Module 6: Electromagnetism

NSWPhysicsSyllabus dot point

Inquiry Question 3: Under what circumstances is an electrical voltage generated by a magnetic field?

Describe and quantitatively analyse electromagnetic induction using Faraday's law (induced EMF = - N dPhi/dt) and Lenz's law, including motional EMF, eddy currents and the induction coil

A focused answer to the HSC Physics Module 6 dot point on electromagnetic induction. Faraday's law as EMF = -N dPhi/dt, Lenz's law and conservation of energy, motional EMF in a moving rod, eddy currents and damping, and the induction coil as a stepped-up pulse source.

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What this dot point is asking

NESA wants you to state Faraday's law in the form ε=NdΦ/dt\varepsilon = -N \, d\Phi / dt, apply Lenz's law to determine the direction of an induced current, work with motional EMF (ε=BLv\varepsilon = BLv) as a special case, and explain qualitatively where eddy currents and the induction coil sit in the same framework. Faraday's law is the keystone of the rest of Module 6: transformers and motors all rely on it.

The answer

Faraday's law

For a single conducting loop linked by a magnetic flux Φ(t)\Phi(t), the induced EMF around the loop is:

ε=dΦdt\varepsilon = -\frac{d\Phi}{dt}

For a coil of NN turns, each turn intercepts the same flux, so the EMFs add in series and the total induced EMF is:

ε=NdΦdt\boxed{\varepsilon = -N \frac{d\Phi}{dt}}

The flux through one turn is Φ=BAcosθ\Phi = B A \cos \theta. Anything that changes BB, AA or θ\theta produces an EMF:

  • Changing BB: a magnet moved toward or away from a stationary coil, or a changing current in a nearby circuit (the basis of the transformer).
  • Changing AA: a conducting rod sliding on rails to enlarge or shrink the circuit area (motional EMF).
  • Changing θ\theta: a coil rotated in a steady field (the AC generator).

The minus sign encodes Lenz's law.

Lenz's law

The induced EMF and induced current always act in a direction that opposes the change in flux that produced them.

In practice, to find the direction of the induced current:

  1. Identify the direction of the external flux through the coil and whether it is increasing or decreasing.
  2. The induced current produces its own magnetic field inside the coil; it points opposite to the external field if external flux is increasing, and along the external field if external flux is decreasing.
  3. Use the right-hand rule for a current loop (fingers curl with current, thumb along its magnetic field) to read off the direction of the induced current itself.

Lenz's law is a statement of energy conservation. If the induced current reinforced the change in flux, it would accelerate the motion or amplify the field that caused it, creating energy from nothing.

Motional EMF

A conducting rod of length LL moving with velocity vv perpendicular to a uniform field BB (and with LL, vv and BB mutually perpendicular) has free charges in it experiencing a magnetic force F=qvBF = qvB along the rod. Charge separates until an electric field inside the rod balances the magnetic force. The resulting EMF between the ends of the rod is:

ε=BLv\varepsilon = B L v

This is exactly the Faraday's law result for the case where the rod is part of a circuit and slides to change the enclosed area: dΦ/dt=BdA/dt=BLvd\Phi / dt = B \, dA / dt = B L v.

If the rod is part of a closed circuit of resistance RR, the induced current is I=ε/RI = \varepsilon / R, and the magnetic force on this current-carrying rod opposes the motion (Lenz's law again).

Eddy currents

When a bulk conductor (a sheet, disc or block of metal) experiences a changing flux, induced EMFs drive circulating currents called eddy currents inside the conductor. They oppose the change in flux that produced them, so they exert a drag force on whatever is causing the flux change.

Examples:

  • Magnetic braking. A conducting disc spinning between the poles of a magnet has currents induced in it. These currents experience a magnetic force opposing the rotation, slowing the disc. Used in train brakes and gym equipment.
  • Induction cooktops. A high-frequency AC field induces eddy currents in the base of a ferromagnetic pot, dissipating energy as heat directly in the pot.
  • Aluminium-tube demo. A magnet dropped down an aluminium tube falls slowly because eddy currents in the tube wall oppose the change in flux as the magnet moves.

Eddy currents are useful for braking and heating, but they are unwanted losses in transformer cores and motor armatures. To reduce them, the iron in those devices is laminated (thin sheets electrically insulated from each other), which breaks the eddy-current paths.

The induction coil

An induction coil is a transformer-like device used to produce high-voltage pulses from a low-voltage DC source. It has:

  1. A primary coil of relatively few turns wound on a soft iron core.
  2. A secondary coil of many more turns wound on the same core.
  3. An interrupter (a mechanical or electronic switch) that rapidly opens and closes the primary circuit.

Each time the interrupter breaks the primary current, the primary's magnetic field collapses rapidly, producing a fast dΦ/dtd\Phi / dt through the secondary. With the large turns ratio, the induced secondary EMF can be tens of kilovolts, enough to produce a spark across an air gap.

Historically used for X-ray tubes and Tesla coils. Modern car ignition coils work on the same principle: the breaker (or transistor) interrupts the primary 12 V supply many times per second, producing tens of kilovolts at the spark plugs.

Worked example: rotating coil

A 100-turn rectangular coil of area 0.0200.020 m2^2 rotates at 5050 Hz in a uniform field of 0.100.10 T. Find the peak induced EMF.

The flux through one turn is Φ(t)=BAcos(ωt)\Phi(t) = B A \cos(\omega t), where ω=2πf=2π×50=314\omega = 2 \pi f = 2 \pi \times 50 = 314 rad/s.

ε=NdΦdt=NBAωsin(ωt)\varepsilon = -N \frac{d\Phi}{dt} = N B A \omega \sin(\omega t).

Peak EMF:

εmax=NBAω=100×0.10×0.020×314=63\varepsilon_{\max} = N B A \omega = 100 \times 0.10 \times 0.020 \times 314 = 63 V.

This is the operating principle of the AC generator: a constant-magnitude EMF that varies sinusoidally with the rotation angle.

Try it: Induced EMF calculator for change in flux, turns and time.

Common traps

Dropping the NN for multi-turn coils. A 100-turn coil with a flux change of 1 Wb produces 100 times more EMF than a single loop with the same change.

Forgetting the minus sign or misusing it. The minus sign encodes Lenz's law. Most numerical problems ask for the magnitude; a separate sentence then explains direction using Lenz's law.

Confusing flux change with flux. A large steady flux produces no EMF. Only a changing flux does.

Saying the induced current "opposes the field." It opposes the change in flux, not the field itself. If the external field is decreasing, the induced current reinforces it (it points the same way as the original field).

Mixing up motional EMF and Faraday's law as if they were two separate things. They are the same law; motional EMF is what Faraday's law gives when the changing flux is due to a changing area in a steady field.

Treating eddy-current heating as a separate phenomenon. It is Faraday's law applied to a bulk conductor, plus resistive dissipation of the induced currents.

In one sentence

A changing magnetic flux through a circuit induces an EMF ε=NdΦ/dt\varepsilon = -N \, d\Phi / dt (Faraday's law) directed to oppose the change that produced it (Lenz's law); special cases include motional EMF ε=BLv\varepsilon = BLv in a moving rod and eddy currents in a bulk conductor.

Past exam questions, worked

Real questions from past NESA papers on this dot point, with our answer explainer.

2023 HSC4 marksA 200-turn rectangular coil of area 0.015 m^2 sits with its normal aligned with a magnetic field. The field strength changes uniformly from 0.30 T to 0.80 T over 0.20 s. Calculate the magnitude of the induced EMF and explain, using Lenz's law, the direction of the induced current.
Show worked answer →

Change in flux per turn:

ΔΦ=AΔB=0.015×(0.800.30)=7.5×103\Delta \Phi = A \, \Delta B = 0.015 \times (0.80 - 0.30) = 7.5 \times 10^{-3} Wb.

Magnitude of induced EMF (Faraday's law):

ε=NΔΦΔt=200×7.5×1030.20=7.5|\varepsilon| = N \frac{\Delta \Phi}{\Delta t} = 200 \times \frac{7.5 \times 10^{-3}}{0.20} = 7.5 V.

Direction by Lenz's law: the external flux through the coil is increasing in the direction of the original field, so the induced current must produce a magnetic field that opposes the increase, that is, a field pointing opposite to the external field inside the coil. Curling the right-hand fingers in the direction of the induced current with the thumb opposite to B\vec{B} gives the sense of the current loop.

Markers reward correct change in flux, application of Faraday's law with the factor of NN, the answer in volts, and a clear Lenz's law statement linking opposition to the change (not opposition to the field itself).

2020 HSC5 marksA conducting rod of length 0.40 m slides at 3.0 m/s along frictionless parallel rails perpendicular to a uniform magnetic field of 0.25 T directed into the page. The rails are connected at one end through a 2.0 ohm resistor. Calculate the induced EMF, the current in the circuit, and the force needed to keep the rod moving at constant velocity.
Show worked answer →

Motional EMF:

ε=BLv=0.25×0.40×3.0=0.30\varepsilon = B L v = 0.25 \times 0.40 \times 3.0 = 0.30 V.

Induced current:

I=ε/R=0.30/2.0=0.15I = \varepsilon / R = 0.30 / 2.0 = 0.15 A.

The current in the rod sits in the external field, so there is a magnetic force on the rod. By Lenz's law it opposes the motion (otherwise energy would be created from nothing):

F=BIL=0.25×0.15×0.40=1.5×102F = B I L = 0.25 \times 0.15 \times 0.40 = 1.5 \times 10^{-2} N.

To maintain constant velocity (zero net force on the rod), an external agent must push with 1.5×1021.5 \times 10^{-2} N in the direction of motion. The mechanical power input P=Fv=1.5×102×3.0=4.5×102P = F v = 1.5 \times 10^{-2} \times 3.0 = 4.5 \times 10^{-2} W equals the electrical power dissipated P=εI=0.30×0.15=4.5×102P = \varepsilon I = 0.30 \times 0.15 = 4.5 \times 10^{-2} W, confirming energy conservation.

Markers reward the motional-EMF formula, Ohm's law step, the opposing-force direction by Lenz's law, and the energy-balance check.

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