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QLDSpecialist MathematicsUnit 3: Mathematical induction, and further vectors, matrices and complex numbers

Quick questions on Vectors in three dimensions, dot and cross products (QCE Specialist Mathematics Unit 3)

6short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is the dot (scalar) product?
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The dot product produces a scalar:
What is the cross (vector) product?
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The cross product produces a vector perpendicular to both inputs:
What are equations of lines?
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A line through point AA with position vector a\mathbf{a} and direction d\mathbf{d} has vector equation
What is properties of the dot product?
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The dot product is commutative, ab=ba\mathbf{a} \cdot \mathbf{b} = \mathbf{b} \cdot \mathbf{a}, and distributes over addition, a(b+c)=ab+ac\mathbf{a} \cdot (\mathbf{b} + \mathbf{c}) = \mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c}. A vector dotted with itself returns the square of its length, aa=a2\mathbf{a} \cdot \mathbf{a} = |\mathbf{a}|^2, which is the algebraic identity behind every magnitude calculation. The base vectors satisfy ii=jj=kk=1\mathbf{i} \cdot \mathbf{i} = \mathbf{j} \cdot \mathbf{j} = \mathbf{k} \cdot \mathbf{k} = 1 and ij=jk=ki=0\mathbf{i} \cdot \mathbf{j} = \mathbf{j} \cdot \mathbf{k} = \mathbf{k} \cdot \mathbf{i} = 0, because they are mutually perpendicular unit vectors. These identities let you expand a product such as (a+2b)(ab)=a2+ab2b2(\mathbf{a} + 2\mathbf{b}) \cdot (\mathbf{a} - \mathbf{b}) = |\mathbf{a}|^2 + \mathbf{a} \cdot \mathbf{b} - 2|\mathbf{b}|^2 without resorting to components, a move QCAA rewards in proof-style items.
What is properties of the cross product?
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The cross product is anti-commutative, a×b=(b×a)\mathbf{a} \times \mathbf{b} = -(\mathbf{b} \times \mathbf{a}), so the order matters and reversing it flips the direction of the normal. A vector crossed with itself or with a parallel vector gives the zero vector, a×a=0\mathbf{a} \times \mathbf{a} = \mathbf{0}, which is the algebraic test for parallel vectors. For the base vectors the cyclic rule holds: i×j=k\mathbf{i} \times \mathbf{j} = \mathbf{k}, j×k=i\mathbf{j} \times \mathbf{k} = \mathbf{i}, k×i=j\mathbf{k} \times \mathbf{i} = \mathbf{j}, with a sign change if you reverse any pair. Because a×b=absinθ|\mathbf{a} \times \mathbf{b}| = |\mathbf{a}||\mathbf{b}|\sin\theta equals the parallelogram area, half of it is the area of the triangle spanned by the two vectors, which is the standard route to a triangle area from three position vectors.
What is choosing the right product?
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The single most important decision in a vectors question is which product to use. Reach for the dot product whenever the question mentions an angle, perpendicularity, work done, or a projection, because the dot product converts directly into cosθ\cos\theta. Reach for the cross product whenever the question mentions a normal direction, an area, or a vector perpendicular to two others, because the cross product converts into sinθ\sin\theta and produces a vector. Stating which product you will use and why is itself worth communication credit in extended-response items.

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