How are metals extracted from ores and protected from corrosion?
Describe methods of metal extraction and explain corrosion (rusting) of iron and methods used to prevent it.
How metals are extracted by reduction methods chosen by reactivity, the electrochemical mechanism of iron corrosion, and prevention methods including sacrificial protection and galvanising.
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What this dot point is asking
You must describe extraction methods, explain the electrochemistry of rusting, and evaluate corrosion-prevention methods.
Extraction by reduction
Most metals occur in ores as positive ions, so extraction means reduction - gaining electrons to form the metal. The method depends on how reactive the metal is.
- Reactive metals (e.g. aluminium, sodium) hold their ions strongly, so carbon cannot reduce them; they are extracted by electrolysis of the molten compound (aluminium from molten alumina).
- Less reactive metals (e.g. iron, zinc) can be reduced by heating the ore with carbon (coke), as in the blast furnace.
Corrosion of iron (rusting)
Rusting is an electrochemical process. Different parts of the iron surface act as anode and cathode, with a film of water as the electrolyte.
At the anode, iron is oxidised:
At the cathode, oxygen is reduced in the presence of water:
The is then further oxidised by oxygen to hydrated iron(III) oxide - rust.
Preventing corrosion
- Barrier methods keep out oxygen and water: painting, oiling, greasing or coating with plastic. They fail once scratched.
- Galvanising coats the iron with zinc. The zinc both acts as a barrier and, being more reactive, corrodes in preference to the iron even where the coating is scratched.
- Sacrificial protection attaches a more reactive metal (zinc or magnesium) to the iron. Being more easily oxidised, it corrodes instead of the iron, protecting it as long as the sacrificial metal lasts.
Exam-style practice questions
Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
2023 SACE Stage 22 marksNickel can be extracted from its minerals using carbon reduction, but lithium can only be extracted by electrolysis of a molten lithium mineral. Explain why it is possible to extract nickel from its minerals using carbon reduction while lithium can only be extracted by electrolysis.Show worked answer β
The extraction method depends on the reactivity of the metal.
Lithium is a very reactive metal (high in the activity series), so its compounds are very stable and it holds its electrons strongly. Carbon is not a strong enough reducing agent to remove the metal from its ore, so the stronger method of electrolysis must be used.
Nickel is much less reactive (lower in the activity series), so its oxide is less stable and carbon is a strong enough reducing agent to reduce nickel ions to the metal at high temperature. One mark for relating lithiums high reactivity to needing electrolysis, one for relating nickels lower reactivity to carbon reduction being sufficient.
2024 SACE Stage 21 marksDuring the electrolysis of a solution containing gallium cations, other cations such as sodium, magnesium, and aluminium are not affected. Using this information, suggest whether gallium is above or below aluminium in the metal activity series.Show worked answer β
Gallium is below aluminium in the metal activity series.
Because gallium ions are reduced (deposited) while aluminium, sodium, and magnesium ions are not, gallium ions are more easily reduced and gallium is less reactive than aluminium. A less reactive metal sits lower in the activity series, so gallium is below aluminium. One mark.
2023 SACE Stage 22 marksAfter concentration, the nickel(II) sulfide mineral, NiS, is heated in a furnace in the presence of oxygen-enriched air to produce nickel(II) oxide and the by-product sulfur dioxide. Write an equation for the reaction that occurs in the furnace.Show worked answer β
Write reactants and products, then balance.
2NiS + 3O2 -> 2NiO + 2SO2
Check: 2 Ni each side; 2 S each side; oxygen is 6 on the left (3 x O2) and 6 on the right (2 from NiO + 4 from 2SO2). One mark for correct reactants and products, one mark for correct balancing.