How do we model quantities that grow or decay by a constant factor over time?
Model and analyse linear and geometric growth and decay using recurrence relations and rules.
Linear (arithmetic) versus geometric (exponential) growth and decay, recurrence relations, closed-form rules, and applications in TCE Mathematics Applications.
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What this dot point is asking
Growth and decay extend the financial recurrence ideas to any repeating process: populations, drug concentrations, radioactive material, or savings. The key question is whether each step adds a fixed amount (linear) or multiplies by a fixed factor (geometric).
Recurrence relations
A recurrence relation defines each term from the previous one and a starting value:
Linear: , with given. Here is growth, is decay.
Geometric: , with given. Here is growth, is decay.
The closed form lets you jump straight to any term without listing all the ones before it.
Recognising the model
If the differences between consecutive terms are constant, the data is linear. If the ratios between consecutive terms are constant, the data is geometric. Always test which one fits before choosing a rule.
Comparing the two models
Over the long run, geometric growth always overtakes linear growth, because multiplying repeatedly outpaces adding repeatedly. Geometric decay approaches zero but never quite reaches it, whereas linear decay hits zero (and would go negative if the rule kept applying).
A complete answer states the type of model, gives both the recurrence and the closed form, and rounds sensibly to the context (whole people for populations, two decimals for milligrams).
Exam-style practice questions
Practice questions written in the style of TASC exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2024 TASC General Mathematics8 marksTable 9 shows the declining number of births per year in a large country: 2021 = 15644946 (T1), 2022 = 15269467 (T2), 2023 = 14903000 (T3). a) Is the sequence arithmetic or geometric? Show working. b) Find the explicit rule for this sequence. c) Use a formula to predict the total number of births over the 10 years from 2021 (including 2021), to the nearest whole number. d) By continually adding the number of births in this sequence, on and on forever, what is the answer?Show worked answer →
a) (2 marks) Test ratios: T2/T1 = 15269467/15644946 = 0.976 and T3/T2 = 14903000/15269467 = 0.976. The ratio is constant (the differences are not), so the sequence is geometric with r = 0.976.
b) (2 marks) Geometric rule Tn = a r^(n-1) with a = 15644946 and r = 0.976: Tn = 15644946 x (0.976)^(n-1).
c) (2 marks) Sum of first 10 terms Sn = a(1 - r^n)/(1 - r) = 15644946(1 - 0.976^10)/(1 - 0.976) = 140590150 births (nearest whole number).
d) (2 marks) Since the common ratio satisfies the absolute value of r being less than 1, the infinite sum converges to a finite limit: S(infinity) = a/(1 - r) = 15644946/0.024 = 651872236. Adding forever does not give infinity, it approaches this fixed value (though in reality births cannot continue indefinitely).
2024 TASC General Mathematics3 marksBelow are questions about models used to study sequences. a) i. Growth of organisms in a petri dish follows the sequence 100, 150, 225, ... Find an equation to model the sequence. ii. A herd of 1500 wildebeest grows by 15% each year, but each year 40 wildebeest are lost to lion attacks. Find an equation to model the situation.Show worked answer →
a) i. (1 mark) Ratios: 150/100 = 1.5 and 225/150 = 1.5, so this is geometric with a = 100 and r = 1.5. Explicit rule: Tn = 100 x (1.5)^(n-1).
a) ii. (2 marks) Each year the herd grows by 15% (multiply by 1.15) then loses 40. This both multiplies and subtracts a fixed amount, so it is a first-order linear recurrence: Tn+1 = 1.15 Tn - 40, with starting value T0 = 1500. Markers want the multiplier 1.15 and the subtraction of 40, not a pure geometric rule.