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QLDMath MethodsSyllabus dot point

What functions and graphs does QCE Math Methods Unit 1 introduce, and how are they analysed?

Functions and graphs introduced in Year 11, including linear, quadratic, cubic, polynomial, exponential and logarithmic functions; their key features, intercepts and transformations

A focused answer to the QCE Math Methods Unit 1 subject-matter point on functions and graphs. Linear, quadratic, polynomial, exponential and logarithmic functions; identification of intercepts, turning points and asymptotes; the four standard transformations; foundation for Unit 3 / 4 calculus work.

Generated by Claude OpusReviewed by Better Tuition Academy8 min answer

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What this dot point is asking

QCAA wants Year 11 students to recognise the major function families, identify their key features, and apply the four standard transformations. Foundation for Unit 3 / 4 calculus work.

Function families

Linear y=mx+cy = mx + c. Straight line, gradient mm, yy-intercept cc.

Quadratic y=ax2+bx+cy = ax^2 + bx + c or vertex form y=a(xβˆ’h)2+ky = a(x - h)^2 + k. Parabola, turning point (h,k)(h, k).

Cubic y=ax3+bx2+cx+dy = ax^3 + bx^2 + cx + d. Up to two turning points; can be monotonic.

Polynomial. Degree nn polynomial has up to nβˆ’1n - 1 turning points.

Exponential y=axy = a^x for a>0,a≠1a > 0, a \neq 1. Always positive, horizontal asymptote y=0y = 0.

Logarithmic y=log⁑a(x)y = \log_a(x). Defined for x>0x > 0, vertical asymptote x=0x = 0, inverse of exponential.

Key features to identify

  • Domain and range.
  • IMATH_16 - and yy-intercepts.
  • Turning points / stationary points.
  • Asymptotes (vertical, horizontal).
  • End behaviour.

The four standard transformations

Given y=f(x)y = f(x):

Translation in yy. y=f(x)+ky = f(x) + k shifts up by kk.

Translation in xx. y=f(xβˆ’h)y = f(x - h) shifts right by hh.

Dilation in yy. y=af(x)y = af(x) stretches vertically by factor aa.

Dilation in xx. y=f(bx)y = f(bx) compresses horizontally by factor 1/b1/b.

Reflections are special cases (aa or bb negative).

Worked example

y=3(xβˆ’2)3βˆ’5y = 3(x - 2)^3 - 5. Start with y=x3y = x^3. Apply:

  • Translation right by 2.
  • Vertical stretch by 3.
  • Translation down by 5.

Inflection point at (2,βˆ’5)(2, -5).

Common errors

Translation sign error. f(xβˆ’h)f(x - h) shifts right by hh, not left.

Wrong transformation order. Apply inside-the-bracket first (operations on xx), then outside (operations on yy).

Forgetting asymptotes. Exponentials have horizontal asymptotes; logs have vertical asymptotes. Mark them.

In one sentence

Unit 1 introduces the major function families (linear, quadratic, polynomial, exponential, logarithmic) and the four standard transformations (translation and dilation in both xx and yy); sketching requires all key features (intercepts, turning points, asymptotes, end behaviour) labelled.

Past exam questions, worked

Real questions from past QCAA papers on this dot point, with our answer explainer.

Year 11 SAC4 marksSketch $y = -2(x - 3)^2 + 8$, labelling the turning point, $y$-intercept and any $x$-intercepts.
Show worked answer β†’

Vertex form y=a(xβˆ’h)2+ky = a(x - h)^2 + k. Turning point (3,8)(3, 8). Opens downward (a=βˆ’2<0a = -2 < 0).

yy-intercept: y=βˆ’2(0βˆ’3)2+8=βˆ’2(9)+8=βˆ’10y = -2(0 - 3)^2 + 8 = -2(9) + 8 = -10. Intercept: (0,βˆ’10)(0, -10).

xx-intercepts: βˆ’2(xβˆ’3)2+8=0-2(x - 3)^2 + 8 = 0, so (xβˆ’3)2=4(x - 3)^2 = 4, xβˆ’3=Β±2x - 3 = \pm 2, x=1x = 1 or x=5x = 5.

Sketch: downward parabola with turning point (3,8)(3, 8), xx-intercepts at (1,0)(1, 0) and (5,0)(5, 0), yy-intercept at (0,βˆ’10)(0, -10).

Markers reward correct turning point identification from vertex form, both intercepts, and shape.

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