Why does a magnetic field only exert a force on a charge that is moving, and what determines the direction of that force?
Calculate the magnetic force on a moving charge and determine its direction using the right-hand rule.
How a magnetic field exerts a force on a moving charge, the equation F = qvB sin theta, and using the right-hand rule to find the direction, with worked examples.
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What this dot point is asking
You need to calculate the magnetic force on a moving charge and determine its direction using a hand rule.
Why the charge must be moving
A stationary charge in a magnetic field feels no magnetic force. Only when the charge moves does the field push on it - and only the component of velocity perpendicular to the field contributes.
Direction: the right-hand rule
The force is perpendicular to both the velocity and the magnetic field - it cannot point along either. For a positive charge, point the fingers of your right hand along the velocity , curl them toward the field (or use the flat-hand "slap" rule: fingers along , thumb along , palm pushes in the force direction). The force is along your thumb/palm.
Circular motion in a magnetic field
Because the magnetic force is always perpendicular to the velocity, it never changes the speed - it only changes direction. It does no work on the charge. A charge entering a uniform field perpendicular to it therefore moves in a circle, with the magnetic force providing the centripetal force (this is developed in the "charged particles in magnetic fields" dot point).
Units
The tesla is defined so that , or equivalently per (coulomb-metre-per-second). A 1 T field is strong; the Earth's field is around .
Exam-style practice questions
Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2024 SACE Stage 22 marksAn electron undergoes uniform circular motion in a uniform magnetic field directed into the plane of the page, perpendicular to its velocity. Explain why the electron undergoes uniform circular motion when it is in the uniform magnetic field.Show worked answer →
The magnetic force on a moving charge is F = q v B sin theta. Because the velocity is perpendicular to the field, this force has a constant magnitude.
The magnetic force always acts perpendicular to the velocity of the electron, so it does no work on the electron. The speed (and therefore the magnitude of the velocity) stays constant.
A constant magnitude force that is always perpendicular to the velocity acts as a centripetal force, continually changing the direction of motion while keeping the speed constant. This produces uniform circular motion.
1 mark for stating the magnetic force is always perpendicular to the velocity (so it changes direction not speed), 1 mark for identifying it as a centripetal force producing uniform circular motion.
2025 SACE Stage 22 marksA sigma particle with charge 1.60 x 10^-19 C and speed 6.53 x 10^5 m s-1 enters a uniform magnetic field perpendicularly. The magnitude of the magnetic field is 0.172 T. Calculate the magnitude of the force acting on the sigma particle as it enters the uniform magnetic field.Show worked answer →
The magnetic force on a moving charge is F = q v B sin theta. The particle enters perpendicular to the field, so theta = 90 degrees and sin theta = 1.
F = q v B = (1.60 x 10^-19)(6.53 x 10^5)(0.172).
F = (1.60 x 10^-19)(6.53 x 10^5)(0.172) = 1.80 x 10^-14 N.
1 mark for F = q v B, 1 mark for the answer of about 1.80 x 10^-14 N. This force is the centripetal force that makes the particle follow a circular path.