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QLDPhysicsSyllabus dot point

Topic 2: Waves

Describe the superposition of mechanical waves and explain constructive and destructive interference in terms of phase relationships

A focused answer to the QCE Physics Unit 2 dot point on superposition and interference. States the principle of superposition, links constructive and destructive interference to path-length difference and phase, and works the QCAA-style two-speaker interference problem from EA Paper 2.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The principle of superposition
  3. Constructive interference
  4. Destructive interference
  5. Path-length difference rule
  6. Where this leads next
  7. Examples in context
  8. Try this

What this dot point is asking

QCAA wants you to state the principle of superposition for mechanical waves and apply it to constructive and destructive interference. The link between path-length difference and phase is the key idea: integer wavelengths of path difference (for sources in phase) give a maximum, half-integer wavelengths give a minimum.

The principle of superposition

When two or more waves meet at a point, the total displacement of the medium at that point is the sum of the displacements that each wave would produce on its own.

This is a linear principle: it applies to mechanical waves with small amplitudes (water, sound, strings) and to electromagnetic waves in vacuum.

After superposing, the waves continue past one another unchanged. They do not interact, only their displacements add at the moment of overlap.

Constructive interference

When two waves meet in phase (peaks line up with peaks, troughs with troughs), the resultant amplitude is the sum of the individual amplitudes. The waves reinforce.

For two identical waves of amplitude AA, the resultant amplitude is 2A2A at points of full constructive interference. Wave energy depends on A2A^2, so the energy at a constructive maximum is 44 times the energy of either wave alone (not 22 times, because energy scales with the square of amplitude).

Destructive interference

When two waves meet exactly out of phase (peaks line up with troughs), the resultant amplitude is the difference of the individual amplitudes. For identical waves, the resultant is zero: total destructive interference.

Energy is not destroyed. It is redistributed to the constructive maxima elsewhere in the interference pattern.

Path-length difference rule

For two sources oscillating in phase at the same frequency, the type of interference at a point depends on the path-length difference Δd\Delta d:

  • Constructive: Δd=nλ\Delta d = n \lambda, where n=0,1,2,3,n = 0, 1, 2, 3, \ldots
  • Destructive: Δd=(n+12)λ\Delta d = (n + \tfrac{1}{2}) \lambda, where n=0,1,2,3,n = 0, 1, 2, 3, \ldots

If the sources are out of phase by half a cycle, swap the two rules.

Where this leads next

Superposition is the foundation for standing waves (next dot point), for diffraction patterns (which you will meet in Year 12), and for double-slit interference of light (Unit 4 quantum context). The same path-difference rule applies in all three.

Examples in context

Example 1. A QPAC sound technician sets up two stage speakers 3.0 m3.0 \text{ m} apart playing the same 680 Hz680 \text{ Hz} test tone (λ=0.50 m\lambda = 0.50 \text{ m}). At a point 4.0 m4.0 \text{ m} from one speaker and 4.25 m4.25 \text{ m} from the other, path difference is 0.25 m=λ/20.25 \text{ m} = \lambda/2, so destructive interference produces a quiet patch. Moving 0.25 m0.25 \text{ m} sideways shifts the path difference to 0.50 m=λ0.50 \text{ m} = \lambda for constructive (loud). QCAA EA Unit 2 thematic items use this two-source setup.

Example 2. A Sunshine Coast tidal study models wave interaction between an ocean swell and a tide-driven counter-flow at a river mouth. When the two surface-wave trains meet 180180^\circ out of phase at 1.2 Hz1.2 \text{ Hz}, amplitudes near-cancel; in phase they double, creating standing crests visible to drone surveys. The same superposition principle underpinning QCAA Unit 2 IA1 data-test stems works at any wavelength.

Try this

Q1. State the principle of superposition. [2 marks]

  • Cue. When two or more waves overlap, the resultant displacement is the algebraic sum of the individual displacements.

Q2. Two speakers emit 1700 Hz1700 \text{ Hz} tones in phase. Calculate the wavelength using v=340 m s1v = 340 \text{ m s}^{-1} and the path-difference required for destructive interference. [3 marks]

  • Cue. λ=0.20 m\lambda = 0.20 \text{ m}; destructive at (n+12)λ=0.10,0.30,0.50 m(n+\tfrac{1}{2})\lambda = 0.10, 0.30, 0.50 \text{ m}.

Q3. A QPAC two-speaker setup at 680 Hz680 \text{ Hz} (v=340 m s1v = 340 \text{ m s}^{-1}) is placed 3.0 m3.0 \text{ m} apart. (a) Calculate the wavelength. (b) Determine the path-difference for the first constructive maximum off-axis. (c) Explain why such interference is rarely heard outdoors and discuss one design consideration. [2+3+3 marks; ISMG: Analysis and interpretation, Evaluation]

  • Cue. (a) 0.50 m0.50 \text{ m}; (b) Δ=λ=0.50 m\Delta = \lambda = 0.50 \text{ m}; (c) reflections off ground/walls scramble phase, design uses directional baffles.

Exam-style practice questions

Practice questions written in the style of QCAA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Year 11 SAC4 marksTwo loudspeakers emit identical sound of frequency 686686 Hz in phase. A listener sits at a point that is 3.503.50 m from one speaker and 4.004.00 m from the other. Take the speed of sound as 343343 m s1^{-1}. Determine whether the listener experiences constructive or destructive interference.
Show worked answer →

Wavelength: λ=v/f=343/686=0.500\lambda = v / f = 343 / 686 = 0.500 m.

Path-length difference: Δd=4.003.50=0.50\Delta d = 4.00 - 3.50 = 0.50 m.

Ratio: Δd/λ=0.50/0.50=1\Delta d / \lambda = 0.50 / 0.50 = 1, an integer.

For sources in phase, integer wavelengths of path difference give constructive interference.

The listener experiences constructive interference (a maximum).

Markers reward computing λ\lambda from v=fλv = f \lambda, the explicit calculation of path-length difference, and the conclusion stated against the integer rule.

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