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SAChemistrySyllabus dot point

How does electrical energy drive non-spontaneous redox reactions in electrolysis?

Describe electrolytic cells, predict electrode products, and apply Faraday's relationships to calculate amounts in electrolysis.

How electrolytic cells use electrical energy to drive non-spontaneous redox reactions, how to predict the products at each electrode, and how to use charge and Faraday's constant in calculations.

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  1. What this dot point is asking
  2. How an electrolytic cell differs from a galvanic cell
  3. Predicting electrode products
  4. Quantitative electrolysis
  5. Applications

What this dot point is asking

You must describe how an electrolytic cell works, predict the products at each electrode, and carry out quantitative electrolysis calculations.

How an electrolytic cell differs from a galvanic cell

A galvanic cell produces electricity from a spontaneous reaction; an electrolytic cell consumes electricity to drive a non-spontaneous one. The electrode definitions by process are unchanged, but the signs swap.

Predicting electrode products

In molten ionic compounds, the only ions present are the cation and anion, so the metal is deposited at the cathode and the non-metal formed at the anode.

In aqueous solutions, water can also be oxidised or reduced, so it competes with the dissolved ions:

  • At the cathode, the more easily reduced species wins. Water is reduced to hydrogen unless a less reactive metal ion (e.g. Cu2+\text{Cu}^{2+}, Ag+\text{Ag}^+) is present, in which case the metal is deposited.
  • At the anode, water is oxidised to oxygen unless a halide ion is present in reasonable concentration, in which case the halogen tends to form.

Quantitative electrolysis

The charge passed is:

Q=ItQ = It

where QQ is charge (C), II is current (A) and tt is time (s). The moles of electrons are:

n(e)=QF,F=96500 C mol1n(e^-) = \frac{Q}{F}, \qquad F = 96\,500\ \text{C mol}^{-1}

Then use the half-equation to relate moles of electrons to moles of product.

Applications

Electrolysis is central to managing resources: extracting reactive metals (aluminium from molten alumina), purifying copper, and electroplating objects with a thin protective or decorative metal layer.

Exam-style practice questions

Practice questions written in the style of SACE Board exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2022 SACE Stage 23 marksBromine can be produced by electrolysis of molten magnesium bromide. Explain whether bromine is formed at the anode or at the cathode in the electrolysis of molten magnesium bromide.
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Identify the species, the type of process, and the electrode.

  1. Molten MgBr2 contains Mg2+ cations and Br- anions.

  2. Forming bromine (Br2) from Br- is an oxidation: 2Br- -> Br2 + 2e- (loss of electrons).

  3. Oxidation always occurs at the anode (the positive electrode in electrolysis). Therefore bromine is formed at the anode. One mark for recognising it is an oxidation, one for the half-equation, one for naming the anode.

2023 SACE Stage 22 marksA diagram shows an electrolytic cell producing hydrogen from acidified water. Write a half-equation for the reaction occurring at the cathode.
Show worked answer →

At the cathode, reduction occurs and hydrogen gas is produced. In acidified water the species reduced is the hydrogen ion:

2H+ + 2e- -> H2

One mark for the correct species and product, one mark for balancing both charge and atoms (two electrons, two H+).

2024 SACE Stage 21 marksGallium can be produced by electrolysis of a solution containing gallium cations. State whether the gallium is produced at the positive or negative electrode in the electrolysis.
Show worked answer →

Gallium metal is produced by reduction of gallium cations (Ga3+ + 3e- -> Ga), which gains electrons.

Reduction occurs at the cathode, which is the negative electrode in an electrolytic cell. So gallium is produced at the negative electrode. One mark.