What are the real numbers, and how do we simplify surds, rationalise denominators and apply the index laws without leaving a surd in the wrong place or a slip in the arithmetic?
Work with the real number system and surds: simplify surds, add, multiply and expand surdic expressions, rationalise single- and binomial-surd denominators, and apply the index laws to expressions with integer indices
A focused answer to the Year 11 Maths Advanced number groundwork: the sets N, Z, Q and R, why a surd is irrational, simplifying surds by taking out square factors, surd arithmetic and binomial expansions, rationalising single-term and binomial-surd denominators with the conjugate, and the index laws for integer indices, with worked examples and original practice questions.
Reviewed by: AI editorial process; not yet individually human-reviewed
Have a quick question? Jump to the Q&A page
What this dot point is asking
Before you can graph, differentiate or solve a quadratic with confidence, you have to be at home with the numbers themselves. NESA expects you to know the real number system, to recognise when a root is a surd (an irrational number that cannot be written as a fraction), and to manipulate surds fluently: simplify them, add and multiply them, expand brackets that contain them, and clear them out of a denominator. You also need the index laws cold, because powers are the language the rest of the course is written in. The methods are short, but they recur in almost every later topic, so the goal is speed without slips, and understanding why each rule holds so you can rebuild it under pressure.
The answer
The real number system: N, Z, Q and R
Mathematics builds its numbers up in layers, each one larger than the last:
- Natural (counting) numbers : (and often ). The numbers you count with.
- Integers : the naturals together with zero and the negatives,
- Rational numbers : every number that can be written as a fraction of two integers (with ). Equivalently, every terminating or recurring decimal. For example and are rational.
- Real numbers : all the points on the number line. The reals that are not rational are the irrational numbers, such as , and . An irrational number has a decimal that never terminates and never recurs.
Each set sits inside the next: . The picture below places a sample number in the smallest set that contains it, so you can see at a glance where any given number lives, and that the irrationals are exactly the reals left over once you remove the fractions.
A subtle point worth keeping: the rationals are dense, meaning between any two of them there is always another, yet they still leave gaps. The number sits in one of those gaps. It is the length of the diagonal of a unit square, so it certainly names a point on the line, but no fraction equals it exactly. That is what "irrational" means, and it is why we keep such numbers in exact form (, not ) until a decimal is actually required.
What a surd is, and why is irrational
A surd is a root such as , or that is not itself a rational number. The test is whether the root comes out exactly: and are not surds because they simplify to integers, whereas is a surd because it does not. Notice that is the positive square root only: although has two square roots, and , the symbol denotes just , and we write for the negative one.
That surds really are irrational is not obvious, and a famous proof by contradiction shows it. The argument is worth seeing once because it explains why surds cannot be tidied into fractions; the worked example "Prove that is irrational" below runs it in full.
Simplifying a surd: take out the largest square factor
A surd is in simplest form when the number under the root sign has no square factor bigger than . To simplify, pull out the largest perfect square () that divides the number, using the law for non-negative and :
Always take out the largest square you can spot, or you will have to simplify twice. If you only notice , you are not finished, because still has the square factor . The two laws that do all the work are
and the squaring facts and . There is no corresponding law for a sum: is not , a trap worth fixing in your memory now.
Surd arithmetic: collecting, multiplying and expanding
Once surds are simplified, the ordinary rules of algebra apply, with , , and so on treated like the pronumerals , .
- Adding and subtracting works only for like surds (the same number under the root). Simplify first so the like surds become visible, then add the coefficients: . Unlike surds, such as , cannot be combined at all.
- Multiplying uses , then check whether the result simplifies further: .
- Expanding brackets is exactly the algebra of the previous page, with the same three special expansions. In particular , a difference of squares that turns two surds into a plain integer. For example . That single identity is the engine behind rationalising a binomial denominator.
Rationalising the denominator
It is conventional, and almost always required for full marks, to leave no surd in a denominator. Removing it is called rationalising, and there are two cases.
A single-term denominator (a surd or a multiple of one). Multiply the top and bottom by that surd. Because , the surd in the denominator becomes rational:
A two-term (binomial) denominator such as or . Multiply the top and bottom by the conjugate, which is the same expression with the middle sign reversed. The denominator then becomes a difference of squares and the surds vanish. The stepped figures below carry through the whole process.
Rationalise a binomial denominator, stage by stage
Stage 1, spot the conjugate. The denominator is . Write down its conjugate, (same terms, opposite middle sign). Multiplying these two will give , a difference of squares with no surd, so the plan is to multiply top and bottom by .
Stage 2, multiply by . Multiply the fraction by . That quotient equals , so the value of the fraction is unchanged; only its appearance changes. The numerator becomes and the denominator becomes .
Stage 3, difference of squares. Expand the denominator with . Here and , so the denominator is . The surd is gone: the denominator is now the integer .
Stage 4, cancel and finish. The numerator and the denominator share the factor . Cancel it to reach the answer , which has no surd in any denominator and so is fully rationalised.
The index laws (integer indices)
A power is repeated multiplication, and five laws let you combine powers of the same base. They are the rules you will use to differentiate, to handle exponentials, and to tidy almost any algebraic expression:
- Multiplying adds indices: .
- Dividing subtracts indices: .
- Power of a power multiplies indices: .
- Power of a product distributes: .
- Power of a quotient distributes: .
When an expression has several factors, work through it systematically: the numbers first, then each pronumeral in turn. For instance , since , and (and any non-zero base to the power is ). A common slip is to add the coefficients instead of multiplying them, or to apply a law across different bases: does not simplify, because the bases differ.
How exam questions ask about surds and indices
These skills underpin many longer questions, and a handful of command words tell you exactly which one is wanted:
- "Simplify" a surd means take out every square factor and collect like surds. State the answer in simplest surd form (no square factor left under the root, no like surds left uncombined).
- "Express in simplest exact form" or "leave your answer in surd form" is a signal not to give a decimal: keep , do not write .
- "Rationalise the denominator" means clear the surd from the bottom: multiply by the surd for a single term, or by the conjugate for a two-term denominator, then use the difference of squares.
- "Show that" a surd expression equals a given value usually means rationalise or expand until both sides match; write every line so the marker can follow the manipulation.
- "Simplify, leaving your answer with positive indices" is an index-law question: combine the powers, then make sure no negative or zero index is left in the final form.
- Pythagoras or geometry problems often produce a surd answer ( gives ); take the positive root for a length, and simplify the surd.
Practice questions
Original practice questions graded from foundation to exam level, each with a full worked solution. Try them before revealing the solution.
foundation2 marksSimplify , and hence simplify .Show worked solution →
Take out the largest square factor of . The squares up to are , and divides . So
Simplify each surd in the second expression. and .
Collect like surds. Both are multiples of , so add the coefficients:
Check numerically. , and . They agree.
foundation2 marksRationalise the denominator of .Show worked solution →
Multiply top and bottom by the surd in the denominator. To clear , multiply by , which equals and so does not change the value:
Simplify the rational coefficient. , so
Check numerically. , and . They agree.
core2 marksExpand and simplify .Show worked solution →
Expand every pair of terms. Multiply each term in the first bracket by each term in the second:
Simplify the surd product. , so .
Collect rational parts and surd parts separately. Rational: . Surd: . So
Check numerically. , and . They agree.
core3 marksSimplify , where and are non-zero, leaving your answer with positive indices.Show worked solution →
Apply the power to the bracket first. Raising a product to a power raises each factor: .
Multiply out the numerator. Multiply by : multiply the numbers () and add the indices of each letter (: ; : ):
Divide by the denominator. To divide powers of the same base, subtract indices (: ; : ):
Every index is already positive, so the simplified expression is .
exam3 marksRationalise the denominator of , expressing your answer in simplest exact form.Show worked solution →
Identify the conjugate of the denominator. The denominator is a two-term (binomial) surd. Its conjugate keeps the terms but flips the middle sign: . Multiplying a binomial surd by its conjugate gives a difference of squares, which removes the surds.
Multiply top and bottom by the conjugate.
Expand the denominator as a difference of squares. :
Cancel the common factor .
Check numerically. , and . They agree.
exam4 marksA rectangular garden bed at a community garden has length metres and width metres. Find, in simplest exact (surd) form, (a) the exact area of the bed, and (b) the exact length of its diagonal.Show worked solution →
(a) Multiply length by width for the area. Multiply the numbers and the surds separately, then simplify:
Here , and has no square factor, so is fully simplified. Numerically .
(b) Use Pythagoras' theorem for the diagonal. The diagonal of a rectangle satisfies . Square each side, remembering :
Take the positive square root (a length is positive):
Since has no square factor, is already in simplest form. Numerically .
Answers. Area ; diagonal .
Related dot points
- Use algebraic techniques to expand, factor and simplify expressions and algebraic fractions, and to solve linear and simultaneous equations
A focused answer to the Year 11 Maths Advanced groundwork: expanding brackets and the special expansions, the four factoring methods (including non-monic quadratics), simplifying and combining algebraic fractions, and solving linear, literal and simultaneous equations, with worked examples and original practice questions.
- Use interval notation and number-line graphs, solve linear and quadratic inequalities, and work with the absolute value definition to solve equations and inequalities of the form |x| < k and |x| > k
A focused Year 11 Maths Advanced answer on intervals, inequalities and absolute value: open, closed and unbounded intervals on the number line, solving linear inequalities and the one rule that reverses the sign, reading a quadratic inequality off the parabola, and absolute value as distance with the |x| < k and |x| > k templates, with worked examples and practice questions.
- Sketch a parabola by finding its intercepts by factoring, complete the square to write a quadratic in vertex form and read off the turning point and axis of symmetry, use the quadratic formula and the discriminant to find and classify the roots, and find the maximum or minimum value of a quadratic
A Year 11 Maths Advanced answer on the parabola: sketch by factoring for the intercepts, complete the square for the vertex form and turning point, use the quadratic formula and the discriminant to count and classify the roots, find the axis of symmetry, and read off the maximum or minimum value, with worked examples and practice questions.
- Sketch the graphs of power functions and contrast even and odd powers, sketch a cubic or higher polynomial that is factored into linear factors using a sign table, sketch circles centred at the origin and recognise shifted circles, and sketch the rectangular hyperbola with its asymptotes
A Year 11 Maths Advanced answer on power, polynomial and circle graphs: the shapes of even and odd powers of x, sketching a factored cubic with a sign table, circles centred at the origin, and the rectangular hyperbola and its asymptotes, with worked examples and practice questions.
- Define and use function notation, distinguish a function from the more general relation using the vertical line test, and classify relations as one-to-one, many-to-one, one-to-many or many-to-many using the horizontal line test
A Year 11 Maths Advanced answer on functions and notation: the function machine and notation, evaluating and substituting expressions into a function, the difference between a function and a relation, the vertical line test, and one-to-one, many-to-one, one-to-many and many-to-many classification via the horizontal line test, with worked examples and practice questions.