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NSWMaths Standard 2Syllabus dot point

How do you choose the right metric unit and convert correctly between units of length, area, volume, mass and speed?

Use units of measurement and convert between them, including length, area, volume, capacity, mass and compound units such as speed, multiplying or dividing by the correct power of 10

A focused answer to the HSC Maths Standard 2 dot point on units and unit conversion. The SI system and prefixes, the metric conversion ladder for length, mass and capacity, squaring the factor for area and cubing it for volume, the litre link to cubic centimetres, and converting compound units like km/h to m/s, with worked Australian examples.

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What this dot point is asking

NESA wants you to work confidently in the metric (SI) system. You need to pick a sensible unit for a real quantity. You also need to convert between units of length, mass, area, volume and capacity, and the compound units of speed (units like km/h that combine two measurements), by multiplying or dividing by the correct power of 1010. The arithmetic is not the hard part. The marks are lost on two decisions: choosing whether to multiply or divide, and remembering that area and volume do not convert by the same factor as length. Get those two right and every conversion in the course becomes routine.

The answer

The metric system is built on powers of 1010. So every conversion between related units is a multiplication or a division by a power of 1010. The trick is reading the direction. Moving to a smaller unit makes the number bigger, so you multiply. Moving to a larger unit makes the number smaller, so you divide. The conversion ladder below captures this for length, mass and capacity, all of which share the same factors.

Metric conversion ladder for length, mass and capacityFour boxes left to right: kilo, the base unit, centi and milli. Stepping right one box you multiply: by 1000 from kilo to the unit, by 100 from unit to centi, by 10 from centi to milli. Stepping left you divide by the same factors.Step right: multiply. Step left: divide.kilokm, kg, kLunitm, g, Lcenticmmillimm, mg, mL× 1000÷ 1000× 100÷ 100× 10÷ 10

The SI system and its prefixes

Australia uses the SI (International System of Units) metric system, which is built on multiples of 1010. Each quantity has a base unit - the metre for length, the gram for mass, the litre for capacity - and the prefix in front of the unit names the power of 1010. The three prefixes you meet most are:

  • kilo (k\text{k}) means 10001000, so 11 km =1000= 1000 m and 11 kg =1000= 1000 g,
  • centi (c\text{c}) means one hundredth, so 11 cm =1100= \tfrac{1}{100} m, that is 100100 cm =1= 1 m,
  • milli (m\text{m}) means one thousandth, so 11 mm =11000= \tfrac{1}{1000} m, that is 10001000 mm =1= 1 m.

Because length, mass and capacity all use the same prefixes, the single ladder above does all three. Converting 5.25.2 kg to grams is the same step as converting 5.25.2 km to metres: multiply by 10001000 to get 52005200.

The direction rule

Every conversion needs you to decide multiply or divide. The reliable rule is to think about the size of the unit, not the size of the number:

  • changing to a smaller unit, the number gets bigger, so multiply, and
  • changing to a larger unit, the number gets smaller, so divide.

A metre is smaller than a kilometre, so a distance has more metres than kilometres, and 42504250 m =4250÷1000=4.25= 4250 \div 1000 = 4.25 km. A gram is smaller than a kilogram, so 2.42.4 kg =2.4×1000=2400= 2.4 \times 1000 = 2400 g. If your answer comes out the wrong way (a few metres turning into thousands of kilometres), you have multiplied where you should have divided.

Area: square the factor

This is where most marks are dropped. Area is a length multiplied by a length, so when you convert the units you convert both lengths, which squares the conversion factor. Since 11 m =100= 100 cm, a square one metre on each side is 100100 cm by 100100 cm:

1 m2=100×100=10000 cm2.1 \text{ m}^2 = 100 \times 100 = 10\,000 \text{ cm}^2.

The diagram makes this visible: the same square is described once in metres and once in centimetres, and counting the small squares gives 1000010\,000, not 100100.

Why one square metre equals ten thousand square centimetresA square one metre on each side. Each side is also one hundred centimetres, so the square is one hundred centimetres by one hundred centimetres, giving one hundred times one hundred equals ten thousand square centimetres. The length factor of one hundred is squared.For area, square the length factor1 m = 100 cm1 m = 100 cmArea = 1 m²= 100 × 100 cm²1 m² = 10 000 cm²

The same logic gives the other area factors. Since 11 km =1000= 1000 m, we get 11 km2=10002=1000000^2 = 1000^2 = 1\,000\,000 m2^2. The hectare is the area unit for land: 11 ha =10000= 10\,000 m2^2, which is exactly a square 100100 m by 100100 m. So 0.80.8 ha =0.8×10000=8000= 0.8 \times 10\,000 = 8000 m2^2, and a paddock of 4500045\,000 m2^2 is 45000÷10000=4.545\,000 \div 10\,000 = 4.5 ha.

Volume: cube the factor

Volume is a length multiplied by a length multiplied by a length, so converting the units cubes the factor. Since 11 m =100= 100 cm,

1 m3=100×100×100=1000000 cm3.1 \text{ m}^3 = 100 \times 100 \times 100 = 1\,000\,000 \text{ cm}^3.

So 0.450.45 m3=0.45×1000000=450000^3 = 0.45 \times 1\,000\,000 = 450\,000 cm3^3. The pattern across length, area and volume is the whole idea: the conversion factor is raised to the power 11 for length, 22 for area and 33 for volume.

Capacity and the litre link

Capacity measures how much a container holds, and it ties to volume through one fact you should commit to memory:

1 cm3=1 mL,1 L=1000 cm3,1 m3=1000 L.1 \text{ cm}^3 = 1 \text{ mL}, \qquad 1 \text{ L} = 1000 \text{ cm}^3, \qquad 1 \text{ m}^3 = 1000 \text{ L}.

That chain lets you turn any volume into a capacity. A volume of 25002500 cm3^3 is 25002500 mL, which is 2500÷1000=2.52500 \div 1000 = 2.5 L. A tank of 0.750.75 m3^3 holds 0.75×1000=7500.75 \times 1000 = 750 L, which is 750÷1000=0.75750 \div 1000 = 0.75 kL. Notice 11 m3=1^3 = 1 kL, so cubic metres and kilolitres carry the same number, a handy check.

Compound units: km/h to m/s

A compound unit combines two units. Speed is the one NESA examines: kilometres per hour and metres per second. To convert a speed you convert the distance unit and the time unit. Going from km/h to m/s, turn kilometres into metres (×1000\times 1000) and hours into seconds (÷3600\div 3600, since 11 hour =60×60=3600= 60 \times 60 = 3600 seconds):

1 km/h=1000 m3600 s=10003600 m/s.1 \text{ km/h} = \frac{1000 \text{ m}}{3600 \text{ s}} = \frac{1000}{3600} \text{ m/s}.

Combining the two factors, 10003600=13.6\dfrac{1000}{3600} = \dfrac{1}{3.6}, which gives the rule worth memorising: to go from km/h to m/s, divide by 3.63.6; to go back from m/s to km/h, multiply by 3.63.6. So a car at 100100 km/h is travelling 100÷3.627.78100 \div 3.6 \approx 27.78 m/s, and a runner at 1212 m/s is moving 12×3.6=43.212 \times 3.6 = 43.2 km/h.

How exam questions ask about units

The wording varies, but each version points to the same decision about factor and direction:

  • "Convert / express ... in [unit]" is the plain conversion: identify the factor, then decide multiply or divide by the size rule.
  • "... in square ... / square metres / hectares" is an area conversion, so square the factor (and remember 11 ha =10000= 10\,000 m2^2).
  • "... in cubic ... / how much does it hold / capacity in litres" is a volume or capacity conversion, so cube the factor or use the litre chain 11 m3=1000^3 = 1000 L.
  • "... in metres per second" or "... in km/h" is a speed conversion, so divide or multiply by 3.63.6.
  • "Which unit is most appropriate ..." asks you to choose a sensible unit: millimetres for a credit card's thickness, kilometres for a road trip, tonnes for a truck, hectares for a farm.
  • "Find the total ... giving your answer in [unit]" means do the arithmetic first, then convert the final total once into the requested unit, rather than converting partway.

Exam-style practice questions

Practice questions written in the style of NESA exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

2022 HSC-style2 marksA recipe for a school fete needs 1.751.75 kg of flour and 450450 g of sugar. (a) Write the mass of flour in grams. (b) Find the total mass of flour and sugar, in kilograms.
Show worked answer →

Part (a) convert kilograms to grams. Grams are smaller than kilograms, so the number gets bigger: multiply by 10001000.

1.75×1000=1750 g1.75 \times 1000 = 1750 \text{ g}

so the flour is 17501750 g. (1 mark for the correct converted mass.)

Part (b) add in the same unit, then state in kilograms. Working in grams, the total is 1750+450=22001750 + 450 = 2200 g. Converting back to kilograms divides by 10001000:

2200÷1000=2.2 kg2200 \div 1000 = 2.2 \text{ kg}

so the combined mass is 2.22.2 kg. (1 mark for the correct total in kilograms.) A common slip is to add 1.75+4501.75 + 450 without converting first; always bring both quantities to one unit before adding.

2024 HSC-style4 marksA council is laying turf on a rectangular park that measures 9090 m by 6060 m. (a) Find the area of the park in square metres. (b) The turf supplier quotes the area in hectares (11 ha =10000= 10\,000 m2^2). Convert the area to hectares. (c) Express the area in square centimetres.
Show worked answer →

Part (a) area of the rectangle. Area is length times width:

90×60=5400 m290 \times 60 = 5400 \text{ m}^2

so the park is 54005400 m2^2. (1 mark.)

Part (b) convert to hectares. One hectare is 1000010\,000 m2^2, and a hectare is larger than a square metre, so divide:

540010000=0.54 ha\frac{5400}{10\,000} = 0.54 \text{ ha}

so the park is 0.540.54 ha. (1 mark.)

Part (c) convert to square centimetres, squaring the factor. Length converts by 11 m =100= 100 cm, so area converts by the square of 100100:

1 m2=1002=10000 cm21 \text{ m}^2 = 100^2 = 10\,000 \text{ cm}^2

Square centimetres are smaller, so multiply:

5400×10000=54000000 cm25400 \times 10\,000 = 54\,000\,000 \text{ cm}^2

so the area is 5400000054\,000\,000 cm2^2. (1 mark for squaring the factor, 1 mark for the correct value.) The frequent error here is multiplying by 100100 instead of 1002100^2; for area you must square the length factor.

2023 HSC-style4 marksA rectangular concrete footing for a shed measures 33 m long, 22 m wide and 0.50.5 m deep. (a) Find the volume of concrete in cubic metres. (b) Convert this volume to cubic centimetres (11 m =100= 100 cm). (c) Concrete is ordered in litres. Given 11 m3=1000^3 = 1000 L, find the volume in litres.
Show worked answer →

Part (a) volume of the cuboid. Multiply the three dimensions:

3×2×0.5=3 m33 \times 2 \times 0.5 = 3 \text{ m}^3

so the volume is 33 m3^3. (1 mark.)

Part (b) convert to cubic centimetres, cubing the factor. Length converts by 11 m =100= 100 cm, so volume converts by the cube of 100100:

1 m3=1003=1000000 cm31 \text{ m}^3 = 100^3 = 1\,000\,000 \text{ cm}^3

Cubic centimetres are smaller, so multiply:

3×1000000=3000000 cm33 \times 1\,000\,000 = 3\,000\,000 \text{ cm}^3

so the volume is 30000003\,000\,000 cm3^3. (1 mark for cubing the factor, 1 mark for the value.)

Part (c) convert to litres. Using 11 m3=1000^3 = 1000 L, multiply:

3×1000=3000 L3 \times 1000 = 3000 \text{ L}

so 30003000 L of concrete is needed. (1 mark.) Note the cube-versus-square trap: for a volume the factor is 1003=1000000100^3 = 1\,000\,000, not 1002100^2.

Practice questions

Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.

foundation2 marksConvert the following. (a) 6.56.5 km to metres. (b) 23002300 g to kilograms.
Show worked solution →

Part (a) - kilometres are bigger than metres, so multiply. Stepping from kilo down to the base unit multiplies by 10001000:

6.5×1000=65006.5 \times 1000 = 6500

so 6.56.5 km =6500= 6500 m.

Part (b) - grams are smaller than kilograms, so divide. Stepping up from grams to kilograms divides by 10001000:

2300÷1000=2.32300 \div 1000 = 2.3

so 23002300 g =2.3= 2.3 kg. (Check the direction with a sanity test: a kilometre is a long way, so its number of metres should be larger, and a kilogram is heavy, so its number of grams should be larger.)

foundation2 marksA tiling plan gives a floor area as 4.24.2 m2^2. Convert this to square centimetres.
Show worked solution →

Square the length factor. Length converts by 11 m =100= 100 cm, so area converts by the square of 100100:

1 m2=1002 cm2=10000 cm21 \text{ m}^2 = 100^2 \text{ cm}^2 = 10\,000 \text{ cm}^2

Multiply by 1000010\,000. Therefore

4.2×10000=420004.2 \times 10\,000 = 42\,000

so 4.24.2 m2=42000^2 = 42\,000 cm2^2. (A common slip is to multiply by 100100 instead of 1000010\,000, which gives only 420420 cm2^2. For area you square the factor.)

core3 marksA garden water feature holds a volume of 0.60.6 m3^3. Find its capacity in litres. (Recall 11 cm3=1^3 = 1 mL and 11 L =1000= 1000 cm3^3.)
Show worked solution →

First convert the volume to cubic centimetres - cube the factor. Length converts by 11 m =100= 100 cm, so volume converts by the cube of 100100:

1 m3=1003 cm3=1000000 cm31 \text{ m}^3 = 100^3 \text{ cm}^3 = 1\,000\,000 \text{ cm}^3

so

0.6×1000000=600000 cm30.6 \times 1\,000\,000 = 600\,000 \text{ cm}^3

Convert cubic centimetres to millilitres. They are equal, 11 cm3=1^3 = 1 mL, so this is 600000600\,000 mL.

Convert millilitres to litres. Divide by 10001000:

600000÷1000=600600\,000 \div 1000 = 600

so the capacity is 600600 L. (Short cut worth knowing: 11 m3=1000^3 = 1000 L, so 0.60.6 m3=600^3 = 600 L directly.)

core2 marksA car is travelling at 9090 km/h. Convert this speed to metres per second, giving an exact answer.
Show worked solution →

Set up the compound-unit conversion. A speed in km/h becomes m/s by turning kilometres into metres (×1000\times 1000) and hours into seconds (÷3600\div 3600):

90 km/h=90×10003600 m/s90 \text{ km/h} = \frac{90 \times 1000}{3600} \text{ m/s}

Evaluate. The numerator is 9000090\,000, and dividing by 36003600 gives

900003600=25\frac{90\,000}{3600} = 25

so 9090 km/h =25= 25 m/s. (The quick rule is to divide by 3.63.6 to go from km/h to m/s: 90÷3.6=2590 \div 3.6 = 25.)

exam4 marksA rectangular paddock measures 15001500 m by 800800 m. (a) Find its area in square metres. (b) Convert this area to hectares (11 ha =10000= 10\,000 m2^2). (c) Convert the area to square kilometres.
Show worked solution →

Part (a) - area in square metres. Area of a rectangle is length times width:

1500×800=12000001500 \times 800 = 1\,200\,000

so the area is 12000001\,200\,000 m2^2.

Part (b) - convert to hectares. One hectare is 1000010\,000 m2^2, so divide:

120000010000=120\frac{1\,200\,000}{10\,000} = 120

so the paddock is 120120 ha.

Part (c) - convert to square kilometres. Length converts by 11 km =1000= 1000 m, so area converts by the square: 11 km2=10002=1000000^2 = 1000^2 = 1\,000\,000 m2^2. Divide:

12000001000000=1.2\frac{1\,200\,000}{1\,000\,000} = 1.2

so the area is 1.21.2 km2^2. (Cross-check: 11 km2=100^2 = 100 ha, and 120÷100=1.2120 \div 100 = 1.2 km2^2, which agrees.)

exam5 marksA rectangular rainwater tank measures 22 m long, 1.51.5 m wide and 11 m deep. (a) Find its volume in cubic metres. (b) Find its capacity in litres and in kilolitres (11 m3=1000^3 = 1000 L, 11 kL =1000= 1000 L). (c) A pump empties the full tank at 5050 litres per minute. How long, in hours, does it take to empty?
Show worked solution →

Part (a) - volume of the cuboid. Multiply the three dimensions:

2×1.5×1=32 \times 1.5 \times 1 = 3

so the volume is 33 m3^3.

Part (b) - capacity in litres and kilolitres. Using 11 m3=1000^3 = 1000 L:

3×1000=30003 \times 1000 = 3000

so the capacity is 30003000 L. Converting litres to kilolitres divides by 10001000:

3000÷1000=33000 \div 1000 = 3

so the capacity is 33 kL. (Note 33 m3^3 and 33 kL are the same amount, because 11 m3=1^3 = 1 kL.)

Part (c) - emptying time. The full tank holds 30003000 L and drains at 5050 L per minute, so the time in minutes is

300050=60 minutes\frac{3000}{50} = 60 \text{ minutes}

Converting minutes to hours divides by 6060:

60÷60=160 \div 60 = 1

so it takes 11 hour to empty the tank.

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