β Unit 2: Calculus and further functions
How is differential calculus introduced in QCE Math Methods Unit 2?
Introduction to differential calculus, including the gradient at a point, the derivative as a function, and the power rule for derivatives of polynomial functions
A focused answer to the QCE Math Methods Unit 2 subject-matter point on differential calculus. The gradient as the slope of a tangent, the derivative as a function, the power rule $d/dx(x^n) = nx^{n-1}$, and applications to tangent lines and stationary points; foundation for Unit 3 calculus.
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What this dot point is asking
QCAA wants Year 11 students to introduce differential calculus via the gradient concept, define the derivative, apply the power rule to polynomials, and classify stationary points using the first derivative.
The gradient and derivative
Average gradient between two points: .
Instantaneous gradient at : limit as of , equals .
The derivative is a function: at each , it gives the gradient of the tangent.
Power rule
For : .
Linearity: .
Constants: derivative of a constant is 0.
Tangents and normals
Tangent. Line at with gradient passing through : .
Normal. Perpendicular: gradient .
Stationary points
Where . Classify by sign of around the point:
- Positive to negative: local maximum.
- Negative to positive: local minimum.
- Same sign on both sides: stationary inflection.
Common errors
Power rule on , , . Power rule applies to , not these (introduced in Unit 3).
Forgetting to set for stationary points. Stationary means zero gradient.
Tangent gradient confused with function value. is value; is gradient.
In one sentence
Differential calculus is introduced in Unit 2 through the gradient at a point (limit of average gradients, equal to ), the derivative as a function obtained via the power rule extended by linearity to polynomial sums, with applications to tangent lines and stationary points (found by solving and classified by the sign of ).
Past exam questions, worked
Real questions from past QCAA papers on this dot point, with our answer explainer.
Year 11 SAC4 marksFor $f(x) = x^3 - 3x^2 + 2$, find (a) $f'(x)$, (b) the gradient at $x = 2$, (c) the stationary points.Show worked answer β
(a) .
(b) .
(c) : , or .
At : . At : .
Sign of : positive for , negative for , positive for . So is a local max (); is a local min ().
Markers reward the derivative, the stationary points by solving , and classification using the sign of .
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