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Module 7: The Nature of Light

Quick questions on Quantum model of light and the photoelectric effect: HSC Physics Module 7

12short Q&A pairs drawn directly from our worked dot-point answer. For full context and worked exam questions, read the parent dot-point page.

What is setting the scene?
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By the late 1800s the wave model of light was the standard. But in 1887 Heinrich Hertz noticed UV light striking metal electrodes increased the spark distance in his radio-wave apparatus. Lenard's careful experiments (1902) revealed three features the wave model could not explain:
What is einstein's photon hypothesis (1905)?
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Building on Planck's 1900 idea that energy is exchanged in discrete amounts $h f$, Einstein proposed that light itself is made of discrete energy packets:
What is threshold frequency?
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The minimum frequency that can eject any electron is the one where $KE_{\max} = 0$:
What is stopping voltage?
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In the standard experiment, a positive collector electrode is gradually reverse-biased until the most energetic photoelectrons are turned back. The reversing voltage at which photocurrent vanishes is the stopping voltage $V_s$:
What is worked example?
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Caesium has work function $\phi = 2.10$ eV. Calculate the maximum kinetic energy and stopping voltage when light of wavelength $400$ nm illuminates the cathode.
What is why the wave model fails?
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Three predictions of the classical wave model are flatly contradicted:
What is planck's constant?
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$h = 6.626 \times 10^{-34}$ J s is the universal constant relating frequency to energy quantum. It also appears in:
What is writing $h f = \phi - KE_{\max}$?
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The signs are: photon energy in, work function out, kinetic energy out. So $h f = \phi + KE_{\max}$.
What is saying intensity increases the electron energy?
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Intensity sets the photon flux (number per second), so it sets the current, not the energy per electron.
What is mixing up frequency and wavelength?
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Higher frequency = shorter wavelength = more energetic photon. Threshold frequency $f_0$ corresponds to maximum (cut-off) wavelength $\lambda_0 = c / f_0$.
What is quoting $\phi$ as the ionisation energy of the metal atom?
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It is the work function of the bulk metal: the energy needed to remove an electron from the metal surface to a stationary state just outside.
What is saying photoelectrons are "freed" when photons "shake" the electrons loose?
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Each photon is absorbed entire by one electron in a single quantum event; there is no shaking.

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