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NSWMaths Standard 2Syllabus dot point

How do world time zones work as offsets from Coordinated Universal Time, and how do you find the local time in another city by adding to the east, subtracting to the west and allowing for daylight saving?

Understand and use Coordinated Universal Time (UTC) and the relationship between time zones around the world expressed as offsets from UTC, including the link between longitude and time, to calculate the local time in different locations

A focused answer to the HSC Maths Standard 2 dot point on time zones and Coordinated Universal Time. UTC offsets, finding local time to the east (add) or west (subtract), allowing for daylight saving, and the longitude-to-time link of 15 degrees per hour, with worked Australian examples that track whether the answer lands on the previous or next day.

Generated by Claude Opus 4.814 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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What this dot point is asking

NESA wants you to treat every time zone as a simple offset from one global reference clock - Coordinated Universal Time, written UTC. Each place around the world keeps a local time that is a whole (or half) number of hours ahead of or behind UTC. Your job is to read those offsets, work out the difference between two places, and then add or subtract to find the local time somewhere else. The arithmetic is just adding and subtracting hours. The marks are won and lost on three decisions: choosing to add (going east) or subtract (going west), allowing for daylight saving when a place is on summer time, and tracking whether your answer slips back to the previous day or forward to the next day.

The answer

Picture one master clock at Greenwich in London showing UTC. Every other city's clock is set a fixed number of hours away from it, called its UTC offset. Sydney's winter clock is 1010 hours ahead, written UTC+10+10; Los Angeles is 88 hours behind, written UTC8-8. The whole topic reduces to one rule: places to the east are ahead (add), places to the west are behind (subtract). The further east you go, the earlier the Sun rises, so the later the clock already reads.

World time zones as offsets from UTCA horizontal strip of time-zone bands from west to east. Reading left to right the offset increases: Los Angeles at UTC minus 8, New York at UTC minus 5, UTC zero at Greenwich London, Dubai at UTC plus 4, Sydney at UTC plus 10. West of UTC the clocks are behind; east of UTC the clocks are ahead.West: behind (subtract) ← UTC → East: ahead (add)−8Los Angeles−5New York0UTC · London+4Dubai+10Sydneyoffset 0clocks behindclocks aheadLocal time = UTC + offset (offset is negative to the west)

Coordinated Universal Time and offsets

Coordinated Universal Time (UTC) is the world's reference clock; it does not change with the seasons and is the same everywhere at any instant. A city's local time is found from one equation:

local time=UTC+offset.\text{local time} = \text{UTC} + \text{offset}.

A positive offset (east of Greenwich) adds hours; a negative offset (west) subtracts them. So if UTC is 12:0012{:}00, then Dubai at UTC+4+4 reads 12:00+4=16:0012{:}00 + 4 = 16{:}00, and New York at UTC5-5 reads 12:005=7:0012{:}00 - 5 = 7{:}00. Australia spans three standard offsets in winter: AEST == UTC+10+10 for the east coast, ACST == UTC+9:30+9{:}30 for the centre (a half-hour zone), and AWST == UTC+8+8 for Perth.

Finding the time in another city directly

You rarely go via UTC in an exam; usually you jump straight from one city to another. The reliable method is two steps:

  1. Difference == subtract the two offsets (treat a negative offset as a negative number).
  2. Direction: the city with the larger offset is further east and is ahead (add to reach it); the city with the smaller offset is further west and is behind (subtract to reach it).

For Sydney (UTC+10+10) to Singapore (UTC+8+8), the difference is 108=210 - 8 = 2 hours and Singapore is behind, so Singapore time == Sydney time 2- 2 h. When two offsets straddle Greenwich, one is positive and one negative, and the subtraction handles it automatically: Sydney (UTC+10+10) to Los Angeles (UTC8-8) gives 10(8)=1810 - (-8) = 18 hours. The time line below shows the two directions from a single starting clock.

East-west time line: subtract to the west, add to the eastA horizontal time line with Sydney in the centre at nine o'clock in the morning. Moving left (west) you subtract hours, reaching Los Angeles at minus eighteen hours, which is three o'clock in the afternoon on the previous day. Moving right (east) you add hours, reaching Auckland at plus two hours, which is eleven o'clock in the morning the same day.West: subtract ← Sydney → East: addSydney UTC+109:00 amLos AngelesUTC−83:00 pmprev dayAucklandUTC+1211:00 am− 18 h (west)+ 2 h (east)

Daylight saving adjustments

In summer many places put their clocks forward one hour to make better use of evening daylight, which increases the offset by 11. Sydney's winter AEST == UTC+10+10 becomes summer AEDT == UTC+11+11; London's winter UTC+0+0 becomes summer BST == UTC+1+1. Always read each city's offset for the season in the question before you subtract. Two cities can both shift, so the gap between them may stay the same, shrink or grow - never assume it is unchanged. Note that Queensland, the Northern Territory and Western Australia do not observe daylight saving, so in summer the eastern states pull an hour ahead of them.

Longitude and time: 15°=115\degree = 1 hour

Time zones exist because the Earth spins. It turns a full 360°360\degree in 2424 hours, so in one hour it turns

360°24=15°.\frac{360\degree}{24} = 15\degree.

That is the key link: 15°15\degree of longitude corresponds to 11 hour of time, and dividing further, 1°1\degree corresponds to 44 minutes (since 60÷15=460 \div 15 = 4). To turn a longitude difference into a time difference, divide the degrees by 1515. Two places 90°90\degree of longitude apart differ by 90÷15=690 \div 15 = 6 hours. The more easterly place is ahead, exactly as before. (Real time zones bend around borders, so this gives the theoretical difference; offsets like Sydney's UTC+10+10 are close to, but rounded from, the longitude calculation.)

How exam questions ask about time zones

The wording varies, but each version points to the same add-or-subtract decision plus a date check:

  • "Given UTC is ..., find the local time in [city]" is the direct offset: local == UTC ++ offset, watching the sign.
  • "When it is [time] in [city A], what is the local time in [city B]?" means find the difference of the offsets, then add (B east) or subtract (B west).
  • "... allowing for daylight saving / in summer / in January" is a flag to use the seasonal offset (usually one hour more), not the standard one.
  • "... state the day / on what day" is telling you the answer crosses midnight - you must give the date as well as the time.
  • "The two cities are ... degrees of longitude apart" is a longitude-to-time question: divide the degrees by 1515 for the hours.
  • "How many hours ahead of / behind ..." asks only for the difference and the direction, not a clock time.

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2022 HSC-style3 marksMadrid is on Central European Time, UTC+1+1. Sydney is on AEST, UTC+10+10. A phone call is made from Sydney at 7:007{:}00 am on Wednesday. (a) Find the time difference between the two cities. (b) State the local day and time in Madrid when the call is made.
Show worked answer →

One mark for the time difference: 101=910 - 1 = 9 hours. One mark for choosing the correct direction - Madrid has the smaller offset, so it is west of Sydney and its clock is behind, meaning subtract 99 hours. One mark for the local time WITH the correct date: 7:007{:}00 am minus 99 hours goes back past midnight, so 79=27 - 9 = -2, then 2+24=22-2 + 24 = 22, that is 10:0010{:}00 pm on Tuesday (the previous day). A marker awards full marks only if the day change is stated; a bald '10:0010{:}00 pm' without 'Tuesday/previous day' typically loses the final mark, because the date is the point of the question.

2021 HSC-style4 marksTwo cities lie on the same line of latitude. City A is at longitude 20°20\degreeW and City B is at longitude 130°130\degreeE. (a) Find the difference in longitude between the two cities. (b) Using the relationship 15°=115\degree = 1 hour, find the time difference between them. (c) When it is 9:009{:}00 am in City A, find the local time in City B, stating whether it is ahead or behind and any day change.
Show worked answer →

Part (a), one mark: the cities are on opposite sides of Greenwich, so the longitudes ADD, 20°+130°=150°20\degree + 130\degree = 150\degree - a frequent error is to subtract and get 110°110\degree. Part (b), one mark: 150÷15=10150 \div 15 = 10 hours. Part (c), two marks: City B is east of City A (it is the eastern longitude), so it is ahead - add 1010 hours; 9:009{:}00 am +10+ 10 h =19:00=7:00= 19{:}00 = 7{:}00 pm the same day, ahead of City A. Markers reward an explicit 'add because B is east/ahead' statement and the correct same-day note; choosing the wrong direction caps the part at one mark.

2023 HSC-style3 marksHonolulu is on Hawaii Standard Time, UTC10-10, and does not observe daylight saving. In summer, Sydney is on AEDT, UTC+11+11. A flight departs Honolulu at 11:0011{:}00 pm on Thursday. (a) Find the time difference between Honolulu and Sydney. (b) State the local Sydney day and time at the moment of departure.
Show worked answer →

Part (a), one mark: 11(10)=2111 - (-10) = 21 hours, with Sydney ahead (keep the minus sign on Honolulu's offset). Part (b), two marks: Sydney is ahead, so add 2121 hours to Honolulu time. Write 11:0011{:}00 pm Thursday as 23:0023{:}00; then 23+21=4423 + 21 = 44. Since 4444 exceeds 2424, subtract 2424 and advance the date one day: 4424=2044 - 24 = 20, so 20:00=8:0020{:}00 = 8{:}00 pm on Friday. A marker awards the second mark for the correct add direction and the third for the correctly advanced date; stating 8:008{:}00 pm without 'Friday' loses the final mark.

Practice questions

Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.

foundation2 marksThe Coordinated Universal Time (UTC) is 14:0014{:}00. (a) Tokyo runs at an offset of UTC+9+9. Find the local time in Tokyo. (b) Buenos Aires runs at UTC3-3. Find the local time in Buenos Aires.
Show worked solution →

Part (a) - a positive offset is east, so add. A UTC offset is just how many hours to add (if positive) or subtract (if negative):

14:00+9 h=23:0014{:}00 + 9 \text{ h} = 23{:}00

so Tokyo is at 23:0023{:}00, that is 11:0011{:}00 pm the same day.

Part (b) - a negative offset is west, so subtract.

14:003 h=11:0014{:}00 - 3 \text{ h} = 11{:}00

so Buenos Aires is at 11:0011{:}00, that is 11:0011{:}00 am the same day. (Neither answer crosses midnight, so the date does not change. Always check whether subtracting takes you before 0:000{:}00 or adding takes you past 24:0024{:}00.)

foundation2 marksSydney is on Australian Eastern Standard Time, AEST == UTC+10+10, with no daylight saving in winter. Perth is on Australian Western Standard Time, AWST == UTC+8+8. When it is 1:001{:}00 pm in Sydney, what is the local time in Perth?
Show worked solution →

Find the time difference between the two cities. Subtract the offsets:

108=2 hours10 - 8 = 2 \text{ hours}

so the two cities are 22 hours apart.

Decide the direction. Perth has the smaller offset, so Perth is west of Sydney and its clock is behind - subtract:

1:00 pm2 h=11:00 am1{:}00 \text{ pm} - 2 \text{ h} = 11{:}00 \text{ am}

so it is 11:0011{:}00 am in Perth, the same day. (Sanity check: Australia's east coast is ahead of the west coast, so when Sydneysiders are at lunch, Perth has not reached lunch yet.)

core3 marksSydney is on AEST == UTC+10+10. London is on Greenwich Mean Time, GMT == UTC+0+0, in winter. A live broadcast starts at 8:008{:}00 am Sydney time. State the local time in London when the broadcast starts, and say whether it is the same day, the previous day or the next day.
Show worked solution →

Find the time difference. Subtract the offsets:

100=10 hours10 - 0 = 10 \text{ hours}

Decide the direction. London has the smaller offset, so London is west of Sydney and behind - subtract 1010 hours:

8:00 am10 h8{:}00 \text{ am} - 10 \text{ h}

Track the date carefully. Going back 88 hours from 8:008{:}00 am reaches 0:000{:}00 (midnight), the start of the same day. There are still 22 more hours to subtract, which steps into the previous day:

0:002 h=22:00=10:00 pm0{:}00 - 2 \text{ h} = 22{:}00 = 10{:}00 \text{ pm}

so in London it is 10:0010{:}00 pm on the previous day. (Subtracting past midnight is the trap here - whenever a westward subtraction goes below 0:000{:}00, add 2424 hours and step the date back one day.)

core3 marksIn summer, Sydney moves to Australian Eastern Daylight Time, AEDT == UTC+11+11. At the same time of year London is on British Summer Time, BST == UTC+1+1. It is 7:007{:}00 pm in Sydney on a Saturday in January. Find the local day and time in London.
Show worked solution →

Use the daylight-saving offsets, not the standard ones. In January Sydney is UTC+11+11 and London is UTC+1+1, so find the difference from those:

111=10 hours11 - 1 = 10 \text{ hours}

Decide the direction. London has the smaller offset, so it is west of Sydney and behind - subtract 1010 hours. Write 7:007{:}00 pm as 19:0019{:}00:

19:0010 h=9:0019{:}00 - 10 \text{ h} = 9{:}00

Check the date. The result 9:009{:}00 stays inside the same day (it did not drop below 0:000{:}00), so London is at 9:009{:}00 am on the same Saturday. The London answer is 9:009{:}00 am Saturday. (Both cities ran their clocks forward by an hour, so the 1010 hour gap happens to be unchanged here - but you must still read each city's correct seasonal offset rather than assume.)

core4 marksAdelaide is on Australian Central Standard Time, ACST == UTC+9:30+9{:}30, a half-hour zone. New York in winter is on Eastern Standard Time, EST == UTC5-5. It is 8:008{:}00 am in Adelaide. Find the local day and time in New York.
Show worked solution →

Find the time difference, keeping the half hour. Subtract the offsets, treating New York's as negative:

9:30(5)=9:30+5:00=14:309{:}30 - (-5) = 9{:}30 + 5{:}00 = 14{:}30

so the two cities are 1414 hours 3030 minutes apart.

Decide the direction. New York has the smaller offset, so it is west of Adelaide and behind - subtract 14:3014{:}30 from 8:008{:}00 am:

8:0014:308{:}00 - 14{:}30

Track the date. Subtracting 88 hours reaches 0:000{:}00, the start of the same day, with 6:306{:}30 still to subtract, which steps into the previous day:

0:006:30=24:006:30=17:30=5:30 pm0{:}00 - 6{:}30 = 24{:}00 - 6{:}30 = 17{:}30 = 5{:}30 \text{ pm}

so New York is at 5:305{:}30 pm on the previous day. (The half-hour zones - Adelaide, Darwin and the central states - are exactly where students drop marks by rounding 9:309{:}30 to 99 or 1010; carry the 3030 minutes through.)

exam4 marksTwo cities lie on the equator. City P is at longitude 30°30\degreeE and City Q is at longitude 135°135\degreeE. (a) Find the difference in longitude between them. (b) Using 15°=115\degree = 1 hour, convert this longitude difference to a time difference in hours. (c) When it is 10:0010{:}00 am in City P, find the local time in City Q, stating whether it is ahead or behind.
Show worked solution →

Part (a) - difference in longitude. Both are east of Greenwich, so subtract:

135°30°=105°135\degree - 30\degree = 105\degree

Part (b) - convert degrees to time. The Earth turns 15°15\degree of longitude every hour, so divide the longitude difference by 1515:

10515=7 hours\frac{105}{15} = 7 \text{ hours}

so the cities are 77 hours apart.

Part (c) - apply the difference. City Q is at the larger eastern longitude, so it is further east and its clock is ahead - add 77 hours:

10:00 am+7 h=17:00=5:00 pm10{:}00 \text{ am} + 7 \text{ h} = 17{:}00 = 5{:}00 \text{ pm}

so City Q is at 5:005{:}00 pm, the same day, and it is ahead of City P. (The Sun rises in the east, so the more easterly city reaches each hour first - hence "east is ahead".)

exam5 marksA sports fan in Sydney (AEST == UTC+10+10) wants to watch a match held in Los Angeles. Los Angeles is on Pacific Standard Time, PST == UTC8-8. (a) Find the time difference between Sydney and Los Angeles. (b) The match starts at 6:006{:}00 pm Friday, Los Angeles time. Find the local Sydney day and time of kick-off. (c) The fan instead records it and starts watching at 9:009{:}00 am Sunday Sydney time. What is the corresponding Los Angeles day and time?
Show worked solution →

Part (a) - time difference. Subtract the offsets, being careful with the negative:

10(8)=10+8=18 hours10 - (-8) = 10 + 8 = 18 \text{ hours}

so Sydney and Los Angeles are 1818 hours apart, with Sydney ahead (it has the larger offset).

Part (b) - Los Angeles time to Sydney time. Sydney is ahead, so add 1818 hours to the Los Angeles time. Start at 6:006{:}00 pm Friday, written as 18:0018{:}00 Friday:

18:00+18 h=36:0018{:}00 + 18 \text{ h} = 36{:}00

Since 36:0036{:}00 is past 24:0024{:}00, subtract 2424 and step the date forward one day:

36:0024:00=12:00 (Saturday)36{:}00 - 24{:}00 = 12{:}00 \text{ (Saturday)}

so kick-off is at 12:0012{:}00 noon Saturday in Sydney.

Part (c) - Sydney time back to Los Angeles time. Now go the other way: Los Angeles is behind, so subtract 1818 hours from the Sydney time. Start at 9:009{:}00 am Sunday, written as 9:009{:}00 Sunday:

9:0018 h=9:009{:}00 - 18 \text{ h} = -9{:}00

A negative result means we crossed back over midnight, so add 2424 and step the date back one day:

9:00+24:00=15:00 (Saturday)-9{:}00 + 24{:}00 = 15{:}00 \text{ (Saturday)}

so it is 3:003{:}00 pm Saturday in Los Angeles. (Both parts use the same 1818 hour gap; the only decisions are add-versus-subtract and adjusting the date whenever you pass 0:000{:}00 or 24:0024{:}00.)