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Scale drawings, building plans, similarity and the trapezoidal rule: HSC Maths Standard 1 Year 12

Syllabus dot point

“Interpret and use scale drawings, including building plans and elevation views, use similarity and scale factors to find lengths, calculate areas and volumes from plans, and use the trapezoidal rule to estimate the area of irregular shapes”

HSCMaths Standard 1Year 12: Measurement8 min read

Quick answer

Use scale 1:nn by multiplying drawing lengths by nn (and dividing to go the other way), remembering building plans are in millimetres. Read floor plans and elevations to find real areas and volumes, use similar triangles to find unknown lengths, and estimate irregular areas with the trapezoidal rule A≈h2(df+dl)A \approx \frac{h}{2}(d_f + d_l) for each strip.

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  1. What this dot point is asking
  2. The answer
  3. Practice questions

What this dot point is asking

You need to read and use scale drawings (including building plans and elevations), find lengths with scale factors and similar figures, calculate areas and volumes from plans, and estimate irregular areas with the trapezoidal rule.

The answer

Scales and scale factors

A scale of 1:nn means 1 unit on the drawing represents nn units in real life.

  • Drawing to real: multiply by nn.
  • Real to drawing: divide by nn.

Building plans use millimetres as the standard unit, so convert to metres (divide by 1000) for areas in m².

Plans and elevations

  • Floor plans show rooms, walls, doors (with swing arcs) and windows from above, with dimensions and common symbols and abbreviations.
  • Elevation views show the building from each side, giving heights, roof pitch and window positions.
  • Use plans to calculate floor areas, wall areas (for painting), and volumes (for concrete slabs or rooms).

Similarity

Similar figures have equal corresponding angles and sides in the same ratio (the scale factor). Similar triangles are used to find heights and distances that cannot be measured directly (shadows, mirrors, surveying).

The trapezoidal rule

For an irregular shape with measurements dfd_f and dld_l a distance hh apart:

A≈h2(df+dl)A \approx \frac{h}{2}(d_f + d_l)

For more strips, apply the rule to each strip and add the areas. Check the formula on your reference sheet.

Area and volume from plans
  1. Convert plan measurements to real lengths.
  2. Convert to the units needed (m for m², m³).
  3. Split composite areas into rectangles and triangles, or use the trapezoidal rule for curved or irregular edges.
  4. Volume = area of cross-section × depth (for slabs, pools).
Worked example

A concrete slab on a 1:100 plan measures 120 mm by 85 mm and is 100 mm thick in reality.

  1. Real dimensions: 120×100=12 000120 \times 100 = 12\,000 mm = 12 m; 85×100=850085 \times 100 = 8500 mm = 8.5 m.
  2. Area =12×8.5=102= 12 \times 8.5 = 102 m².
  3. Volume =102×0.1=10.2= 102 \times 0.1 = 10.2 m³ of concrete.
Common traps
Forgetting millimetres on plans
A wall of 3600 means 3.6 m.
Using the wrong h in the trapezoidal rule
hh is the distance between measurements, not the total length.
Scaling areas by the scale factor
Convert lengths first, then calculate area.

Practice questions

Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.

foundation3 marks
A floor plan has a scale of 1:50. The kitchen measures 64 mm by 90 mm on the plan. Find its real dimensions and floor area.
Show worked solution →

Real length =90×50=4500= 90 \times 50 = 4500 mm = 4.5 m; real width =64×50=3200= 64 \times 50 = 3200 mm = 3.2 m.

Area =4.5×3.2=14.4= 4.5 \times 3.2 = 14.4 m².

Marking guide: 1 mark for each dimension, 1 mark for the area.

core3 marks
A 1.8 m tall person casts a 2.4 m shadow at the same time a tree casts a 14 m shadow. Use similar triangles to find the height of the tree.
Show worked solution →

The triangles are similar (sun's rays at the same angle).

h14=1.82.4\frac{h}{14} = \frac{1.8}{2.4}, so h=14×0.75=10.5h = 14 \times 0.75 = 10.5 m.

Marking guide: 1 mark for identifying similar triangles, 1 mark for the ratio, 1 mark for 10.5 m.

exam5 marks
A surveyor measures the width of an irregular block of land at 20 m intervals along a 40 m straight boundary: 18 m, 25 m and 21 m. Use two applications of the trapezoidal rule to estimate the area, then estimate the cost of turfing it at 14 dollars per square metre.
Show worked solution →

Two applications, each with h=20h = 20:

First strip: 202(18+25)=10×43=430\frac{20}{2}(18 + 25) = 10 \times 43 = 430 m².

Second strip: 202(25+21)=10×46=460\frac{20}{2}(25 + 21) = 10 \times 46 = 460 m².

Total area ≈890\approx 890 m².

Cost ≈890×$14=$12 460\approx 890 \times \$14 = \$12\,460.

Marking guide: 1 mark for hh, 1 mark per strip (2 marks), 1 mark for the total, 1 mark for the cost.

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Sources & how we know this

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