+(aq) + e^- -> Ag(s) E° = +0.80 V
Zn^2+(aq) + 2e^- -> Zn(s) E° = -0.76 V
Ag^+ has the more positive E° so it is the stronger oxidant. Ag is the cathode (reduction); Zn is the anode (oxidation).
Half-equations:
Anode (oxidation): Zn(s) -> Zn^2+(aq) + 2e^-
Cathode (reduction): 2Ag^+(aq) + 2e^- -> 2Ag(s)
Overall:
Zn(s) + 2Ag^+(aq) -> Zn^2+(aq) + 2Ag(s)
Electron flow: through the external wire from the Zn anode (negative terminal) to the Ag cathode (positive terminal).
Salt bridge: cations (K^+) flow towards the cathode half-cell to balance the build-up of negative charge as Ag^+ is consumed; anions (NO3^-) flow towards the anode half-cell to balance the build-up of positive Zn^2+.
Cell EMF:
E°_cell = E°(cathode) - E°(anode) = (+0.80) - (-0.76) = +1.56 V
The positive E°_cell confirms the reaction is spontaneous and the cell delivers 1.56 V under standard conditions.
2025 VCE3 marksDistinguish between a primary cell, a secondary cell and a fuel cell with one example of each.Show worked answer →
A 3-mark answer needs the defining feature of each plus a named example.
- Primary cell: cannot be recharged. The reactants are consumed and the cell is discarded once flat. Example: an alkaline AA battery (zinc anode, manganese dioxide cathode).
- Secondary cell: can be recharged because the redox reactions are reversible. Reversing the current drives the reverse reaction, regenerating reactants. Example: a lithium-ion phone battery, or a lead-acid car battery.
- Fuel cell: reactants (a fuel and an oxidant) are supplied continuously from outside the cell, so the cell runs as long as fuel is supplied without being "recharged". Example: a hydrogen oxygen fuel cell used in buses or in spacecraft.
Markers reward the continuous supply distinction for fuel cells (often missed) and the reversibility of the redox reactions for secondary cells.
Related dot points
- redox reactions with reference to the electrochemical series, including the writing of balanced half-equations and overall ionic equations, the identification of oxidants and reductants, the prediction of spontaneous reactions, and the use of standard electrode potentials at 25°C
A focused VCE Chemistry Unit 3 answer on redox reactions and the electrochemical series. Covers oxidation and reduction in terms of electron transfer, writing and balancing half-equations, identifying oxidants and reductants, and using standard electrode potentials to predict spontaneous reactions.
- the design and operation of electrolytic cells for the commercial production of chemicals, including comparison with galvanic cells, the polarity of electrodes in each, the difference between molten and aqueous electrolysis, and the application of Faraday's laws using Q = It and n(e) = Q/F to calculate the mass of substance produced or consumed
A focused VCE Chemistry Unit 3 answer on electrolytic cells. Covers electrolysis of molten and aqueous electrolytes, the comparison with galvanic cells, electrode polarity, and quantitative calculations using Faraday's laws (Q = It and n(e) = Q/F).