Module 6: Electromagnetism

NSWPhysicsSyllabus dot point

Inquiry Question 3: Under what circumstances is an electrical voltage generated by a magnetic field?

Describe how magnetic flux can be sensed by the changing alignment of a magnet on a compass needle and quantitatively analyse the concept of magnetic flux density B and flux Phi = B A cos theta in a magnetic field

A focused answer to the HSC Physics Module 6 dot point on magnetic flux. The definitions of flux density B (tesla) and magnetic flux Phi (weber), the cosine factor for tilted loops, and a worked rotating-coil example with the right traps highlighted.

Generated by Claude OpusReviewed by Better Tuition Academy7 min answer

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What this dot point is asking

NESA wants you to distinguish magnetic flux density BB (the field at a point, in tesla) from magnetic flux Φ\Phi (the total field through a surface, in weber), apply Φ=BAcosθ\Phi = B A \cos \theta correctly, and connect this concept to the qualitative idea of a compass needle responding to field direction. Flux is the bridge to Faraday's law in the next dot point.

The answer

Magnetic flux density B

The magnetic flux density (often just called the magnetic field) B\vec{B} at a point is a vector describing the strength and direction of the magnetic field there. It is what a compass needle aligns with, and it determines the force on a moving charge (F=qvBF = qvB) or on a current (F=BILsinθF = BIL \sin \theta).

SI unit: the tesla (T). Equivalent forms:

1 T=1Wbm2=1NA m=1kgA s21 \text{ T} = 1 \frac{\text{Wb}}{\text{m}^2} = 1 \frac{\text{N}}{\text{A m}} = 1 \frac{\text{kg}}{\text{A s}^2}

Typical magnitudes:

  • Earth's surface field: about 5×1055 \times 10^{-5} T.
  • Bar magnet near a pole: 0.01 to 0.1 T.
  • MRI scanner: 1.5 to 3 T (some research machines reach 7 T).
  • Strong laboratory electromagnet: up to 10 T.
  • Neutron star: 10810^8 T (and rising).

Magnetic flux

For a flat surface of area AA placed in a uniform field B\vec{B}, the magnetic flux through the surface is:

Φ=BAcosθ\Phi = B A \cos \theta

where θ\theta is the angle between B\vec{B} and the normal to the surface (the vector perpendicular to the surface). SI unit: the weber (Wb), where 1 Wb = 1 T m2^2.

Two ways to picture it:

  1. Flux is the "amount of field passing through" the surface. More field, more area, or more alignment with the surface normal all increase flux.
  2. Flux is the dot product Φ=BA\Phi = \vec{B} \cdot \vec{A}, where A\vec{A} is the area vector (magnitude AA, direction along the normal).

Special angles:

  • IMATH_19 (field along the normal): Φ=BA\Phi = BA, maximum flux.
  • IMATH_21 (field in the plane of the surface): Φ=0\Phi = 0, no flux through the surface.
  • IMATH_23 : Φ=BA\Phi = -BA, maximum negative flux (the field passes through the surface in the opposite sense).

The angle convention (watch this)

The θ\theta in Φ=BAcosθ\Phi = B A \cos \theta is the angle between B\vec{B} and the normal to the surface, not between B\vec{B} and the surface itself. Questions sometimes give the angle between the field and the plane of a coil; you must take the complement.

"Plane at 30° to the field" \Rightarrow normal at 60° to the field \Rightarrow cos60°=0.5\cos 60° = 0.5.

"Normal at 30° to the field" \Rightarrow cos30°=0.866\cos 30° = 0.866.

Flux through multiple turns

A coil of NN turns links flux NN times (each turn intercepts the same flux, in series). The flux linkage is:

Ψ=NΦ=NBAcosθ\Psi = N \Phi = N B A \cos \theta

Faraday's law uses flux linkage: ε=NdΦ/dt\varepsilon = - N \, d\Phi / dt, not just dΦ/dtd\Phi / dt. We treat this in the induction dot point.

Compass needles and flux qualitatively

A compass needle is a small magnetic dipole. It aligns with the local field direction so that its north pole points along B\vec{B}. By placing compasses (or sprinkling iron filings) over a region you can map the direction of B\vec{B} at every point, hence the field line pattern. The density of the lines (lines per unit area perpendicular to them) is proportional to the flux density BB, hence the name.

If you tilt a small loop of wire in a uniform field while watching the field lines, the number of lines threading the loop changes as cosθ\cos \theta. That is the geometric content of Φ=BAcosθ\Phi = BA \cos \theta.

Worked example: rotating coil

A square coil of side 0.200.20 m and 5050 turns is rotated in a uniform field of 0.300.30 T. Find the maximum flux linkage and the flux linkage when the coil normal is at 45°45° to the field.

Area: A=0.202=0.040A = 0.20^2 = 0.040 m2^2.

Maximum flux linkage (normal aligned with field, θ=0°\theta = 0°):

Ψmax=NBA=50×0.30×0.040=0.60\Psi_{\max} = N B A = 50 \times 0.30 \times 0.040 = 0.60 Wb.

At θ=45°\theta = 45°:

Ψ=NBAcos45°=0.60×0.707=0.42\Psi = N B A \cos 45° = 0.60 \times 0.707 = 0.42 Wb.

As the coil rotates, the flux linkage oscillates between +0.60+0.60 Wb and 0.60-0.60 Wb, with the rate of change driving the induced EMF in a generator (Faraday's law).

Common traps

Confusing BB and Φ\Phi. BB is a field strength per unit area; Φ\Phi is a total field through an area. They have different units (T vs Wb).

Using the angle to the surface instead of to the normal. Questions love to phrase the geometry as "the coil is at 60 degrees to the field," meaning the plane of the coil is at 60 degrees, so the normal is at 30 degrees. Always check what θ\theta refers to before substituting into cos\cos.

Forgetting the NN for a multi-turn coil. A 100-turn coil with 1 Wb through each turn has 100 Wb of flux linkage, not 1 Wb. For Faraday's law, you must use NΦN \Phi or apply the NN outside the derivative.

Treating flux as a vector. Flux Φ\Phi is a scalar. The direction information is buried in the sign through cosθ\cos \theta (positive or negative depending on orientation).

Quoting flux as the dot product without specifying the area direction. Always state which way the area normal points; a flipped normal flips the sign of flux but does not change physics.

In one sentence

Magnetic flux density BB is the local field strength (tesla, T = Wb/m2^2), and magnetic flux Φ=BAcosθ\Phi = B A \cos \theta (weber, Wb = T m2^2) is the total field threading a surface of area AA whose normal lies at angle θ\theta to B\vec{B}.

Past exam questions, worked

Real questions from past NESA papers on this dot point, with our answer explainer.

2023 HSC3 marksA circular loop of radius 0.10 m sits in a uniform magnetic field of 0.50 T. Calculate the magnetic flux through the loop when its plane is (a) perpendicular to the field and (b) at 30 degrees to the field.
Show worked answer →

Area of the loop:

A=πr2=π(0.10)2=3.14×102A = \pi r^2 = \pi (0.10)^2 = 3.14 \times 10^{-2} m2^2.

(a) Plane perpendicular to the field means the field passes through the loop along its normal, so θ=0°\theta = 0° between B\vec{B} and the area vector:

Φ=BAcos0°=0.50×3.14×102×1=1.57×102\Phi = B A \cos 0° = 0.50 \times 3.14 \times 10^{-2} \times 1 = 1.57 \times 10^{-2} Wb.

(b) "Plane at 30° to the field" means the field makes 30° with the plane, so the normal makes 60° with the field:

Φ=BAcos60°=0.50×3.14×102×0.5=7.85×103\Phi = B A \cos 60° = 0.50 \times 3.14 \times 10^{-2} \times 0.5 = 7.85 \times 10^{-3} Wb.

Markers reward correct interpretation of "plane at X degrees to field" versus "normal at X degrees to field," correct area calculation, and units in webers.

2018 HSC2 marksExplain the difference between magnetic flux density B and magnetic flux Phi, and state the SI units of each.
Show worked answer →

Magnetic flux density BB is a vector quantity describing the strength and direction of the magnetic field at a point. Its SI unit is the tesla (T), where 1 T = 1 Wb/m2^2 = 1 N/(A m). It tells you the force per unit current per unit length on a conductor placed at that point, or the force per unit charge per unit velocity on a moving charge.

Magnetic flux Φ\Phi is a scalar quantity describing the total magnetic field passing through a surface of area AA. Its SI unit is the weber (Wb), where 1 Wb = 1 T m2^2. It is given by Φ=BAcosθ\Phi = B A \cos \theta, where θ\theta is the angle between the field direction and the normal to the surface.

Markers reward correct units for both, the area dependence of flux, and a clear statement that BB is per unit area and Φ\Phi is over the whole area.

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