Module 7: The Nature of Light

NSWPhysicsSyllabus dot point

Inquiry Question 2: What is observed when light interacts with matter?

Investigate emission and absorption spectra, distinguish continuous, line emission and line absorption spectra, and analyse stellar spectra to identify chemical composition, surface temperature and motion

A focused answer to the HSC Physics Module 7 dot point on spectroscopy. Continuous, emission-line and absorption-line spectra explained by quantised atomic energy levels, plus how stellar spectra reveal chemical composition, surface temperature, rotation and radial velocity (Doppler shift).

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What this dot point is asking

NESA wants you to know the three types of spectrum, why atomic energy levels are quantised, and how spectroscopy is used to determine the composition, temperature and motion of stars. You should be able to read an absorption line in a stellar spectrum and explain what it tells you.

The answer

Quantised atomic energy levels

Electrons in atoms occupy discrete energy levels E1,E2,E3,E_1, E_2, E_3, \dots When an electron drops from a higher level EiE_i to a lower level EfE_f, a photon of energy:

hf=EiEfh f = E_i - E_f

is emitted. The reverse is absorption: an electron absorbs a photon of exactly the right energy and jumps to a higher level. Because the levels are discrete, only certain photon energies (and therefore wavelengths) appear in atomic spectra. Each element has a characteristic set of levels and therefore a unique spectral "fingerprint".

Three types of spectrum (Kirchhoff's laws, 1859)

Continuous spectrum. A hot dense object (a glowing solid, liquid or high-pressure gas, or the interior of a star) emits a smooth distribution of wavelengths. The peak wavelength shifts with temperature (Wien's law); the total intensity follows the Stefan-Boltzmann law. The spectrum approximates a blackbody curve.

Line emission spectrum. A hot, low-density gas (a discharge lamp, the corona of a star, a nebula) emits only at specific wavelengths corresponding to its atoms' allowed downward transitions. The spectrum looks like bright lines on a dark background.

Line absorption spectrum. Continuum light passing through a cool gas loses the photons whose energies match the gas atoms' allowed upward transitions. The result is a continuous spectrum crossed by dark lines (Fraunhofer lines). Stellar spectra are predominantly of this type: the photosphere produces near-continuum light that is absorbed by the cooler outer atmosphere.

What stellar spectra reveal

A typical stellar spectrum is analysed for four things:

Chemical composition. Identify the absorption lines by wavelength and match to laboratory spectra. The most prominent lines in a Sun-like star are hydrogen Balmer lines (H-alpha at 656.3656.3 nm), neutral sodium, ionised calcium, magnesium and iron lines. Helium was discovered in 1868 from a solar absorption line that did not match any known terrestrial element.

Surface temperature. The relative strengths of different lines depend on temperature, because each transition has an optimal temperature for being populated. The shape of the underlying continuum (Wien's law: λpeakT=\lambda_{\text{peak}} T = constant) gives an independent temperature estimate. Together these classify stars into the spectral sequence O, B, A, F, G, K, M, from hottest (blue-white) to coolest (red).

Radial velocity (line of sight). All lines are shifted from their laboratory wavelengths by the Doppler effect:

Δλλ0=vc(for vc)\frac{\Delta \lambda}{\lambda_0} = \frac{v}{c} \quad \text{(for } v \ll c\text{)}

A redshift (λobs>λ0\lambda_{\text{obs}} > \lambda_0) means the source is receding; a blueshift (λobs<λ0\lambda_{\text{obs}} < \lambda_0) means it is approaching. This is how we know about the expansion of the universe (Hubble) and detect orbiting exoplanets (the star wobbles).

Rotation. A rotating star has one limb moving toward us and the other away, so each spectral line is broadened symmetrically into a profile whose width measures the equatorial rotation speed.

Other inferences include surface gravity (from line widths sensitive to pressure broadening), magnetic field (Zeeman splitting of lines) and turbulent motion.

Worked example: identifying composition

A stellar absorption spectrum shows strong lines at 588.99588.99 nm and 589.59589.59 nm. These match the laboratory sodium D doublet, so the star's atmosphere contains sodium. Comparing the doublet positions to laboratory values gives the radial velocity by the Doppler formula above.

Diffraction grating spectrometers

In practice, spectra are recorded by sending starlight through a slit, collimating it, dispersing it with a prism or diffraction grating, and imaging the result onto a CCD. A diffraction grating with line spacing dd produces principal maxima at:

dsinθ=mλd \sin \theta = m \lambda

so different wavelengths emerge at different angles and can be measured precisely. Gratings give much higher resolution than prisms and are standard in modern astrophysics.

Common traps

Conflating absorption and reflection. A dark Fraunhofer line means light is missing from the transmitted beam, not that the star reflects that wavelength.

Saying continuous spectra come from any gas. They come from hot dense matter. A low-density gas at the same temperature gives line emission only.

Quoting redshift as "the star is moving away from the universe". Redshift means radial velocity away from the observer (line-of-sight component), not total motion.

Forgetting that the same atom can produce both an emission and an absorption spectrum. Whether the transition is observed as emission or absorption depends on whether the gas is hot and observed against a dark background or cool and observed against a continuum.

Treating spectral type as the only temperature indicator. Spectral type and Wien's-law peak wavelength are independent measures and should agree.

In one sentence

Spectroscopy uses the discrete photon energies hf=EiEfh f = E_i - E_f from atomic transitions to produce element-specific emission and absorption line spectra; analysing the lines in starlight reveals stellar composition, surface temperature, radial velocity (Doppler shift) and rotation.

Past exam questions, worked

Real questions from past NESA papers on this dot point, with our answer explainer.

2023 HSC4 marksDistinguish between continuous, line emission and line absorption spectra, and explain how an absorption line in the spectrum of a star can identify an element in the star's atmosphere.
Show worked answer →

Continuous spectrum: a smooth rainbow of all wavelengths, produced by a hot dense source (an incandescent solid, liquid or compressed gas) where the energy levels are smeared together by close packing.

Line emission spectrum: a series of bright lines on a dark background at specific wavelengths, produced by a hot, low-pressure gas. The lines correspond to photons released as electrons drop from higher to lower discrete energy levels in the atoms, Ephoton=EiEf=hfE_{\text{photon}} = E_i - E_f = h f.

Line absorption spectrum: a continuous spectrum crossed by dark lines at specific wavelengths, produced when continuum light passes through a cool gas. Electrons in the cool gas absorb only those photons whose energies exactly match the gas atoms' allowed transitions, removing those wavelengths from the transmitted beam.

A star produces continuum light from its hot dense interior, which passes through the cooler stellar atmosphere. Atoms in the atmosphere absorb the wavelengths matching their characteristic transitions, leaving dark lines in the stellar spectrum. Each element has a unique fingerprint, so matching the observed absorption-line wavelengths to laboratory spectra identifies the elements present (this is how helium was discovered in the Sun in 1868, before being found on Earth).

Markers reward all three spectrum types correctly described with examples, plus the absorption-by-atmosphere mechanism and the fingerprint-matching idea.

2019 HSC3 marksA hydrogen absorption line that has a laboratory wavelength of 656.3 nm is observed in a distant galaxy at 689.1 nm. Calculate the radial velocity of the galaxy and state whether it is moving toward or away from Earth.
Show worked answer →

Redshift fraction:

z=Δλ/λ0=(689.1656.3)/656.3=32.8/656.3=0.0500z = \Delta \lambda / \lambda_0 = (689.1 - 656.3) / 656.3 = 32.8 / 656.3 = 0.0500.

For vcv \ll c, the non-relativistic Doppler formula gives:

v=zc=0.0500×3.00×108=1.5×107v = z c = 0.0500 \times 3.00 \times 10^8 = 1.5 \times 10^7 m/s.

Sign and direction: the observed wavelength is longer than the laboratory wavelength (redshift), so the galaxy is receding from Earth at about 1.5×1071.5 \times 10^7 m/s.

Markers reward the formula, correct value of zz, conversion to velocity, and identification of "receding" because of the redshift. Some answers will use the relativistic Doppler formula; at v/c=0.05v / c = 0.05 the correction is small (0.1%\sim 0.1\%).

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