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What evidence shows that light behaves as a wave, and how do waves combine when they overlap?

Describe the wave model of light and apply the principle of superposition to constructive and destructive interference.

The wave model of light, the principle of superposition, and how path difference determines constructive and destructive interference, with worked examples.

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  1. What this dot point is asking
  2. The wave model of light
  3. The principle of superposition
  4. Coherence and path difference
  5. Why interference is evidence for waves
  6. How SACE assesses this

What this dot point is asking

You need to describe the wave model of light and apply the principle of superposition to predict where constructive and destructive interference occur.

The wave model of light

The wave model treats light as a transverse electromagnetic wave. Its key quantities are wavelength λ\lambda, frequency ff and speed vv (in a vacuum, c=3.00×108 m s1c = 3.00\times10^8\ \text{m s}^{-1}), linked by:

v=fλ.v = f\lambda.

Different colours correspond to different wavelengths; the visible range runs from about 400 nm400\ \text{nm} (violet) to 700 nm700\ \text{nm} (red). The wave model successfully explains reflection, refraction, diffraction and interference.

The principle of superposition

Superposition is what makes interference possible: the combined wave can be larger or smaller than either wave alone, depending on the phase relationship at that point.

Coherence and path difference

For a stable interference pattern the two sources must be coherent, meaning they have the same frequency and a constant phase relationship. The outcome at any point is then decided by the path difference, the difference in the distances travelled by the two waves to that point.

So you classify any point by dividing its path difference by the wavelength: a whole number gives a maximum, a half-integer gives a minimum.

Why interference is evidence for waves

Interference - the alternating reinforcement and cancellation of two overlapping disturbances - is a uniquely wave phenomenon. Particles travelling in straight lines cannot cancel one another out, yet two coherent light beams produce dark fringes where they overlap. The double-slit pattern (next dot point) is the classic demonstration and was historically decisive evidence for the wave nature of light.

How SACE assesses this

SACE Stage 2 questions on superposition give the path difference to a point (often from two antennas or two slits) and ask whether the interference is constructive or destructive. The reliable method is to compute the path difference, divide it by the wavelength, and classify the result: a whole number of wavelengths gives a maximum (constructive), an odd number of half-wavelengths gives a minimum (destructive). A frequent explanation part asks you to account for the dark fringes in a two-slit pattern, where the marking points are superposition of the two coherent waves, destructive interference (a crest meeting a trough), and the path-difference condition of an odd number of half-wavelengths. State your reasoning explicitly and quote the path-difference condition you are using.

Exam-style practice questions

Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

SACE 20243 marksTwo vertical transmitting antennas A and B emit coherent electromagnetic waves of wavelength 62.5 m62.5\ \text{m}. A receiver at point P is 30.0 km30.0\ \text{km} from A and 40.0 km40.0\ \text{km} from B. Determine whether the waves at P are at maximum or minimum amplitude.
Show worked answer →

Whether the interference is constructive (maximum) or destructive (minimum) depends on the path difference compared with the wavelength.

Path difference =40.030.0=10.0 km=10000 m= 40.0 - 30.0 = 10.0\ \text{km} = 10\,000\ \text{m}.

Divide by the wavelength: 1000062.5=160\dfrac{10\,000}{62.5} = 160, a whole number of wavelengths.

A path difference of a whole number of wavelengths means the waves arrive in phase, so they interfere constructively and the amplitude at P is a maximum. 1 mark for the path difference, 1 mark for dividing by the wavelength to get a whole number, 1 mark for concluding maximum amplitude.

SACE 20233 marksIn a two-slit experiment with a sodium lamp, a pattern of dark and light fringes appears on a screen. Explain the production of the dark fringes.
Show worked answer →

Light from the two slits spreads out and overlaps on the screen. Because the light is coherent, the two sets of waves combine by the principle of superposition.

A dark fringe forms where the two waves arrive exactly out of phase, so a crest from one slit meets a trough from the other. This is destructive interference, and the waves cancel to give minimum (zero) amplitude.

This happens where the path difference is an odd number of half-wavelengths (12λ\tfrac{1}{2}\lambda, 32λ\tfrac{3}{2}\lambda, and so on). 1 mark for superposition of the two coherent waves, 1 mark for destructive interference (crest meets trough), 1 mark for the odd-number-of-half-wavelengths condition.

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